Introduction
Hybridization is the key to understanding the 3D shapes of organic molecules! It explains why methane is tetrahedral, ethene is planar, and ethyne is linear. Master this concept, and organic chemistry becomes 10x easier!
What is Hybridization?
Definition
Hybridization is the concept of mixing atomic orbitals to form new hybrid orbitals of equal energy, which are better suited for bonding.
$$\boxed{\text{Atomic orbitals} \xrightarrow{\text{Mix}} \text{Hybrid orbitals} \xrightarrow{\text{Overlap}} \text{Bonds}}$$Why Hybridization?
Problem: Ground state carbon has 2 unpaired electrons, should form only 2 bonds!
Carbon ground state: 1s² 2s² 2p²
2s: [↑↓]
2p: [↑] [↑] [ ]
But carbon forms 4 bonds in CH₄!
Solution: Hybridization
Excitation: One 2s electron promoted to 2p
2s: [↑] 2p: [↑] [↑] [↑]Hybridization: 2s and 2p orbitals mix to form hybrid orbitals
Result: 4 equivalent hybrid orbitals for bonding!
Types of Hybridization
Summary Table
| Hybridization | Orbitals Mixed | Hybrid Orbitals | Geometry | Bond Angle | Examples |
|---|---|---|---|---|---|
| sp³ | 1s + 3p | 4 sp³ | Tetrahedral | 109.5° | CH₄, C₂H₆, Diamond |
| sp² | 1s + 2p | 3 sp² + 1p | Trigonal planar | 120° | C₂H₄, C₆H₆, Graphite |
| sp | 1s + 1p | 2 sp + 2p | Linear | 180° | C₂H₂, CO₂, HCN |
sp³ Hybridization
Formation
Mixing: 1 s orbital + 3 p orbitals → 4 sp³ hybrid orbitals
graph LR
A[2s: 1 orbital] --> C[4 sp³ orbitals]
B[2p: 3 orbitals] --> C
C --> D[Tetrahedral arrangement]Energy diagram:
Before: After hybridization:
2p: [↑] [↑] [↑] sp³: [↑] [↑] [↑] [↑]
2s: [↑] (equal energy)
Characteristics
Geometry: Tetrahedral
Bond Angle: 109.5° (109° 28')
% s-character: 25% (1/4)
% p-character: 75% (3/4)
Shape of sp³ orbital:
- Large lobe pointing in one direction
- Small lobe in opposite direction
- Better overlap → stronger bonds
Examples
1. Methane (CH₄)
Structure:
- C is sp³ hybridized
- 4 sp³ orbitals overlap with H 1s orbitals
- All C-H bonds equivalent
- Perfect tetrahedral: All angles = 109.5°
2. Ethane (C₂H₆)
Structure:
- Both carbons sp³ hybridized
- C-C bond: sp³-sp³ overlap (σ-bond)
- C-H bonds: sp³-1s overlap (σ-bonds)
- Free rotation around C-C single bond
3. Ammonia (NH₃)
Structure:
- N is sp³ hybridized
- 3 sp³ orbitals form N-H bonds
- 1 sp³ orbital contains lone pair
- Pyramidal shape (not tetrahedral!)
- Bond angle: 107° (less than 109.5° due to lone pair repulsion)
4. Water (H₂O)
Structure:
- O is sp³ hybridized
- 2 sp³ orbitals form O-H bonds
- 2 sp³ orbitals contain lone pairs
- Bent shape
- Bond angle: 104.5° (lone pair-lone pair > lone pair-bond pair repulsion)
Bond angle trend due to lone pairs:
$$\boxed{CH_4 (109.5°) > NH_3 (107°) > H_2O (104.5°)}$$Rule: More lone pairs → smaller bond angle (lone pairs repel more strongly)
5. Diamond
Structure:
- Each C is sp³ hybridized
- 3D network of C-C single bonds
- Tetrahedral geometry throughout
- Extremely hard (strong C-C σ-bonds in 3D)
sp² Hybridization
Formation
Mixing: 1 s orbital + 2 p orbitals → 3 sp² hybrid orbitals + 1 unhybridized p orbital
graph LR
A[2s: 1 orbital] --> C[3 sp² orbitals]
B[2p: 2 orbitals] --> C
D[2p: 1 orbital] --> E[Unhybridized p]
C --> F[Trigonal planar]
E --> G[π-bonding]Energy diagram:
Before: After hybridization:
2p: [↑] [↑] [↑] sp²: [↑] [↑] [↑] (in plane)
2s: [↑] p: [↑] (perpendicular)
Characteristics
Geometry: Trigonal planar (all atoms in one plane)
Bond Angle: 120°
% s-character: 33.3% (1/3)
% p-character: 66.7% (2/3)
Unhybridized p orbital: Perpendicular to the plane, used for π-bonding
Examples
1. Ethene (C₂H₄)
Structure:
- Both C atoms sp² hybridized
- σ-bonds:
- C-C: sp²-sp² overlap
- C-H: sp²-1s overlap (4 bonds)
- π-bond:
- Sideways overlap of unhybridized p orbitals
- Above and below the plane
Double bond = 1 σ + 1 π
Important features:
- All 6 atoms in same plane
- No free rotation around C=C (π-bond restricts rotation)
- Bond angle: ~120° (slightly less due to π-electron repulsion)
2. Benzene (C₆H₆)
Structure:
- All 6 C atoms sp² hybridized
- σ-bonds:
- C-C: sp²-sp² overlap (6 bonds forming hexagon)
- C-H: sp²-1s overlap (6 bonds)
- π-bonds:
- 6 unhybridized p orbitals (one per C)
- Delocalized over the entire ring
- Forms π-electron cloud above and below the ring
Features:
- Perfectly planar molecule
- All C-C bonds equal length (1.39 Å)
- All bond angles = 120°
- Aromatic stability due to delocalized π-electrons
3. Graphite
Structure:
- All C atoms sp² hybridized
- Forms hexagonal layers
- Within layer: Strong C-C σ-bonds (sp²-sp²)
- Between layers: Weak van der Waals forces
- Delocalized π-electrons move freely (electrical conductivity!)
Properties from sp²:
- Soft (layers slide easily)
- Good conductor (delocalized electrons)
- Black color (π-electron transitions)
4. Carbonyl Group (C=O)
Structure:
- C is sp² hybridized
- O is sp² hybridized (+ 2 lone pairs in sp²)
- σ-bond: sp²(C) - sp²(O)
- π-bond: p(C) - p(O)
- Planar geometry around C=O
“sp² = 2 Doubly bonded”
- sp² hybridization is present when there’s a DOUBLE bond
- Geometry is PLANAR (all in 2D plane)
- Bond angle is 120° (three bonds spread out)
Examples: C=C, C=O, C=N, benzene
sp Hybridization
Formation
Mixing: 1 s orbital + 1 p orbital → 2 sp hybrid orbitals + 2 unhybridized p orbitals
graph LR
A[2s: 1 orbital] --> C[2 sp orbitals]
B[2p: 1 orbital] --> C
D[2p: 2 orbitals] --> E[2 unhybridized p]
C --> F[Linear]
E --> G[2 π-bonds]Energy diagram:
Before: After hybridization:
2p: [↑] [↑] [↑] sp: [↑] [↑] (linear)
2s: [↑] p: [↑] [↑] (perpendicular)
Characteristics
Geometry: Linear (180° apart)
Bond Angle: 180°
% s-character: 50% (1/2)
% p-character: 50% (1/2)
Unhybridized p orbitals: 2 perpendicular p orbitals for π-bonding
Examples
1. Ethyne/Acetylene (C₂H₂)
Structure:
- Both C atoms sp hybridized
- σ-bonds:
- C-C: sp-sp overlap
- C-H: sp-1s overlap (2 bonds)
- π-bonds:
- Two p-p overlaps (perpendicular to each other)
- Form cylindrical π-electron cloud around C-C axis
Triple bond = 1 σ + 2 π
Important features:
- Linear molecule (H-C-C-H all in one line)
- Bond angle: 180°
- No free rotation (two π-bonds lock the molecule)
- Very strong C≡C bond
2. Carbon Dioxide (CO₂)
Structure:
- C is sp hybridized
- Each O is sp² hybridized
- σ-bonds: sp(C) - sp²(O) on each side
- π-bonds: 2 π-bonds (one with each O)
- Linear molecule: O=C=O (180°)
3. Hydrogen Cyanide (HCN)
Structure:
- C is sp hybridized
- σ-bonds:
- C-H: sp-1s
- C-N: sp-sp
- π-bonds: 2 π-bonds (C≡N triple bond)
- Linear: H-C≡N (180°)
4. Alkynes (General)
R-C≡C-R’
- Both triple-bonded carbons: sp
- Linear geometry at triple bond
- Bond angle: 180°
Bond length and strength trend:
$$\boxed{C \equiv C < C=C < C-C \text{ (length)}}$$ $$\boxed{C \equiv C > C=C > C-C \text{ (strength)}}$$Reason:
- sp has 50% s-character (most s → shortest, strongest)
- sp² has 33% s-character (intermediate)
- sp³ has 25% s-character (least s → longest, weakest)
More s-character → Shorter, stronger bonds
Interactive Demo: Visualize Orbital Shapes
Explore sp, sp², and sp³ hybrid orbitals in 3D space.
Comparison of Hybridizations
Properties Comparison
| Property | sp³ | sp² | sp |
|---|---|---|---|
| Orbitals mixed | 1s + 3p | 1s + 2p | 1s + 1p |
| Hybrid orbitals | 4 | 3 | 2 |
| Unhybridized p | 0 | 1 | 2 |
| Geometry | Tetrahedral | Trigonal planar | Linear |
| Bond angle | 109.5° | 120° | 180° |
| s-character | 25% | 33.3% | 50% |
| p-character | 75% | 66.7% | 50% |
| Bond type | Only σ | σ + π | σ + 2π |
| Rotation | Free | Restricted | No rotation |
| Example | C₂H₆ | C₂H₄ | C₂H₂ |
Bond Properties
s-character effects:
Bond length: More s → shorter bond
$$sp < sp² < sp³$$Bond strength: More s → stronger bond
$$sp > sp² > sp³$$Acidity: More s → more acidic H
$$HC \equiv CH > H_2C=CH_2 > H_3C-CH_3$$(pKa: 25 > 44 > 50)
Electronegativity: More s → more electronegative C
$$sp > sp² > sp³$$
Mistake: Assuming all carbon atoms have the same hybridization in a molecule.
Correct: Different carbons can have different hybridizations!
Example: CH₂=CH-CH₃ (propene)
- C1 (in =CH₂): sp²
- C2 (in CH=): sp²
- C3 (in -CH₃): sp³
Always identify each carbon’s bonding separately!
Determining Hybridization
Method 1: Counting Regions of Electron Density
Steric Number = σ-bonds + Lone pairs
| Steric Number | Hybridization | Geometry |
|---|---|---|
| 2 | sp | Linear |
| 3 | sp² | Trigonal planar |
| 4 | sp³ | Tetrahedral |
Examples:
CH₄: C has 4 σ-bonds, 0 lone pairs → Steric # = 4 → sp³
NH₃: N has 3 σ-bonds, 1 lone pair → Steric # = 4 → sp³
C₂H₄: Each C has 3 σ-bonds (2 C-H, 1 C-C), 0 lone pairs → sp²
CO₂: C has 2 σ-bonds (2 C-O), 0 lone pairs → sp
Method 2: Counting Bonds
| Bond Type | Hybridization |
|---|---|
| 4 single bonds (4σ) | sp³ |
| 1 double + 2 single (3σ + 1π) | sp² |
| 1 triple + 1 single (2σ + 2π) | sp |
| 2 double bonds (2σ + 2π) | sp |
Key: Count σ-bonds only for hybridization!
Resonance and Hybridization
Resonance Structures
When resonance is present, hybridization is determined by the resonance hybrid, not individual structures.
Example: Carboxylate ion (CH₃COO⁻)
Both oxygens are equivalent due to resonance:
O⁻ O
‖ ↔ ‖
R—C R—C
| |
O O⁻
Hybridization:
- C (carbonyl): sp²
- Both O atoms: sp² (not one sp² and one sp³!)
- Resonance averages the bonding
Benzene Revisited
All 6 carbons are sp² due to resonance:
- Delocalized π-system
- All C-C bonds equivalent (1.39 Å)
- Cannot assign double/single bonds
Applications and Examples
Example 1: Allene (H₂C=C=CH₂)
Structure:
- C1 and C3: sp² (in double bonds, planar)
- C2: sp (forms two double bonds, linear)
Geometry:
- C2 is linear
- C1 and C3 planes are perpendicular to each other!
Example 2: Vitamin C (Ascorbic Acid)
Multiple hybridizations:
- Ring carbons: Mostly sp³
- Carbonyl C: sp²
- Enol C: sp²
Example 3: Formaldehyde (H₂C=O)
Structure:
- C: sp² (3 σ-bonds: 2 C-H, 1 C-O)
- O: sp² (1 σ-bond + 2 lone pairs in sp²)
- Planar molecule
- H-C-H angle ≈ 120°
Practice Problems
Level 1: Basic Identification
Identify the hybridization of each carbon:
- a) CH₃-CH₃
- b) CH₂=CH₂
- c) HC≡CH
- d) CH₃-CH=CH₂
What is the bond angle in:
- a) Methane (CH₄)
- b) Ethene (C₂H₄)
- c) Acetylene (C₂H₂)
How many σ and π bonds in:
- a) C₂H₆
- b) C₂H₄
- c) C₂H₂
Level 2: Application
Explain why:
- C-H bond in acetylene is more acidic than in ethane
- Benzene is planar
- There’s no free rotation around C=C double bond
Determine hybridization of each atom:
- a) Formaldehyde (H₂CO)
- b) Acetone (CH₃COCH₃)
- c) Carbon dioxide (CO₂)
Arrange in order of increasing C-C bond length: CH₃-CH₃, CH₂=CH₂, HC≡CH
Which molecule is linear?
- a) H₂O
- b) NH₃
- c) CO₂
- d) CH₄
Level 3: JEE Advanced
In the molecule CH₃-C≡C-CHO, how many carbon atoms are sp hybridized?
- (a) 1
- (b) 2
- (c) 3
- (d) 4
The H-C-H bond angle in ethene is closest to:
- (a) 109.5°
- (b) 120°
- (c) 117°
- (d) 180°
Which statement is INCORRECT about sp² hybridization?
- (a) Bond angle is 120°
- (b) Geometry is trigonal planar
- (c) One p orbital remains unhybridized
- (d) All four orbitals are used in σ-bonding
Assertion (A): sp hybridized carbon forms stronger C-H bonds than sp³. Reason (R): sp has 50% s-character while sp³ has 25% s-character.
- (a) Both A and R true, R explains A
- (b) Both true, R doesn’t explain A
- (c) A true, R false
- (d) Both false
In benzene, each C-C bond length is 1.39 Å. This is:
- (a) Equal to C-C single bond
- (b) Equal to C=C double bond
- (c) Between single and double bond
- (d) Equal to C≡C triple bond
Memory Tricks
“SLIP” for Hybridization
- Single bonds only → sp³
- Linear geometry → sp
- In-plane (planar) → sp²
- Pi bonds: 0(sp³), 1(sp²), 2(sp)
Bond Angles Quick Memory
“109, 120, 180 - All in Line!”
- sp³: 109.5° (tetrahedral)
- sp²: 120° (planar)
- sp: 180° (linear)
s-character Rule
“More s, More Short, More Strong!”
- More s-character → Shorter bonds
- More s-character → Stronger bonds
- More s-character → More acidic H
- sp (50%) > sp² (33%) > sp³ (25%)
Counting Method
“Count sigma, ignore pi!”
- 4 σ-bonds → sp³
- 3 σ-bonds → sp²
- 2 σ-bonds → sp
Related Topics
Within Organic Principles
- Electronic Effects - How hybridization affects electron distribution
- Isomerism Types - Geometric isomerism in sp²
- Reaction Intermediates - Hybridization of carbocations (sp²)
- Reaction Types - Mechanistic role of hybridization
Chemical Bonding Foundation
- Hybridization in Bonding - VBT perspective on hybridization
- VSEPR Theory - Predicting molecular geometry
- Covalent Bonding - Sigma and pi bonds
- Molecular Orbital Theory - MO diagrams
Atomic Structure
- Orbital Shapes - s, p, d orbital shapes
- Electronic Configuration - Ground state configurations
Hydrocarbon Applications
- Alkanes - sp³ hybridization examples
- Alkenes - sp² hybridization and addition
- Alkynes - sp hybridization, triple bonds
- Benzene - sp² and aromaticity
Functional Group Applications
- Aldehydes and Ketones - sp² carbonyl carbon
- Carboxylic Acids - sp² in -COOH
Cross-Subject Connections
- Vector Algebra - 3D spatial understanding
- Trigonometry - Bond angles