Prerequisites
Before diving into VSEPR theory, review:
- Covalent Bonding — Lewis structures and electron pairs
- Lewis Dot Structures — Drawing molecular structures
- Electronic Configuration — Understanding valence electrons
The Hook: Why Water Isn’t Linear
Imagine if water was linear (H-O-H at 180°) instead of bent (104.5°)…
- Ice wouldn’t float → oceans would freeze from bottom up → no marine life
- Water wouldn’t be such a good solvent → no biochemistry, no life
- Snowflakes wouldn’t have their beautiful hexagonal shapes
One tiny angle difference = The difference between a living planet and a dead rock!
In Interstellar (2014), they search for planets with liquid water. But it’s not just H₂O that matters — it’s the bent shape that gives water its unique properties! The reason? VSEPR Theory — Valence Shell Electron Pair Repulsion.
JEE Reality: This is a free marks topic! 2-3 guaranteed questions every year worth 8-12 marks. Master the patterns, and you’ll solve these in under 30 seconds each!
The Core Concept
What is VSEPR Theory?
VSEPR Theory predicts the 3D shapes of molecules based on one simple idea:
$$\boxed{\text{Electron pairs repel each other and arrange to minimize repulsion}}$$In simple terms: Imagine balloons tied together at a central point. The balloons naturally spread out as far as possible to minimize bumping into each other. That’s exactly what electron pairs do around an atom!
The Fundamental Principle
Electron pairs (bonding + lone pairs) around a central atom arrange themselves to be as far apart as possible to minimize repulsion.
graph TD
A[Count electron pairs
around central atom] --> B{Total electron pairs}
B -->|2 pairs| C[Linear
180°]
B -->|3 pairs| D[Trigonal Planar
120°]
B -->|4 pairs| E[Tetrahedral
109.5°]
B -->|5 pairs| F[Trigonal Bipyramidal
90°, 120°]
B -->|6 pairs| G[Octahedral
90°]
style A fill:#e1f5fe
style C fill:#fff9c4
style D fill:#f0f4c3
style E fill:#dcedc8
style F fill:#c5e1a5
style G fill:#aed581VSEPR Methodology: The 4-Step Process
Step 1: Draw Lewis Structure
Identify central atom, count valence electrons, distribute as bonds and lone pairs.
Step 2: Count Electron Pairs
Steric Number (SN) = Number of bonding pairs + Number of lone pairs
Important: Count multiple bonds as ONE bonding region (double = 1, triple = 1)
Step 3: Determine Electron Geometry
Based on total electron pairs (SN), determine how electron pairs arrange in space.
Step 4: Determine Molecular Geometry
Consider only atoms (ignore lone pairs) to determine molecular shape.
Electron geometry (includes lone pairs) determines electron arrangement
Molecular geometry (only atoms) determines molecular shape
Example: H₂O
- Electron geometry: Tetrahedral (4 electron pairs)
- Molecular geometry: Bent (only 2 H atoms visible)
JEE Trap: Questions ask for “shape” → they want molecular geometry, not electron geometry!
Repulsion Order: Who Pushes Harder?
Not all electron pairs repel equally! Lone pairs occupy more space than bonding pairs.
$$\boxed{\text{LP-LP} > \text{LP-BP} > \text{BP-BP}}$$Where:
- LP = Lone Pair
- BP = Bonding Pair
Why? Lone pairs are held by only one nucleus (the central atom), so they spread out more. Bonding pairs are held by two nuclei, so they’re more compressed.
Effect on Bond Angles
More lone pairs → Smaller bond angles
Example: CH₄ vs NH₃ vs H₂O
| Molecule | LP | BP | Bond Angle | Reason |
|---|---|---|---|---|
| CH₄ | 0 | 4 | 109.5° | Standard tetrahedral |
| NH₃ | 1 | 3 | 107° | 1 LP pushes BP’s closer |
| H₂O | 2 | 2 | 104.5° | 2 LP’s push BP’s even closer |
Memory trick: “More Lone, Less Angle!” → Each lone pair reduces angle by ~2.5°
The Complete VSEPR Guide
2 Electron Pairs (SN = 2)
Linear Geometry (180°)
Electron Geometry: Linear Molecular Geometries: 1 shape possible
Type: AX₂ (2 BP, 0 LP) — LINEAR
Example: BeCl₂, CO₂, HCN
Cl-Be-Cl or O=C=O
180° 180°
Visual Description:
- Linear: Like a straight rod
- Both atoms on opposite sides of central atom
- Bond angle = 180°
Imagine a barbell with weights on both ends. The central carbon is the bar, and the oxygen atoms are the weights on opposite ends. Perfectly straight, perfectly balanced.
Why linear? 2 electron regions want to be as far apart as possible → 180° is maximum separation!
3 Electron Pairs (SN = 3)
Electron Geometry: Trigonal Planar (120°)
Type 1: AX₃ (3 BP, 0 LP) — TRIGONAL PLANAR
Example: BF₃, BCl₃, CO₃²⁻, NO₃⁻
F
|
F—B—F
120°
Visual Description:
- Trigonal Planar: Like a Mercedes-Benz logo
- All atoms in the same plane
- Three arms at 120° angles
- Flat, symmetrical
Example: BF₃ (boron trifluoride)
- B at center, 3 F atoms around it
- All in one plane, 120° apart
- Looks like three spokes of a wheel
Type 2: AX₂E (2 BP, 1 LP) — BENT/V-SHAPED
Example: SO₂, O₃, NO₂⁻
O
//
S
\
O
~120° (actually ~119°)
Visual Description:
- Bent: Like a boomerang
- Two atoms bonded, one lone pair (invisible)
- Lone pair pushes atoms closer
- Bond angle < 120° (usually ~119° for SO₂)
CO₂ (linear) vs SO₂ (bent) — Why different?
CO₂: C has 4 valence e⁻, forms 2 double bonds → 2 bonding regions, 0 LP → linear
SO₂: S has 6 valence e⁻, forms 2 double bonds → 2 bonding regions, 1 LP → bent
JEE Trick: Even though both have O=X=O formula, count lone pairs!
4 Electron Pairs (SN = 4)
Electron Geometry: Tetrahedral (109.5°)
Type 1: AX₄ (4 BP, 0 LP) — TETRAHEDRAL
Example: CH₄, CCl₄, NH₄⁺, SO₄²⁻
H
|
H—C—H
|
H
109.5°
Visual Description:
- Tetrahedral: Like a triangular pyramid
- 4 atoms arranged at corners of a tetrahedron
- Central atom at the center
- All bond angles = 109.5°
- 3D structure (NOT flat!)
Imagine: A tripod with one leg pointing up and three pointing down (but more symmetrical). Or a soccer ball’s stitching at a vertex.
Type 2: AX₃E (3 BP, 1 LP) — TRIGONAL PYRAMIDAL
Example: NH₃, PCl₃, H₃O⁺
N
/|\
H H H
~107°
Visual Description:
- Trigonal Pyramidal: Like a tripod or a stool
- 3 atoms form a triangular base
- Central atom above the base (not in the plane!)
- Lone pair at the top (invisible)
- Bond angle ≈ 107° (less than 109.5° due to LP repulsion)
Imagine: A three-legged camera tripod. The camera (central atom) sits above the three legs (bonded atoms). There’s an invisible fourth leg (lone pair) pointing up.
Type 3: AX₂E₂ (2 BP, 2 LP) — BENT/V-SHAPED
Example: H₂O, H₂S, SCl₂
O: (2 lone pairs)
/ \
H H
104.5°
Visual Description:
- Bent: Like a boomerang or an open book
- 2 atoms bonded at an angle
- 2 lone pairs (invisible) push from opposite sides
- Bond angle ≈ 104.5° (H₂O), smaller than 109.5°
Imagine: Take a tetrahedral structure, remove two opposite corners (atoms), replace with lone pairs. The remaining two atoms form a bent shape.
Two types of bent shapes — DON’T confuse!
Bent from 3 electron pairs (AX₂E):
- Example: SO₂
- Electron geometry: Trigonal planar
- Bond angle ≈ 119-120°
Bent from 4 electron pairs (AX₂E₂):
- Example: H₂O
- Electron geometry: Tetrahedral
- Bond angle ≈ 104-105°
JEE Trap: Both are “bent,” but different angles! Always count total electron pairs first!
5 Electron Pairs (SN = 5)
Electron Geometry: Trigonal Bipyramidal (90° and 120°)
Key Feature: TWO types of positions:
- Axial: 2 positions above and below (90° to equatorial)
- Equatorial: 3 positions in the middle plane (120° to each other)
Important: Lone pairs ALWAYS occupy equatorial positions first (less repulsion!)
Type 1: AX₅ (5 BP, 0 LP) — TRIGONAL BIPYRAMIDAL
Example: PCl₅, PF₅
Cl (axial)
|
Cl—P—Cl (equatorial, 120° apart)
|
Cl (axial)
Visual Description:
- Trigonal Bipyramidal: Like two triangular pyramids joined at the base
- 3 atoms in the middle (equatorial) at 120°
- 2 atoms above and below (axial) at 90° to equatorial
- NOT all bond angles equal!
Imagine: A bow tie or two Egyptian pyramids stuck together base-to-base.
Type 2: AX₄E (4 BP, 1 LP) — SEE-SAW/DISTORTED TETRAHEDRAL
Example: SF₄, XeO₂F₂
F (axial)
|
F—S—F (equatorial)
|
F (axial)
(LP at equatorial)
Visual Description:
- See-Saw: Like a playground see-saw or teeter-totter
- Lone pair occupies one equatorial position
- 2 axial atoms (above/below)
- 2 equatorial atoms (one position empty due to LP)
- Asymmetrical, distorted
Bond angles: ~90° (axial-equatorial), ~120° (equatorial-equatorial), but distorted by LP
Imagine: A see-saw at a playground — two kids on the ends (axial), one kid on one side (equatorial), empty seat on other side (lone pair).
Type 3: AX₃E₂ (3 BP, 2 LP) — T-SHAPED
Example: ClF₃, BrF₃
F
|
F—Cl—F
(2 LP at equatorial)
Visual Description:
- T-Shaped: Like the letter “T”
- 2 lone pairs occupy equatorial positions
- 2 atoms at axial positions (up and down)
- 1 atom at remaining equatorial position
- Forms a T
Bond angles: ~90° (axial to equatorial), slightly less than 90° due to LP repulsion
Imagine: A capital letter T. The vertical part has atoms at top and bottom (axial), the horizontal part has one atom extending to the side (equatorial).
Type 4: AX₂E₃ (2 BP, 3 LP) — LINEAR
Example: XeF₂, I₃⁻
F—Xe—F
(3 LP at equatorial)
Visual Description:
- Linear: Straight line (like AX₂)
- 3 lone pairs occupy ALL equatorial positions
- 2 atoms at axial positions (least repulsion)
- Bond angle = 180°
Imagine: A barbell again, but with invisible balloons (lone pairs) in the middle plane pushing the atoms to opposite sides.
“Lone pairs love the equator!” — They always go to equatorial positions first.
Why? Equatorial positions have 2 neighbors at 90° (axial positions have 3 neighbors at 90°). Lone pairs need more space, so they choose the less crowded equatorial spots!
Patterns:
- 0 LP: Trigonal bipyramidal (all atoms)
- 1 LP: See-saw (LP at equatorial)
- 2 LP: T-shaped (both LP at equatorial)
- 3 LP: Linear (all LP at equatorial, atoms at axial)
6 Electron Pairs (SN = 6)
Electron Geometry: Octahedral (90°)
Key Feature: All 6 positions are equivalent (unlike TBP)
Type 1: AX₆ (6 BP, 0 LP) — OCTAHEDRAL
Example: SF₆, PF₆⁻, [Fe(CN)₆]³⁻
F
|
F—S—F
|
F
(+ 1 F front, 1 F back)
Visual Description:
- Octahedral: Like two square pyramids joined at the base
- 6 atoms at corners of an octahedron
- All bond angles = 90°
- Highly symmetrical
Imagine: A die (6-sided cube) with atoms at each face’s center. Or two Egyptian pyramids (square base) stuck together.
Type 2: AX₅E (5 BP, 1 LP) — SQUARE PYRAMIDAL
Example: BrF₅, IF₅, [NiCN₅]³⁻
F
|
F—Br—F
| |
F—F
(LP opposite to apex)
Visual Description:
- Square Pyramidal: Like the Egyptian pyramids
- 4 atoms form a square base
- 1 atom at the apex (top)
- Lone pair at the bottom (opposite to apex)
Bond angles: ~90° (mostly), slightly distorted by LP
Imagine: The Great Pyramid of Giza — square base, apex at top, lone pair hidden underground.
Type 3: AX₄E₂ (4 BP, 2 LP) — SQUARE PLANAR
Example: XeF₄, ICl₄⁻, [PtCl₄]²⁻
F
|
F—Xe—F
|
F
(2 LP above and below plane)
Visual Description:
- Square Planar: Like a flat square
- 4 atoms at corners of a square
- 2 lone pairs above and below the plane
- All atoms in one plane
- Bond angles = 90°
Imagine: A perfectly flat piece of paper with atoms at the four corners. Lone pairs are ghosts floating above and below the paper.
Summary Table: All VSEPR Shapes
| SN | Formula | BP | LP | Electron Geometry | Molecular Geometry | Bond Angle | Example |
|---|---|---|---|---|---|---|---|
| 2 | AX₂ | 2 | 0 | Linear | Linear | 180° | CO₂, BeCl₂ |
| 3 | AX₃ | 3 | 0 | Trigonal planar | Trigonal planar | 120° | BF₃, CO₃²⁻ |
| 3 | AX₂E | 2 | 1 | Trigonal planar | Bent | ~120° | SO₂, NO₂⁻ |
| 4 | AX₄ | 4 | 0 | Tetrahedral | Tetrahedral | 109.5° | CH₄, NH₄⁺ |
| 4 | AX₃E | 3 | 1 | Tetrahedral | Trigonal pyramidal | ~107° | NH₃, PCl₃ |
| 4 | AX₂E₂ | 2 | 2 | Tetrahedral | Bent | ~104.5° | H₂O, H₂S |
| 5 | AX₅ | 5 | 0 | TBP | Trigonal bipyramidal | 90°, 120° | PCl₅ |
| 5 | AX₄E | 4 | 1 | TBP | See-saw | <90°, <120° | SF₄ |
| 5 | AX₃E₂ | 3 | 2 | TBP | T-shaped | ~90° | ClF₃ |
| 5 | AX₂E₃ | 2 | 3 | TBP | Linear | 180° | XeF₂, I₃⁻ |
| 6 | AX₆ | 6 | 0 | Octahedral | Octahedral | 90° | SF₆ |
| 6 | AX₅E | 5 | 1 | Octahedral | Square pyramidal | ~90° | BrF₅ |
| 6 | AX₄E₂ | 4 | 2 | Octahedral | Square planar | 90° | XeF₄ |
Interactive Demo: Explore VSEPR Molecular Geometries
Use this interactive 3D visualization to explore all VSEPR geometries. Select preset molecules like CH4, NH3, H2O, or customize electron pair counts. Drag to rotate the model and observe how lone pairs affect bond angles. Watch the difference between electron geometry and molecular geometry in real-time!
- Select a Preset: Choose from common molecules like CH4, NH3, H2O, SF6, XeF4, etc.
- Custom Mode: Use sliders to set total electron pairs (2-6) and lone pairs
- Rotate: Drag on the molecule to rotate it in 3D space
- Observe: Watch how lone pairs (purple clouds) push bonding pairs closer together
- Compare: Notice the difference between electron geometry and molecular geometry!
Key Insight: The visualization shows LP-LP > LP-BP > BP-BP repulsion - lone pairs compress bond angles!
Memory Tricks & Patterns
The Lone Pair Effect
“Each lonely pair steals 2.5° from the party!”
For tetrahedral base (109.5°):
- 0 LP: CH₄ = 109.5°
- 1 LP: NH₃ = 107° (−2.5°)
- 2 LP: H₂O = 104.5° (−5°)
Shape Family Tree
2 EP: Linear only
3 EP: Planar (flat) shapes only
4 EP: 3D shapes start
5 EP: Complex shapes, LP prefer equatorial
6 EP: 3D symmetrical shapes
Visual Mnemonics
BeCl₂: Becomes Linear (180°) BF₃: Boron Forms Trigonal planar (120°) CH₄: Carbon Has Tetrahedral (109.5°) NH₃: Nitrogen’s Pyramid (107°) H₂O: Highly Bent (104.5°) PCl₅: Phosphor BP shape (Bipyramidal) SF₆: Sulfur Octahedral (6 faces)
Special Cases and Exceptions
Multiple Bonds Count as ONE Region
Double and triple bonds count as ONE electron region for VSEPR!
Example: CO₂
- Lewis structure: O=C=O
- You might think “4 bonds = 4 regions”
- WRONG! Each C=O is one bonding region
- Total: 2 regions → Linear
Example: HCN
- Lewis structure: H-C≡N
- H-C is 1 region, C≡N is 1 region
- Total: 2 regions → Linear
Expanded Octets (Period 3 and Beyond)
Elements in Period 3 and higher can accommodate more than 8 electrons using vacant d-orbitals.
Examples:
- PCl₅: P has 10 electrons (5 bonds)
- SF₆: S has 12 electrons (6 bonds)
- IF₇: I has 14 electrons (7 bonds)
Why? They have accessible 3d, 4d, 5d orbitals for electron accommodation.
Resonance Doesn’t Change Shape
Example: CO₃²⁻
- Has 3 resonance structures (double bond rotates)
- But VSEPR shape remains trigonal planar
- Why? Average bond order doesn’t change electron regions
Common Mistakes to Avoid
Mistake: Saying H₂O is “tetrahedral”
Correct:
- H₂O has tetrahedral electron geometry (4 electron pairs)
- But bent molecular geometry (only 2 H atoms visible)
JEE questions ask for “shape of molecule” → Answer = Bent, not tetrahedral!
Rule: Unless specifically asked for “electron geometry,” always give molecular geometry!
Mistake: Counting C=O double bond as 2 bonding regions
Correct: C=O is ONE bonding region (even though it has 2 bonds)
Example: CO₂
- Wrong count: 4 bonds → 4 regions → tetrahedral
- Correct count: 2 bonding regions (each C=O) → Linear ✓
Mistake: Drawing Lewis structure but not identifying lone pairs on central atom
Example: SO₂
- S has 6 valence electrons
- Forms 2 double bonds (uses 4 electrons)
- Remaining 2 electrons = 1 lone pair ← Don’t forget this!
- Result: 2 BP + 1 LP → Bent, not linear
JEE Tip: After drawing Lewis structure, ALWAYS count lone pairs on central atom!
Practice Problems
Level 1: Foundation (NCERT Style)
Question: Predict the shape of the following molecules: (a) BeCl₂ (b) BF₃ (c) CH₄
Solution:
(a) BeCl₂:
- Be has 2 valence electrons
- Forms 2 bonds with Cl
- SN = 2 (2 BP, 0 LP)
- Shape: Linear (180°)
(b) BF₃:
- B has 3 valence electrons
- Forms 3 bonds with F
- SN = 3 (3 BP, 0 LP)
- Shape: Trigonal planar (120°)
(c) CH₄:
- C has 4 valence electrons
- Forms 4 bonds with H
- SN = 4 (4 BP, 0 LP)
- Shape: Tetrahedral (109.5°)
Question: Why is H₂O bent and not linear?
Solution:
Lewis structure of H₂O:
- O has 6 valence electrons
- Forms 2 bonds with H (uses 2 electrons)
- Remaining 4 electrons = 2 lone pairs
VSEPR Analysis:
- Total electron pairs = 2 BP + 2 LP = 4
- Electron geometry: Tetrahedral
- Molecular geometry: Bent (only 2 H atoms)
- Bond angle ≈ 104.5° (less than 109.5° due to LP-LP repulsion)
Answer: H₂O is bent because oxygen has 2 lone pairs that repel the bonding pairs, creating a bent shape instead of linear.
Level 2: JEE Main Type
Question: Arrange the following in order of increasing bond angle: H₂O, NH₃, CH₄, BF₃
Solution:
Step 1: Identify shapes and electron pairs
- H₂O: 2 BP, 2 LP → Bent (tetrahedral base) → ~104.5°
- NH₃: 3 BP, 1 LP → Trigonal pyramidal → ~107°
- CH₄: 4 BP, 0 LP → Tetrahedral → 109.5°
- BF₃: 3 BP, 0 LP → Trigonal planar → 120°
Step 2: Order by bond angle
H₂O (104.5°) < NH₃ (107°) < CH₄ (109.5°) < BF₃ (120°)
Answer: H₂O < NH₃ < CH₄ < BF₃
JEE Tip: More lone pairs → smaller bond angle (for same electron geometry)
Question: Which of the following has a square planar shape? (A) CCl₄ (B) XeF₄ (C) NH₄⁺ (D) SF₄
Solution:
(A) CCl₄:
- C has 4 valence e⁻, 4 Cl atoms
- SN = 4 (4 BP, 0 LP) → Tetrahedral ✗
(B) XeF₄:
- Xe has 8 valence e⁻, 4 F atoms
- 4 bonds use 4 electrons, remaining 4 = 2 LP
- SN = 6 (4 BP, 2 LP) → Square planar ✓
(C) NH₄⁺:
- N has 5 valence e⁻, but +1 charge → 4 electrons
- 4 bonds, 0 LP
- SN = 4 (4 BP, 0 LP) → Tetrahedral ✗
(D) SF₄:
- S has 6 valence e⁻, 4 F atoms
- 4 bonds, 1 LP
- SN = 5 (4 BP, 1 LP) → See-saw ✗
Answer: (B) XeF₄
Level 3: JEE Advanced Type
Question: Among NH₃, NH₄⁺, and NH₂⁻, which has: (a) The largest bond angle? (b) The smallest bond angle? Explain with reasoning.
Solution:
NH₃ (Ammonia):
- N has 5 valence e⁻, 3 H atoms
- 3 BP, 1 LP
- Shape: Trigonal pyramidal
- Bond angle ≈ 107°
NH₄⁺ (Ammonium ion):
- N has 5 valence e⁻, +1 charge → 4 electrons available for bonding
- 4 BP, 0 LP
- Shape: Tetrahedral
- Bond angle = 109.5°
NH₂⁻ (Amide ion):
- N has 5 valence e⁻, −1 charge → 6 electrons total
- 2 H atoms → 2 BP, 2 LP
- Shape: Bent
- Bond angle ≈ 104.5°
Answers: (a) Largest bond angle: NH₄⁺ (109.5°) — no lone pairs! (b) Smallest bond angle: NH₂⁻ (104.5°) — 2 lone pairs compress the most!
Pattern: As LP increases, bond angle decreases
- 0 LP: 109.5°
- 1 LP: ~107°
- 2 LP: ~104.5°
Question: Predict the shape of ClF₃ and explain why all bond angles are NOT equal.
Solution:
Step 1: Lewis structure
- Cl has 7 valence e⁻, 3 F atoms
- 3 bonds use 3 electrons, remaining 4 = 2 LP
- Total: 3 BP + 2 LP = 5 electron pairs
Step 2: Electron geometry
- 5 electron pairs → Trigonal bipyramidal
Step 3: Place lone pairs
- Lone pairs prefer equatorial positions (less repulsion)
- 2 LP occupy 2 equatorial spots
- 3 F atoms: 2 at axial, 1 at remaining equatorial
Step 4: Molecular shape
- T-shaped (3 atoms, 2 LP)
Step 5: Bond angles
- Axial F—Cl—Equatorial F: ~90° (but slightly less due to LP repulsion)
- Axial F—Cl—Axial F: ~180° (slightly less)
Why not equal? The 2 lone pairs at equatorial positions repel the bonding pairs unevenly:
- LP-BP repulsion > BP-BP repulsion
- Axial bonds are pushed slightly toward each other
- Equatorial bond is pushed away from LP’s
Answer: ClF₃ is T-shaped with bond angles ≈ 87-88° (F-Cl-F, axial to equatorial) and ~175° (axial to axial), not exactly 90° and 180° due to lone pair repulsions.
Quick Revision Box
| Total EP | 0 LP | 1 LP | 2 LP | 3 LP |
|---|---|---|---|---|
| 2 | Linear (180°) | — | — | — |
| 3 | Trig. planar (120°) | Bent (~120°) | — | — |
| 4 | Tetrahedral (109.5°) | Trig. pyramidal (~107°) | Bent (~104.5°) | — |
| 5 | TBP (90°, 120°) | See-saw | T-shaped (~90°) | Linear (180°) |
| 6 | Octahedral (90°) | Sq. pyramidal | Sq. planar (90°) | — |
Most Tested Molecules in JEE
| Molecule | Shape | Bond Angle | Key Feature |
|---|---|---|---|
| CO₂ | Linear | 180° | Double bonds count as 1 region |
| H₂O | Bent | 104.5° | 2 LP compress angle |
| NH₃ | Trig. pyramidal | 107° | 1 LP reduces angle |
| CH₄ | Tetrahedral | 109.5° | Perfect tetrahedral |
| PCl₅ | Trig. bipyramidal | 90°, 120° | 2 different angles |
| SF₆ | Octahedral | 90° | All positions equivalent |
| XeF₂ | Linear | 180° | 3 LP at equatorial |
| XeF₄ | Square planar | 90° | 2 LP above/below plane |
Real-World Applications
1. Drug Design: Drugs fit into enzyme active sites like a key in a lock. The shape of the molecule determines if it fits!
- Example: Inhibitor drugs are designed to be exact shapes to block enzyme activity
2. Smell and Taste: Your nose and tongue detect molecules based on shape, not just composition!
- Limonene (lemon scent) vs Carvone (mint scent) — same formula, different shapes!
3. DNA Structure: The double helix exists because of the bent shape of water that stabilizes it through hydrogen bonding. Linear water → No DNA → No life!
4. Ozone Layer: O₃ is bent (not linear like O₂), which makes it absorb UV radiation differently. The bent shape is crucial for protecting Earth from harmful UV!
5. Catalysts: Transition metal complexes have specific shapes (octahedral, square planar) that determine their catalytic activity. Wrong shape → No catalysis!
Teacher’s Summary
1. VSEPR = Electron pairs minimize repulsion
- Count total electron pairs (bonding + lone)
- Arrange to maximize separation
- Simple concept, powerful predictions!
2. Electron geometry ≠ Molecular geometry
- Electron geometry: includes lone pairs
- Molecular geometry: only atoms (what you “see”)
- JEE asks for molecular geometry!
3. Repulsion order determines angles
- LP-LP > LP-BP > BP-BP
- More lone pairs → Smaller bond angles
- Each LP reduces angle by ~2.5° (tetrahedral base)
4. Multiple bonds = ONE bonding region
- C=O, C≡N count as 1 region each
- Don’t count individual bonds in multiple bonds!
5. For 5 EP: Lone pairs love equatorial
- Equatorial positions have less repulsion
- Fill equatorial first with LP’s
- Determines see-saw, T-shaped, linear shapes
6. Patterns for quick solving:
- 2 EP → Linear (only 1 option)
- 3 EP → Planar/Bent (2 options)
- 4 EP → Tetrahedral/Pyramidal/Bent (3 options)
- 5 EP → TBP/See-saw/T/Linear (4 options!)
- 6 EP → Octahedral/Sq.Pyramidal/Sq.Planar (3 options)
7. JEE Strategy:
- Draw Lewis structure (10 sec)
- Count BP and LP (5 sec)
- Look up table/remember pattern (5 sec)
- Total: 20 seconds per question!
“Lone pairs are like invisible bullies — they take up more space and push everyone else closer together!”
Related Topics
Within Chemical Bonding
- Covalent Bonding - Lewis structures, sigma and pi bonds
- Hybridization - Why these shapes exist (VBT explanation)
- Molecular Orbital Theory - Advanced bonding perspective
- Ionic Bonding - Comparison with ionic structures
- Hydrogen Bonding - Shape and polarity effects
Atomic Structure Foundation
- Orbital Shapes - s, p, d orbital geometry
- Electronic Configuration - Valence electrons
Organic Chemistry Applications
- Organic Principles - Hybridization - Carbon geometry in organic molecules
- Reaction Intermediates - Carbocation (sp2) and carbanion shapes
- Aldehydes and Ketones - Carbonyl geometry
Coordination Chemistry
- Coordination Compounds - Complex ion geometry
- Crystal Field Theory - d-orbital splitting
Inorganic Applications
- p-Block Elements - Oxoacid structures
- Group 15 - NH3, PCl5 shapes
- Group 16 - H2O, H2S shapes
Physics Connection
- Electrostatics - Charge repulsion basics
- Electric Dipole - Molecular polarity
Mathematics
- Vector Algebra - Dipole moment vector addition