Lanthanoids: The 4f Series

Master lanthanoid contraction, electronic configuration, properties, oxidation states, and trends of lanthanoid elements for JEE Chemistry.

Introduction

Lanthanoids (also called lanthanides or rare earth elements) are the 14 elements in the 4f series - from Cerium (Ce) to Lutetium (Lu). Despite their name, they’re not actually rare; they’re called “rare” because they’re difficult to separate from each other!

Rare Earths in Your Phone
In The Billion Dollar Code (2024), tech companies fight over rare earth element patents. Your smartphone contains up to 16 different lanthanoid elements! From the vibrant OLED display (using europium and terbium) to the powerful magnets in speakers (neodymium), lanthanoids are everywhere in modern technology. China controls 90% of global production - that’s why they’re geopolitically crucial!

Position in Periodic Table

Lanthanoid Series:

  • Elements: Ce (58) to Lu (71) - 14 elements
  • Also includes: Lanthanum (La, 57) - often grouped with them
  • Collective name: Lanthanoids or Rare Earth Elements
  • Period: 6th period
  • Block: f-block (4f orbitals being filled)
graph TD
    A[f-Block Elements] --> B[Lanthanoids]
    A --> C[Actinoids]
    B --> B1[4f series: Ce to Lu]
    B --> B2[58 to 71]
    C --> C1[5f series: Th to Lr]
    C --> C2[90 to 103]

In Periodic Table:

  • Placed below the main table
  • Interrupt the 5d series
  • La → 4f fills → Lu → 5d continues (Hf)

Interactive Demo: Visualize Lanthanoid Position

Explore the position of lanthanoids in the periodic table and understand the 4f series placement.


Electronic Configuration

General Configuration

$$\boxed{[Xe] \, 4f^{1-14} \, 5d^{0-1} \, 6s^2}$$

Complete Electronic Configurations:

ElementZSymbolElectronic Configurationf-electrons
Lanthanum57La[Xe]5d¹6s²0
Cerium58Ce[Xe]4f¹5d¹6s²1
Praseodymium59Pr[Xe]4f³6s²3
Neodymium60Nd[Xe]4f⁴6s²4
Promethium61Pm[Xe]4f⁵6s²5
Samarium62Sm[Xe]4f⁶6s²6
Europium63Eu[Xe]4f⁷6s²7
Gadolinium64Gd[Xe]4f⁷5d¹6s²7
Terbium65Tb[Xe]4f⁹6s²9
Dysprosium66Dy[Xe]4f¹⁰6s²10
Holmium67Ho[Xe]4f¹¹6s²11
Erbium68Er[Xe]4f¹²6s²12
Thulium69Tm[Xe]4f¹³6s²13
Ytterbium70Yb[Xe]4f¹⁴6s²14
Lutetium71Lu[Xe]4f¹⁴5d¹6s²14

Anomalous Configurations:

ElementExpectedActualReason
Ce[Xe]4f²6s²[Xe]4f¹5d¹6s²4f and 5d similar energy
Gd[Xe]4f⁸6s²[Xe]4f⁷5d¹6s²Half-filled 4f stability
Lu[Xe]4f¹⁴6s²[Xe]4f¹⁴5d¹6s²Fully-filled 4f stability
JEE Alert

Lanthanoids have POOR shielding because:

  1. 4f orbitals are deeply buried inside the atom
  2. 4f electrons are closer to nucleus than 5s, 5p electrons
  3. Diffused shape of f-orbitals provides ineffective shielding

This poor shielding causes lanthanoid contraction!


Lanthanoid Contraction

The most important concept in lanthanoid chemistry!

Definition

Lanthanoid contraction is the steady decrease in atomic and ionic radii of lanthanoid elements from La to Lu.

$$\boxed{\text{Atomic/Ionic size: } La > Ce > Pr > Nd > ... > Yb > Lu}$$

Radii Data

Ln³⁺ Ionic Radii (in pm):

IonRadius (pm)IonRadius (pm)
La³⁺106Gd³⁺94
Ce³⁺103Tb³⁺92
Pr³⁺101Dy³⁺91
Nd³⁺99Ho³⁺89
Pm³⁺98Er³⁺88
Sm³⁺96Tm³⁺87
Eu³⁺95Yb³⁺86
Lu³⁺85

Total decrease: La³⁺ (106 pm) to Lu³⁺ (85 pm) = 21 pm

Cause of Lanthanoid Contraction

graph TD
    A[Adding electrons to 4f orbitals] --> B[Poor shielding by 4f electrons]
    B --> C[Nuclear charge increases]
    C --> D[Outer electrons pulled closer]
    D --> E[Atomic radius decreases]
    E --> F[Lanthanoid Contraction]

    style F fill:#e74c3c

Detailed Explanation:

  1. Across the series: Each element has one more proton (nuclear charge +1)
  2. Extra electron goes into: 4f orbital
  3. 4f electrons provide: Very poor shielding (diffused orbitals)
  4. Result: Effective nuclear charge increases
  5. Consequence: Outer electrons pulled closer → radius decreases

Why poor shielding?

  • 4f orbitals have complex shape
  • 4f electrons are buried deep inside
  • Less effective at screening nuclear charge

Consequences of Lanthanoid Contraction

1. Similar Chemical Properties

All lanthanoids behave very similarly:

  • Same oxidation state (+3 predominant)
  • Similar ionic radii
  • Difficult to separate from each other

2. Difficult Separation

Lanthanoids are hard to separate because:

  • Very similar ionic radii
  • Similar chemical behavior
  • Require ion-exchange chromatography or fractional crystallization

3. Effect on Post-Lanthanoid Elements

Most Important Consequence:

The 4d and 5d series elements have similar atomic radii!

ElementSeriesAtomic Radius
Zr4d160 pm
Hf5d159 pm
Nb4d146 pm
Ta5d146 pm
Mo4d139 pm
W5d139 pm

Why?

  • Hf comes after lanthanoids
  • Lanthanoid contraction compensates for expected size increase
  • Hf and Zr have almost identical radii despite being in different periods!

Result:

  • Zr and Hf are very similar chemically
  • Nb and Ta are almost identical twins
  • Very difficult to separate (e.g., Zr from Hf)

4. Variation in Basic Strength of Hydroxides

$$\boxed{\text{Basic strength: } La(OH)_3 > Ce(OH)_3 > ... > Lu(OH)_3}$$

Reason:

  • Smaller cation → higher charge density
  • Stronger M-O bond → less ionization
  • Less OH⁻ released → weaker base

5. Trends in Properties

Due to lanthanoid contraction:

  • Density increases: La to Lu
  • Melting point increases: Generally (irregular)
  • Hardness increases: La to Lu
  • Ionic character decreases: Of M-X bonds
Common JEE Mistake

Question: Why do Zr and Hf have similar radii?

Wrong answer: Because they’re in the same group.

Correct answer: Due to lanthanoid contraction! The 4f series fills between Zr and Hf, causing Hf’s radius to contract to match Zr’s size.

This is one of the MOST asked conceptual questions in JEE!


General Characteristics

1. Physical Properties

Appearance:

  • Silvery-white metals
  • Soft (can be cut with knife)
  • High luster when freshly cut
  • Tarnish rapidly in air

Metallic Properties:

  • Good electrical conductivity
  • Moderate thermal conductivity
  • High melting points (except Eu, Yb)
  • High density

2. Chemical Properties

Reactivity:

  • Quite reactive (similar to Ca)
  • Readily form oxides in air: 4M + 3O₂ → 2M₂O₃
  • React with water (slowly): 2M + 6H₂O → 2M(OH)₃ + 3H₂
  • React with halogens: 2M + 3X₂ → 2MX₃
  • React with acids: 2M + 6HCl → 2MCl₃ + 3H₂

Reducing Nature:

  • Good reducing agents (especially Eu, Yb)
  • Standard reduction potential: E° ≈ -2.3 V

3. Oxidation States

Most Common: +3

The +3 oxidation state is most stable for all lanthanoids.

$$\boxed{\text{Stable state: } Ln^{3+} \text{ (configuration: [Xe]4f}^{0-14}\text{)}}$$

Other Oxidation States (Less Common):

ElementCommon OSOther OSReason for Other OS
Ce+3, +4Ce⁴⁺ is [Xe] = stable noble gas
Pr+3+4Can achieve f⁰
Nd+3+2, +4
Sm+3+2Sm²⁺ is f⁶
Eu+2, +3Eu²⁺ is f⁷ (half-filled)
Gd+3Gd³⁺ is f⁷ (most stable)
Tb+3+4Tb⁴⁺ is f⁷
Dy+3+2, +4
Tm+3+2Tm²⁺ is f¹³
Yb+2, +3Yb²⁺ is f¹⁴ (fully-filled)

Stability of +2 and +4:

  1. +4 state (Ce⁴⁺):

    • Ce⁴⁺ = [Xe] (noble gas configuration)
    • Very stable, used as oxidizing agent
  2. +2 states (Eu²⁺, Yb²⁺):

    • Eu²⁺ = [Xe]4f⁷ (half-filled)
    • Yb²⁺ = [Xe]4f¹⁴ (fully-filled)
    • Both stable
Memory Trick

“CEEBY” for variable oxidation states:

  • Ce - +4 (noble gas)
  • Eu - +2 (half-filled f⁷)
  • Yb - +2 (fully-filled f¹⁴)

All others predominantly show +3!

4. Magnetic Properties

All lanthanoid ions (except La³⁺ and Lu³⁺) are paramagnetic due to unpaired f-electrons.

Magnetic Moment:

Not strictly spin-only! Must consider orbital contribution:

$$\mu_{eff} = g\sqrt{J(J+1)} \text{ BM}$$

where J = total angular momentum quantum number

Paramagnetism:

Ion4f electronsUnpaired e⁻Magnetic?
La³⁺f⁰0Diamagnetic
Ce³⁺1Paramagnetic
Gd³⁺f⁷7Most paramagnetic
Yb³⁺f¹³1Paramagnetic
Lu³⁺f¹⁴0Diamagnetic

Gd³⁺ (f⁷) has the highest magnetic moment due to 7 unpaired electrons.

5. Color of Lanthanoid Ions

Many Ln³⁺ ions are colored due to f-f transitions (weak, forbidden transitions).

Colors in Aqueous Solution:

IonColorIonColor
La³⁺ColorlessGd³⁺Colorless
Ce³⁺ColorlessTb³⁺Pale pink
Ce⁴⁺Red-orangeDy³⁺Yellow
Pr³⁺GreenHo³⁺Yellow
Nd³⁺VioletEr³⁺Pink
Pm³⁺PinkTm³⁺Pale green
Sm³⁺YellowYb³⁺Colorless
Eu³⁺Pale pinkLu³⁺Colorless

Colorless ions: La³⁺ (f⁰), Gd³⁺ (f⁷, half-filled), Lu³⁺ (f¹⁴)

Why colored?

  • f-f transitions in visible region
  • Forbidden transitions (weak absorption)
  • Colors are pale compared to d-block elements

6. Complex Formation

Lanthanoids have less tendency to form complexes compared to d-block elements.

Reasons:

  1. Large ionic size (low charge density)
  2. No vacant d-orbitals for bonding
  3. +3 charge is moderate

Some complexes:

  • [Ce(NO₃)₆]²⁻
  • Lanthanoid chelates with EDTA
  • Organometallic compounds

Coordination Numbers:

  • Usually high: 8, 9, or even 12
  • Due to large size

Comparison with Actinoids

PropertyLanthanoidsActinoids
Series4f (58-71)5f (90-103)
Common OS+3+3, +4, +5, +6, +7
Oxidation StatesLimited (+2, +3, +4)Variable (+3 to +7)
RadioactivityNOT radioactive*ALL radioactive
Complex FormationLess tendencyGreater tendency
ContractionLanthanoid contractionActinoid contraction
Ionic RadiiLargerSmaller (at same OS)
MagneticParamagnetic (mostly)Paramagnetic
ColorPale colors (f-f)Deep colors
OccurrenceNaturalMostly synthetic

*Except Pm-61 (all isotopes radioactive)


Applications of Lanthanoids

Industrial Uses

1. Permanent Magnets:

  • Nd-Fe-B magnets (Neodymium): Strongest permanent magnets
  • Used in hard drives, speakers, electric motors

2. Catalysts:

  • Ce compounds: Catalytic converters in automobiles
  • La: Petroleum cracking catalysts

3. Phosphors and LEDs:

  • Eu, Tb: Red and green phosphors in LEDs, TVs
  • Ce: Scintillation counters

4. Glass and Ceramics:

  • Ce oxide: Glass polishing powder
  • Pr, Nd: Colored glass and welder’s goggles

5. Lasers:

  • Nd:YAG laser (Neodymium-doped yttrium aluminum garnet)

6. Hydrogen Storage:

  • LaNi₅: Rechargeable battery electrodes

7. Medical Applications:

  • Gd compounds: MRI contrast agents

8. Metallurgy:

  • Mischmetal (Ce-rich mixture): Added to steels and alloys
Real-World Impact
Electric vehicles use 1 kg of neodymium in their motors! That’s why lanthanoid mining is crucial for the green energy transition. Wind turbines also use massive Nd-magnets - some up to 600 kg per turbine!

Separation of Lanthanoids

Extremely difficult due to:

  1. Very similar chemical properties
  2. Nearly identical ionic radii
  3. All show +3 oxidation state

Methods

1. Ion Exchange Chromatography:

  • Most effective modern method
  • Uses ion-exchange resins
  • Smaller ions (Lu³⁺) bind more strongly
  • Eluted in order: La → Ce → … → Lu

2. Solvent Extraction:

  • Uses organic solvents
  • Exploits slight differences in partition coefficients

3. Fractional Crystallization:

  • Traditional method
  • Repeated crystallization of salts
  • Very tedious (hundreds of cycles needed!)

Common JEE Mistakes

  1. Lanthanum is NOT a lanthanoid

    • Lanthanoids: Ce (58) to Lu (71)
    • Lanthanum (57) is often grouped with them but technically separate
    • La has no f-electrons: [Xe]5d¹6s²
  2. Lanthanoid contraction causes

    • Wrong: Filled f-orbitals cause contraction
    • Correct: POOR SHIELDING by f-electrons causes contraction
  3. Similar radii of 4d and 5d

    • Wrong: They’re in same group
    • Correct: Lanthanoid contraction compensates for expected increase
  4. Color origin

    • d-block: d-d transitions (strong, bright colors)
    • f-block: f-f transitions (weak, pale colors)
  5. Oxidation states

    • ALL lanthanoids show +3 as primary state
    • Only Ce (+4), Eu (+2), Yb (+2) are notable exceptions
  6. Promethium exception

    • Pm-61 is radioactive (no stable isotopes)
    • All other lanthanoids are NOT radioactive

Practice Problems

Level 1: Basic Concepts

  1. What is lanthanoid contraction? Write its causes.

  2. Why are lanthanoids difficult to separate from each other?

  3. Write electronic configuration of:

    • Ce (Z=58)
    • Gd (Z=64)
    • Lu (Z=71)
  4. Which lanthanoid ions are diamagnetic?

Level 2: Application

  1. Explain the following:

    • Ce⁴⁺ is a good oxidizing agent
    • Eu²⁺ is a good reducing agent
    • Gd³⁺ is colorless despite having 7 f-electrons
  2. Compare:

    • Ionic radii of La³⁺ and Lu³⁺
    • Atomic radii of Zr and Hf
    • Basic strength of La(OH)₃ and Lu(OH)₃
  3. Why do lanthanoids show limited oxidation states compared to actinoids?

Level 3: JEE Advanced

  1. Arrange in order of decreasing ionic radii: Ce³⁺, Eu³⁺, Gd³⁺, Lu³⁺

  2. The most common oxidation state of lanthanoids is:

    • (a) +2
    • (b) +3
    • (c) +4
    • (d) +5
  3. Which property is NOT a consequence of lanthanoid contraction?

    • (a) Similar radii of Zr and Hf
    • (b) Difficulty in separation of lanthanoids
    • (c) Decrease in basic character from La(OH)₃ to Lu(OH)₃
    • (d) Radioactivity of lanthanoids
  4. Assertion (A): Lanthanoid contraction is caused by poor shielding of 4f electrons. Reason (R): The size of Hf is similar to Zr due to lanthanoid contraction.

    • (a) Both A and R true, R explains A
    • (b) Both true, R doesn’t explain A
    • (c) A true, R false
    • (d) Both false
  5. Calculate the total decrease in ionic radius from La³⁺ (106 pm) to Lu³⁺ (85 pm). What is the average decrease per element?

Quick Check
Can you explain: Why does Hf have similar atomic radius to Zr, even though Hf is in the 6th period and Zr is in the 5th? (Hint: What happens between Zr and Hf in the periodic table?)

Memory Tricks

“LCPN” for Lanthanoid Series

Starts with:

  • Lanthanum (though not technically a lanthanoid)
  • Cerium (first true lanthanoid)
  • Praseodymium
  • Neodymium
  • …and so on

Lanthanoid Contraction

“Poor Shielding = Smaller Size”

  • 4f electrons shield poorly
  • Nuclear charge increases
  • Size decreases across series

Variable Oxidation States

“CE uses 4, EU and YB use 2”

  • Ce: +4 (noble gas config)
  • Eu: +2 (half-filled f⁷)
  • Yb: +2 (fully-filled f¹⁴)

Consequences of Contraction

“SZBD” (Size Decreases, But Difficult)

  • Separation is difficult
  • Zr and Hf similar (also Nb-Ta, Mo-W)
  • Basicity decreases (La(OH)₃ > Lu(OH)₃)
  • Density increases

Within d-f Block Elements

Other Chemistry Topics

Cross-Subject Connections