Chemistry Organic Compounds Containing Halogens

Organic Compounds Containing Halogens Formula Sheet

All key reactions, mechanisms, and reactivity orders for haloalkanes, haloarenes, SN1/SN2, E1/E2 & polyhalogens — JEE Main & Advanced quick revision.

8 min read Updated Jun 2026 #formula sheet#quick revision#jee-main

Last-minute revision sheet for the entire Halogens Compounds chapter — every preparation reaction, reactivity order, mechanism, and high-yield environmental fact, grouped by sub-topic for fast scanning.

How to use this sheet
This is a mostly reaction- and fact-based chapter (organic chemistry), so the “formulas” here are named reactions, reactivity orders, and rate equations. Everything below is drawn only from the chapter pages — no outside additions.

General Formulas & Bond Nature

QuantityFormulaNotes
Alkyl halide$\text{R-X}$X = F, Cl, Br, I
Aryl halide (haloarene)$\text{Ar-X}$X on sp² ring carbon
C-X polarity$\delta^+\text{C} - \delta^-\text{X}$Carbon is electrophilic
$$\boxed{\delta^+ \text{C} - \delta^- \text{X} \quad (\text{polar covalent})}$$

Classification (1°/2°/3°): count carbons attached to the C bearing X — 1 neighbour = 1°, 2 = 2°, 3 = 3°.


Key Reactivity & Property Orders

These ordered relations are the single most-tested items in the chapter.

PropertyOrderReason
Bond strength (C-X)$\text{C-F} > \text{C-Cl} > \text{C-Br} > \text{C-I}$BDE: 485 > 339 > 285 > 213 kJ/mol
Reactivity in nucleophilic substitution$\text{R-I} > \text{R-Br} > \text{R-Cl} > \text{R-F}$Leaving-group ability (opposite to bond strength)
Leaving group ability$\text{I}^- > \text{Br}^- > \text{Cl}^- > \text{F}^-$More stable anion = better LG
Boiling point$\text{R-I} > \text{R-Br} > \text{R-Cl} > \text{R-F}$Molecular mass / van der Waals
Density$\text{R-I} > \text{R-Br} > \text{R-Cl} > \text{R-F}$All denser than water
Dipole moment$\text{CH}_3\text{F} > \text{CH}_3\text{Cl} > \text{CH}_3\text{Br} > \text{CH}_3\text{I}$EN decreases down the group
Alcohol reactivity with HX$3° > 2° > 1°$Carbocation stability
HX reactivity$\text{HI} > \text{HBr} > \text{HCl}$HF works poorly
$$\boxed{\text{Bond strength: C-F} > \text{C-Cl} > \text{C-Br} > \text{C-I}}$$

$$\boxed{\text{Reactivity \& LG ability: I} > \text{Br} > \text{Cl} > \text{F}}$$
The reactivity paradox
C-I is the weakest bond yet R-I is the most reactive — because I⁻ is the most stable (best) leaving group. Bond strength and reactivity run opposite.

Branching → lower BP: 1-bromobutane (101 °C) vs 2-bromo-2-methylpropane (73 °C).


Preparation of Alkyl Halides

From Alcohols

$$\boxed{\text{R-OH} + \text{HX} \rightarrow \text{R-X} + \text{H}_2\text{O}}$$
ReagentReactionNote
PCl₃$3\text{R-OH} + \text{PCl}_3 \rightarrow 3\text{R-Cl} + \text{H}_3\text{PO}_3$All alcohol types
PCl₅$\text{R-OH} + \text{PCl}_5 \rightarrow \text{R-Cl} + \text{POCl}_3 + \text{HCl}$
PBr₃$3\text{R-OH} + \text{PBr}_3 \rightarrow 3\text{R-Br} + \text{H}_3\text{PO}_3$
PI₃$3\text{R-OH} + \text{PI}_3 \rightarrow 3\text{R-I} + \text{H}_3\text{PO}_3$
SOCl₂$\text{R-OH} + \text{SOCl}_2 \rightarrow \text{R-Cl} + \text{SO}_2\uparrow + \text{HCl}\uparrow$Purest product (gaseous by-products escape)

Halogenation of Alkanes (free radical)

$$\boxed{\text{R-H} + \text{X}_2 \xrightarrow{h\nu \text{ or heat}} \text{R-X} + \text{HX}}$$

Gives a mixture of products — poor preparative method.

Addition of HX to Alkenes

$$\boxed{\text{R-CH=CH}_2 + \text{HX} \rightarrow \text{R-CHX-CH}_3 \quad (\text{Markovnikov})}$$

$$\boxed{\text{R-CH=CH}_2 + \text{HBr} \xrightarrow{\text{peroxide}} \text{R-CH}_2\text{-CH}_2\text{Br} \quad (\text{anti-Markovnikov})}$$

Peroxide effect works only with HBr (not HCl or HI).

Halogen Exchange & Special Reactions

ReactionEquationPurpose
Finkelstein$\text{R-X} + \text{NaI} \xrightarrow{\text{dry acetone}} \text{R-I} + \text{NaX}\downarrow$R-Cl/R-Br → R-I
Swarts$\text{R-X} + \text{AgF (or Hg}_2\text{F}_2) \rightarrow \text{R-F} + \text{AgX}$Make R-F
Hunsdiecker$\text{R-COOAg} + \text{Br}_2 \xrightarrow{\text{CCl}_4} \text{R-Br} + \text{CO}_2 + \text{AgBr}$Product has one C less
Finkelstein driving force
NaCl/NaBr are insoluble in acetone and precipitate out, pulling the equilibrium toward R-I.

Nucleophilic Substitution: SN1 vs SN2

General reaction:

$$\boxed{\text{R-X} + \text{Nu}^- \rightarrow \text{R-Nu} + \text{X}^-}$$
FeatureSN2SN1
Steps1 (concerted, backside attack)2 (via carbocation)
Rate law$\text{Rate} = k[\text{R-X}][\text{Nu}^-]$$\text{Rate} = k[\text{R-X}]$
Substrate order$\text{CH}_3 > 1° > 2° > 3°$$3° > 2° > 1° > \text{CH}_3$
Stereochemistry100% inversion (Walden)Racemization (50:50)
NucleophileStrong Nu⁻ neededStrength irrelevant to rate
SolventPolar aprotic (acetone, DMSO, DMF, CH₃CN)Polar protic (H₂O, ROH, HCOOH, CH₃COOH)
RearrangementNonePossible (1,2-shifts)
$$\boxed{\text{SN2 rate} = k[\text{R-X}][\text{Nu}^-]} \qquad \boxed{\text{SN1 rate} = k[\text{R-X}]}$$

SN1 two steps:

$$\text{R-X} \xrightarrow{\text{slow}} \text{R}^+ + \text{X}^- \qquad \text{R}^+ + \text{Nu}^- \xrightarrow{\text{fast}} \text{R-Nu}$$

Carbocation stability:

$$\boxed{3° > 2° > 1° > \text{CH}_3^+}$$

Stabilised by hyperconjugation + inductive (+I) effect.

Nucleophilicity (protic solvent):

$$\boxed{\text{I}^- > \text{Br}^- > \text{Cl}^- > \text{F}^-} \qquad \text{RS}^- > \text{RO}^- > \text{OH}^- > \text{NH}_2^-$$

Negative charge > neutral species.

Mnemonics
SN2 = 2 sides → inversion. SN1 = 1 planar carbocation → attack from both faces → racemization. SPRINT (SN2): Small substrate, Polar aprotic, Robust Nu, Inversion, No rearrangement, Transition state. CRISP (SN1): Carbocation, Rearrangement, Ionizing (protic) solvent, Stable substrate, Planar → racemic.
Common traps
SN2 gives inversion, not racemization. SN1 gives racemization, not complete inversion. Nucleophilicity ≠ basicity — for SN2 think nucleophilicity. Always check SN1 carbocations for rearrangement (e.g. neopentyl bromide + H₂O → tert-butanol).

Special substrates: allylic / benzylic halides do both SN1 & SN2; SN1 favoured by resonance-stabilised carbocation.


Elimination: E1 vs E2

General (β-elimination):

$$\boxed{\text{R-CH}_2\text{-CHX-R'} + \text{Base} \rightarrow \text{R-CH=CH-R'} + \text{HX}}$$
FeatureE2E1
Steps1 (concerted)2 (via carbocation)
Rate law$\text{Rate} = k[\text{R-X}][\text{Base}]$$\text{Rate} = k[\text{R-X}]$
Substrate$3° \geq 2° > 1°$$3° > 2° \gg 1°$
BaseStrong base requiredWeak base OK
StereochemistryAnti-periplanar (H, X at 180°)No restriction
RearrangementNonePossible
Competes withSN2SN1
$$\boxed{\text{E2 rate} = k[\text{R-X}][\text{Base}]} \qquad \boxed{\text{E1 rate} = k[\text{R-X}]}$$

E1 two steps:

$$\text{R-X} \xrightarrow{\text{slow}} \text{R}^+ + \text{X}^- \qquad \text{R}^+ \xrightarrow{-\text{H}^+,\ \text{fast}} \text{Alkene}$$

Saytzeff vs Hofmann

Alkene stability:

$$\boxed{\text{Tetra} > \text{Tri} > \text{Di} > \text{Mono-substituted}}$$
RuleMajor productConditions
Saytzeff (Zaitsev)More substituted alkeneNormal (e.g. alcoholic KOH)
HofmannLess substituted alkeneBulky base or quaternary R₄N⁺

Example: 2-bromobutane → ~80% 2-butene : 20% 1-butene (Saytzeff).

Substitution vs Elimination cheat-grid
1° → SN2 loves it. 3° + strong base → E2. 2° → depends on everything. High temperature → favours elimination (ΔS positive). Bulky strong base (t-BuO⁻) → E2. Strong small nucleophile (CN⁻, I⁻) + polar aprotic → SN2.
SubstrateSmall baseBulky base
SN2 majorE2
SN2 or E2E2 major
SN1/E1E2 only

Haloarenes (Ar-X)

Why unreactive (RIP): Resonance (partial C=X double-bond character, C-Cl ≈ 169 pm), Inert sp² carbon (higher s-character), unstable Phenyl cation. ⇒ ~1000× slower than alkyl halides.

Preparation

MethodEquation
Direct halogenation$\text{C}_6\text{H}_6 + \text{X}_2 \xrightarrow{\text{Lewis acid}} \text{C}_6\text{H}_5\text{X} + \text{HX}$
Sandmeyer$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{CuX} \rightarrow \text{C}_6\text{H}_5\text{X} + \text{N}_2$ (X = Cl, Br)
Gattermann$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{HX/Cu} \rightarrow \text{C}_6\text{H}_5\text{X} + \text{N}_2$
Iodobenzene$\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{KI} \rightarrow \text{C}_6\text{H}_5\text{I} + \text{N}_2 + \text{KCl}$; or C₆H₆ + I₂ with HNO₃
Balz-Schiemann (F)$\text{C}_6\text{H}_5\text{N}_2^+\text{BF}_4^- \xrightarrow{\Delta} \text{C}_6\text{H}_5\text{F} + \text{N}_2 + \text{BF}_3$

Lewis acid catalysts: Cl₂ → FeCl₃/AlCl₃; Br₂ → FeBr₃/AlBr₃; I₂ → needs HNO₃ (oxidant).

Reactions

ReactionEquation / Note
Replacement by OH (industrial)$\text{C}_6\text{H}_5\text{Cl} + \text{NaOH} \xrightarrow{623\text{ K, 300 atm}} \text{C}_6\text{H}_5\text{OH} + \text{NaCl}$
Reduction$\text{C}_6\text{H}_5\text{Cl} + \text{H}_2 \xrightarrow{\text{Ni},\ \Delta} \text{C}_6\text{H}_6 + \text{HCl}$
Wurtz-Fittig$\text{C}_6\text{H}_5\text{Br} + \text{CH}_3\text{Br} + 2\text{Na} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5\text{-CH}_3 + 2\text{NaBr}$
Fittig$2\text{C}_6\text{H}_5\text{Br} + 2\text{Na} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5\text{-C}_6\text{H}_5 + 2\text{NaBr}$ (biphenyl)
Grignard$\text{C}_6\text{H}_5\text{Br} + \text{Mg} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5\text{MgBr}$

SNAr (Activated Nucleophilic Aromatic Substitution)

  • Requires electron-withdrawing groups at o/p positions → addition-elimination via Meisenheimer complex.
  • Activation order: $\text{-NO}_2 > \text{-CN} > \text{-COCH}_3 > \text{-CHO} > \text{-COOH}$.
  • Reactivity: chlorobenzene ≪ 2,4-dinitrochlorobenzene < 2,4,6-trinitrochlorobenzene (picryl chloride).
Directing effect trap
Halogens are ortho/para directing BUT deactivating (“Odd: O/p but Deactivating”). Resonance donation governs orientation; inductive withdrawal slows the ring. Synthesis tip: for meta products use a meta-director (NO₂) first, then introduce halogen.

Boiling Points of Haloarenes

CompoundBP (°C)
Fluorobenzene85
Chlorobenzene132
Bromobenzene156
Iodobenzene188

Polyhalogen Compounds

Chloroform (CHCl₃, trichloromethane)

ReactionEquationProduct/Note
Industrial prep$\text{CH}_4 \xrightarrow{\text{Cl}_2/h\nu} \text{CH}_3\text{Cl} \rightarrow \text{CH}_2\text{Cl}_2 \rightarrow \text{CHCl}_3$Free-radical; goes to CCl₄ with excess Cl₂
Haloform (lab)$\text{CH}_3\text{COCH}_3 + 3\text{Cl}_2 + 4\text{NaOH} \rightarrow \text{CHCl}_3 + 3\text{NaCl} + \text{CH}_3\text{COONa} + 3\text{H}_2\text{O}$
Air + light oxidation$2\text{CHCl}_3 + \text{O}_2 \xrightarrow{h\nu} 2\text{COCl}_2 + 2\text{HCl}$Phosgene (toxic)
Reduction$\text{CHCl}_3 + 6[\text{H}] \xrightarrow{\text{Zn/HCl}} \text{CH}_4 + 3\text{HCl}$
Carbylamine$\text{CHCl}_3 + \text{RNH}_2 + 3\text{KOH} \rightarrow \text{RNC} + 3\text{KCl} + 3\text{H}_2\text{O}$Test for 1° amine (foul smell)
Nitration$\text{CHCl}_3 + \text{HNO}_3 \rightarrow \text{CCl}_3\text{NO}_2 + \text{H}_2\text{O}$Chloropicrin (tear gas)
Why dark bottles + 1% ethanol (HIGH-YIELD)

Dark bottle blocks light-induced oxidation to phosgene; ethanol neutralises any phosgene formed:

$$\text{COCl}_2 + 2\text{C}_2\text{H}_5\text{OH} \rightarrow (\text{C}_2\text{H}_5\text{O})_2\text{CO} + 2\text{HCl}$$

Always state both reasons.

Carbon Tetrachloride (CCl₄)

ReactionEquation
Hydrolysis (very slow)$\text{CCl}_4 + 2\text{H}_2\text{O} \rightarrow \text{CO}_2 + 4\text{HCl}$
Swarts (→ Freons)$\text{CCl}_4 + \text{HF} \xrightarrow{\text{SbF}_3} \text{CCl}_3\text{F}, \text{CCl}_2\text{F}_2, \text{CClF}_3$
From CS₂ (industrial)$\text{CS}_2 + 3\text{Cl}_2 \xrightarrow{\text{catalyst}} \text{CCl}_4 + \text{S}_2\text{Cl}_2$

Freons (CFCs) & Ozone Depletion

FreonFormula
Freon-11CCl₃F
Freon-12CCl₂F₂
Freon-22CHClF₂
Freon-113CCl₂F-CClF₂

Prep: $\text{CCl}_4 + 2\text{HF} \rightarrow \text{CCl}_2\text{F}_2 + 2\text{HCl}$ (SbF₃).

Ozone-destruction catalytic cycle:

$$\text{CCl}_2\text{F}_2 \xrightarrow{\text{UV}} \text{CClF}_2^\bullet + \text{Cl}^\bullet$$

$$\text{Cl}^\bullet + \text{O}_3 \rightarrow \text{ClO}^\bullet + \text{O}_2$$

$$\text{ClO}^\bullet + \text{O}^\bullet \rightarrow \text{Cl}^\bullet + \text{O}_2$$

$$\boxed{\text{Net: } \text{O}_3 + \text{O}^\bullet \rightarrow 2\text{O}_2 \quad (\text{Cl}^\bullet = \text{catalyst})}$$

One Cl• destroys ~100,000 O₃ molecules. Solution: Montreal Protocol (1987) → HFCs (no Cl, no ozone depletion).

Ozone-depleting potential
No Cl = no depletion. HFC-134a (CH₂FCF₃, 0 Cl) < HCFC-22 (CHClF₂, has C-H → breaks down sooner) < CFC-12 (CCl₂F₂) ≈ CCl₄ (4 Cl, most stable). More Cl + no C-H + higher stability = worse.

DDT & Iodoform

  • DDT = (ClC₆H₄)₂CH(CCl₃); prep: $2\text{C}_6\text{H}_5\text{Cl} + \text{CCl}_3\text{CHO} \xrightarrow{\text{H}_2\text{SO}_4} (\text{ClC}_6\text{H}_4)_2\text{CH(CCl}_3) + \text{H}_2\text{O}$.
  • Fat-soluble + non-biodegradable → biomagnification (concentration rises up the food chain; thins bird eggshells).
  • Iodoform $\text{CH}_3\text{COCH}_3 + 3\text{I}_2 + 4\text{NaOH} \rightarrow \text{CHI}_3\downarrow + 3\text{NaI} + \text{CH}_3\text{COONa} + 3\text{H}_2\text{O}$ — yellow ppt; tests for CH₃CO- / CH₃CH(OH)- groups.
Haloform / iodoform test scope
Positive for compounds with CH₃CO- or CH₃CH(OH)- groups: methyl ketones, acetaldehyde, ethanol (→ CH₃CHO), 2° alcohols of type CH₃CH(OH)-. HCHO does not respond (no CH₃ group).

Compound Summary Table

CompoundFormulaKey factEnvironmental issue
ChloroformCHCl₃Oxidises to phosgene; store dark + 1% EtOHHepatotoxic
Carbon tetrachlorideCCl₄Non-flammable, very stableOzone depleter, toxic
FreonsCCl₂F₂ etc.Inert, volatile refrigerantsOzone depletion
DDT(ClC₆H₄)₂CH(CCl₃)Fat-soluble, persistent insecticideBiomagnification
IodoformCHI₃Yellow solid, antisepticLimited use

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