Chemistry Organic Compounds Containing Nitrogen

Nitrogen Compounds Formula Sheet

All key Chemistry reactions, basicity orders, and named reactions for amines and diazonium salts - JEE Main & Advanced quick revision in one place.

6 min read Updated Jun 2026 #formula sheet#quick revision#jee-main

This is a mostly descriptive organic chapter, so the sheet is built around named reactions, reagent-product maps, and basicity orders rather than numeric formulas. Every reaction and order below is taken directly from the chapter pages.

How to use this sheet

The high-value JEE items here are the aqueous basicity order, the HNO₂ test products, and the diazonium reagent-to-product map. Lock those three down first.

Classification at a Glance

TypeGeneral formulaNote
Primary (1°)$\text{R-NH}_2$One group on N
Secondary (2°)$\text{R}_2\text{NH}$Two groups on N
Tertiary (3°)$\text{R}_3\text{N}$Three groups on N
Quaternary salt$\text{R}_4\text{N}^+\text{X}^-$NOT an amine (no lone pair, not basic)
  • Aromatic amine: N directly on ring, e.g. aniline $\text{C}_6\text{H}_5\text{-NH}_2$.
  • Aliphatic (even with a ring): N on CH₂, e.g. benzylamine $\text{C}_6\text{H}_5\text{-CH}_2\text{-NH}_2$.
  • Structure of N in amines: sp³, pyramidal, bond angle ~107°, one lone pair.

Basicity (High-Yield)

Defining relations

$$\text{R-NH}_2 + \text{H}_2\text{O} \rightleftharpoons \text{R-NH}_3^+ + \text{OH}^-$$$$K_b = \frac{[\text{R-NH}_3^+][\text{OH}^-]}{[\text{R-NH}_2]}, \qquad \text{p}K_b = -\log K_b$$$$\boxed{K_a \times K_b = K_w = 10^{-14}}$$$$\boxed{\text{p}K_a + \text{p}K_b = 14}$$
  • Lower $\text{p}K_b$ → stronger base; higher $\text{p}K_a$ of conjugate acid → stronger base.

Order of basicity

$$\boxed{\text{Aqueous: } 2° > 1° > 3° > \text{NH}_3}$$$$\boxed{\text{Gas phase: } 3° > 2° > 1° > \text{NH}_3}$$
  • Aqueous winner is set by a balance of +I effect (3° > 2° > 1°) and solvation of conjugate acid (1° > 2° > 3°).
  • Gas phase is controlled by +I effect alone.
$$\boxed{\text{Overall: Aliphatic} \gg \text{NH}_3 \gg \text{Aromatic}}$$

The chapter’s “ultimate JEE order”:

$$(\text{CH}_3)_2\text{NH} > \text{CH}_3\text{NH}_2 > \text{C}_6\text{H}_5\text{CH}_2\text{NH}_2 > \text{NH}_3 > \text{C}_6\text{H}_5\text{NH}_2$$

Substituent effect on aniline

$$\text{p-CH}_3\text{O-C}_6\text{H}_4\text{-NH}_2 > \text{p-CH}_3\text{-C}_6\text{H}_4\text{-NH}_2 > \text{C}_6\text{H}_5\text{-NH}_2 > \text{p-Cl-C}_6\text{H}_4\text{-NH}_2 > \text{p-NO}_2\text{-C}_6\text{H}_4\text{-NH}_2$$
  • EDG (−OCH₃, −CH₃, −NH₂) increase basicity; EWG (−NO₂, −CN, −X, −CHO) decrease it.
  • Nitroaniline isomers: meta > para > ortho (meta has no direct resonance with NH₂, so only −I acts).

pKb values to remember

AminepKb
$(\text{CH}_3)_2\text{NH}$3.27 (strongest aliphatic)
$\text{CH}_3\text{NH}_2$3.38
$\text{C}_2\text{H}_5\text{NH}_2$3.35
$(\text{CH}_3)_3\text{N}$4.22
$\text{NH}_3$4.75 (reference)
$\text{C}_6\text{H}_5\text{CH}_2\text{NH}_2$4.70
$\text{C}_6\text{H}_5\text{NH}_2$ (aniline)9.42
m-nitroaniline11.5
p-nitroaniline13.0
o-nitroaniline14.3

Special cases

SpeciesBehaviourReason
GuanidineExtremely strong base, pKb ≈ 0.4Conjugate acid: +ve charge over 3 equivalent N (resonance)
PyrroleEssentially non-basic, pKb > 14N lone pair is part of aromatic sextet
Aniline > diphenylamine > triphenylamineDecreasing basicityMore phenyls → more lone-pair delocalization

Preparation of Amines

Starting materialReagentProductCarbon change
$\text{R-NO}_2$Sn/HCl, Fe/HCl, LiAlH₄, or H₂/Ni1° aminenone
$\text{R-CN}$LiAlH₄, H₂/Ni, or Na/C₂H₅OH1° amine+1
$\text{R-CO-NH}_2$LiAlH₄1° aminenone
$\text{R-CO-NH}_2$Br₂ + 4 NaOH (Hoffmann)1° amine−1
Phthalimide(1) KOH (2) R-X (3) H₃O⁺ (Gabriel)pure 1° aliphaticnone
$\text{NH}_3$R-Xmixture of 1°,2°,3°,quaternarynone
$\text{R-CHO} + \text{R'-NH}_2$then [H] (reductive amination)2° aminevaries

Key headline equations:

$$\boxed{\text{R-NO}_2 + 6[\text{H}] \rightarrow \text{R-NH}_2 + 2\text{H}_2\text{O}}$$$$\boxed{\text{R-CN} + 4[\text{H}] \rightarrow \text{R-CH}_2\text{-NH}_2}$$$$\boxed{\text{R-CO-NH}_2 \xrightarrow{\text{LiAlH}_4} \text{R-CH}_2\text{-NH}_2}$$$$\boxed{\text{R-CO-NH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O}}$$
LiAlH₄ vs Hoffmann on an amide

Same amide, two different amines: $\text{C}_6\text{H}_5\text{CONH}_2 \xrightarrow{\text{LiAlH}_4} \text{C}_6\text{H}_5\text{CH}_2\text{NH}_2$ (benzylamine, all C kept) vs $\text{C}_6\text{H}_5\text{CONH}_2 \xrightarrow{\text{Br}_2/\text{NaOH}} \text{C}_6\text{H}_5\text{NH}_2$ (aniline, one C lost). “LiAlH₄ is Loyal, Hoffmann is Harsh.”

  • Amide reduction preserves degree: 1° amide → 1° amine, 2° amide → 2° amine, 3° amide → 3° amine.
  • Gabriel fails for aromatic amines (aryl halides don’t do SN2). For aniline, reduce nitrobenzene instead.
  • Selective reduction of one −NO₂ in m-dinitrobenzene: use (NH₄)₂S.

Physical Properties

$$\boxed{\text{Boiling point (similar mass): } 1° > 2° > 3°}$$$$\boxed{\text{Alcohols} > \text{1° Amines} > \text{Hydrocarbons (similar mass)}}$$
  • Driver: H-bonding capacity (count of N-H bonds). H-bonding outweighs molecular mass — e.g. $(\text{CH}_3)_2\text{NH}$ (bp 7°C) > $(\text{CH}_3)_3\text{N}$ (bp 3°C) despite higher mass of the 3° amine.
  • Solubility in water: lower amines C₁-C₄ soluble; aromatic amines insoluble (but soluble in dilute acid as the salt). Order $1° \approx 2° > 3°$.

Chemical Reactions of Amines

Salt formation, acylation, benzoylation

$$\text{R-NH}_2 + \text{HCl} \rightarrow [\text{R-NH}_3^+]\text{Cl}^-$$$$\text{R-NH}_2 + \text{CH}_3\text{COCl} \rightarrow \text{R-NH-CO-CH}_3 + \text{HCl}$$$$\text{R-NH}_2 + \text{C}_6\text{H}_5\text{COCl} \xrightarrow{\text{NaOH}} \text{R-NH-CO-C}_6\text{H}_5 \quad (\text{Schotten-Baumann})$$
  • Acylation/benzoylation: 1° and 2° react; 3° does not (no N-H).

Identification tests

TestReagent
CarbylamineCHCl₃ + 3KOH, Δfoul-smelling isocyanide (positive)no reactionno reaction
HinsbergC₆H₅SO₂Clsulfonamide, soluble in KOHsulfonamide, insolubleno reaction
$$\boxed{\text{R-NH}_2 + \text{CHCl}_3 + 3\text{KOH} \xrightarrow{\Delta} \text{R-N}{\equiv}\text{C} + 3\text{KCl} + 3\text{H}_2\text{O}}$$
Carbylamine scope

Carbylamine distinguishes 1° from 2°/3°, NOT aliphatic from aromatic. Both aliphatic and aromatic primary amines give the foul smell.

Reaction with nitrous acid (HNO₂)

AmineProductObservation
1° aliphaticR-OH + N₂brisk effervescence (N₂ gas)
1° aromatic$[\text{Ar-N}_2^+]\text{Cl}^-$stable diazonium salt at 0-5°C
2° (aliphatic or aromatic)$\text{R}_2\text{N-N=O}$yellow oily N-nitrosamine (carcinogenic)
3° aliphatic$[\text{R}_3\text{NH}^+]\text{NO}_2^-$water-soluble nitrite salt
3° aromaticp-nitroso-N,N-dialkylanilinegreen colour

Electrophilic substitution in aniline

  • −NH₂ is strongly activating, ortho/para directing; electron density ortho ≈ para > meta.
  • Direct bromination gives 2,4,6-tribromoaniline (white ppt) — uncontrolled.
  • For mono-substitution: acetylate → react → hydrolyse (acetanilide is moderately activating).
$$\text{C}_6\text{H}_5\text{NH}_2 + 3\text{Br}_2(\text{aq}) \rightarrow 2,4,6\text{-tribromoaniline} + 3\text{HBr}$$
  • Sulphonation of aniline (via anilinium salt, 180-200°C) gives sulfanilic acid (p-aminobenzenesulfonic acid).
  • Oxidation: aniline → black tar (cannot be cleanly oxidised to nitrobenzene).

Diazonium Salts

Diazotization

$$\boxed{\text{Ar-NH}_2 + \text{NaNO}_2 + 2\text{HCl} \xrightarrow{0\text{-}5°\text{C}} [\text{Ar-N}_2^+]\text{Cl}^- + \text{NaCl} + 2\text{H}_2\text{O}}$$
  • Aromatic 1° amines only; 0-5°C essential; never isolate, use in situ.
  • Above ~10°C decomposes: $[\text{C}_6\text{H}_5\text{N}_2^+]\text{Cl}^- \rightarrow \text{C}_6\text{H}_5\text{OH} + \text{N}_2 + \text{HCl}$.
  • Aromatic salts are stable (resonance with ring); aliphatic salts decompose instantly even at 0°C.

Replacement reactions (memorize this map)

Target groupReagentNamed methodProduct
−FHBF₄, then heatBalz-SchiemannAr-F
−ClCuCl, or Cu/HClSandmeyer / GattermannAr-Cl
−BrCuBr, or Cu/HBrSandmeyer / GattermannAr-Br
−IKI (no catalyst)direct substitutionAr-I
−CNCuCNSandmeyer onlyAr-CN
−OHH₂O, warmhydrolysisphenol
−HH₃PO₂ or C₂H₅OH/Znreduction (deamination)arene
−N=N-Ar′Ar′-OH or Ar′-NR₂couplingazo dye
$$[\text{Ar-N}_2^+]\text{X}^- \xrightarrow{\text{Cu}_2\text{X}_2 \text{ or CuX}} \text{Ar-X} + \text{N}_2 \quad (\text{Sandmeyer})$$$$[\text{Ar-N}_2^+]\text{X}^- \xrightarrow{\text{Cu/HX}} \text{Ar-X} + \text{N}_2 \quad (\text{Gattermann})$$
  • For −CN only Sandmeyer (CuCN) works; for −F only Balz-Schiemann; for −I plain KI suffices.
  • Synthetic chains: aniline → ArN₂⁺ → CuCN → Ar-CN → (H₃O⁺) → Ar-COOH; aniline → ArN₂⁺ → (H₂O, warm) → phenol.

Azo Coupling and Dyes

$$\boxed{[\text{Ar-N}_2^+]\text{X}^- + \text{Ar'-H} \rightarrow \text{Ar-N=N-Ar'} + \text{HX}}$$
Coupling partnerpH / mediumReason
Phenols, naphtholspH 8-10 (alkaline)forms phenoxide (C₆H₅O⁻), more activated
Aromatic aminespH 4-5 (weakly acidic)keeps −NH₂ free and N₂⁺ stable
  • Coupling needs a strongly activated ring (−OH, −OR, −NH₂, −NHR, −NR₂). Benzene, toluene, chlorobenzene, nitrobenzene do not couple.
  • Regioselectivity: predominantly para (less steric hindrance). Temperature 0-5°C throughout.
  • Colour source: extended conjugation; chromophore = −N=N−; auxochromes = −OH, −NH₂, −SO₃H. EDG → bathochromic (red) shift; EWG → hypsochromic (blue) shift.
  • Methyl orange = sulfanilic acid (diazotized) + N,N-dimethylaniline; red in acid (pH < 3.1), yellow in base (pH > 4.4).
  • Orange II = sulfanilic acid (diazotized) + β-naphthol (alkaline coupling).
Classic identification test

An unknown gives a diazonium salt with NaNO₂/HCl at 0-5°C and then a brilliant orange dye with alkaline β-naphthol → the unknown is an aromatic primary amine (e.g. aniline).

Reaction Map

graph TD
    NB["Nitrobenzene C6H5NO2"] -->|Sn/HCl| AN["Aniline C6H5NH2"]
    AN -->|"NaNO2/HCl, 0-5C"| DZ["Diazonium C6H5N2+ Cl-"]
    DZ -->|CuCl| ArCl["Chlorobenzene"]
    DZ -->|CuCN| ArCN["Benzonitrile"]
    DZ -->|"H2O, warm"| PhOH["Phenol"]
    DZ -->|H3PO2| Bz["Benzene"]
    DZ -->|"HBF4, heat"| ArF["Fluorobenzene"]
    DZ -->|KI| ArI["Iodobenzene"]
    DZ -->|"phenol/amine coupling"| Azo["Azo dye Ar-N=N-Ar'"]
    ArCN -->|H3O+| COOH["Benzoic acid"]

See Also