Reactive Intermediates in Organic Chemistry

Master carbocations, carbanions, free radicals, carbenes - their structure, stability, and role in reaction mechanisms for JEE.

Introduction

Reactive intermediates are the fleeting species that form during reactions - they exist for nanoseconds but determine the entire outcome! Understanding them is the KEY to mastering organic reaction mechanisms.

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Classification of Reactive Intermediates

graph TD
    A[Reactive Intermediates] --> B[Carbocation R₃C⁺]
    A --> C[Carbanion R₃C⁻]
    A --> D[Free Radical R₃C·]
    A --> E[Carbene R₂C:]
    B --> B1[sp², planar, empty p]
    C --> C1[sp³, pyramidal, lone pair]
    D --> D1[sp², planar, 1 unpaired e⁻]
    E --> E1[sp², singlet or triplet]

Carbocations (Carbonium Ions)

Structure

Definition: Carbon with positive charge and only 6 electrons in valence shell.

$$\boxed{R_3C^+ \text{ (electron-deficient)}}$$

Electronic Configuration:

  • Hybridization: sp²
  • Geometry: Trigonal planar
  • Bond angle: 120°
  • Empty p-orbital: Perpendicular to plane
        R
        |
    R - C⁺     ← Planar
        |         Empty p-orbital ⊥
        R

Characteristics:

  • Electrophilic (electron-loving)
  • Lewis acid (accepts electron pair)
  • Extremely reactive (short-lived)
  • Forms in polar solvents

Stability Order

$$\boxed{3° > 2° > 1° > CH_3^+ > \text{vinyl} > \text{phenyl}}$$

Detailed:

$$\boxed{(CH_3)_3C^+ > (CH_3)_2CH^+ > CH_3CH_2^+ > CH_3^+ > CH_2=CH^+ > C_6H_5^+}$$

Factors Affecting Stability:

1. Inductive Effect (+I)

Alkyl groups donate electrons, stabilizing positive charge.

(CH₃)₃C⁺: 3 methyl groups donating
(CH₃)₂CH⁺: 2 methyl groups
CH₃CH₂⁺: 1 methyl group
CH₃⁺: 0 methyl groups (least stable)

2. Hyperconjugation

α-Hydrogens delocalize into empty p-orbital.

Number of α-H:

  • tert-Butyl: 9 α-H → 9 hyperconjugative structures
  • Isopropyl: 6 α-H → 6 structures
  • Ethyl: 3 α-H → 3 structures
  • Methyl: 0 α-H → 0 structures

More α-H → More stable

3. Resonance

Delocalization through π-system enormously stabilizes.

Example: Allyl cation (CH₂=CH-CH₂⁺)

CH₂=CH-CH₂⁺  ↔  ⁺CH₂-CH=CH₂

Positive charge delocalized over 2 carbons
Much more stable than propyl cation!

Example: Benzyl cation (C₆H₅-CH₂⁺)

Resonance with benzene ring
Positive charge delocalized into ring
Very stable!

Stability with resonance:

$$\boxed{\text{Allyl/Benzyl} > 3° > 2° > 1°}$$

Special Cases

Vinyl and Phenyl Cations

Extremely unstable!

Vinyl cation (CH₂=CH⁺):

  • Positive charge on sp² carbon
  • High s-character (50%) holds electrons tightly
  • No hyperconjugation possible
  • Very unstable

Phenyl cation (C₆H₅⁺):

  • Disrupts aromaticity
  • Extremely unstable

Bridgehead Cations

Also very unstable - violate Bredt’s rule.

Cannot form planar sp² geometry at bridgehead.

Carbocation Rearrangements

Carbocations rearrange to form more stable species!

1. Hydride Shift (1,2-H shift)

H with electron pair migrates to adjacent carbon.

Example:

   CH₃                    CH₃
    |                      |
CH₃-CH-CH₂⁺  →  CH₃-C⁺-CH₃

2° carbocation    →    3° carbocation
(less stable)          (more stable)

Driving force: Forms more stable carbocation

2. Methyl Shift (1,2-CH₃ shift)

Alkyl group migrates with electron pair.

Example:

   CH₃   CH₃             CH₃   CH₃
    |     |               |     |
CH₃-C---CH⁺  →  CH₃-C⁺--CH₂
    |                    |
   CH₃                  CH₃

2° carbocation    →    3° carbocation

General rule: Always shifts to form more stable carbocation

Common JEE Mistake

Mistake: Forgetting about carbocation rearrangements in mechanisms.

Reality: Carbocations ALWAYS rearrange if it gives more stability!

Example: Hydration of 3-methyl-1-butene

Expected: 3-methylbutan-2-ol Actual: 2-methylbutan-2-ol (after rearrangement!)

CH₃-CH(CH₃)-CH=CH₂ + H₂O
         ↓ H⁺
CH₃-CH(CH₃)-CH₂-CH₂⁺  (2°)
         ↓ rearrangement
CH₃-CH(CH₃)-CH(OH)-CH₃  WRONG!

Correct: H⁺ adds to form 3° cation after rearrangement!

This is THE most common mechanism trap!


Carbanions

Structure

Definition: Carbon with negative charge and 8 electrons (lone pair).

$$\boxed{R_3C^- \text{ (electron-rich)}}$$

Electronic Configuration:

  • Hybridization: sp³
  • Geometry: Pyramidal (like NH₃)
  • Bond angle: ~109°
  • Lone pair in sp³ orbital
        R
        |
    R - C⁻     ← Pyramidal
        |         Lone pair in sp³
        R

Characteristics:

  • Nucleophilic (nucleus-loving)
  • Lewis base (donates electron pair)
  • Very reactive
  • Forms in aprotic solvents (no acidic H)

Stability Order

OPPOSITE of carbocations!

$$\boxed{CH_3^- > 1° > 2° > 3°}$$

Detailed:

$$\boxed{CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-}$$

Also:

$$\boxed{\text{Phenyl} > \text{Vinyl} > \text{sp}^3 \text{ carbanions}}$$

Factors Affecting Stability:

1. Inductive Effect (-I)

Electron-withdrawing groups stabilize negative charge.

CF₃CH₂⁻ > CH₃CH₂⁻

-CF₃ withdraws electrons, stabilizes negative charge

Order with -I groups:

$$\boxed{Cl_3C-CH_2^- > Cl_2CH-CH_2^- > ClCH_2-CH_2^- > CH_3-CH_2^-}$$

2. Hyperconjugation

Destabilizes carbanions! (opposite of carbocations)

More α-H → Less stable carbanion

Why? H atoms are electron-donating, increase electron density on already negative center.

3. Resonance

Enormously stabilizes by delocalizing negative charge.

Example: Cyanide ion (CN⁻)

:C≡N:⁻  ↔  ⁻:C=N:

Negative charge delocalized
Very stable!

Example: Acetate ion (CH₃COO⁻)

     O⁻         O
     ‖    ↔    ‖
CH₃-C         CH₃-C
     |          |
     O          O⁻

Resonance makes acetic acid acidic!

4. Hybridization Effect

More s-character → More stable (holds electrons closer)

$$\boxed{sp (50\%) > sp^2 (33\%) > sp^3 (25\%)}$$

Example:

HC≡C⁻ > CH₂=CH⁻ > CH₃CH₂⁻

Acetylide (sp) most stable
Ethyl (sp³) least stable

Acidity order matches:

$$\boxed{HC \equiv CH \text{ (pKa 25)} > CH_2=CH_2 \text{ (44)} > CH_3CH_3 \text{ (50)}}$$

Carbanion Reactions

Strong bases and nucleophiles

Common reactions:

  1. Nucleophilic substitution
  2. Addition to carbonyls
  3. Elimination reactions
  4. Deprotonation

Free Radicals

Structure

Definition: Species with unpaired electron.

$$\boxed{R_3C \cdot \text{ (one unpaired electron)}}$$

Electronic Configuration:

  • Hybridization: sp²
  • Geometry: Planar (or nearly planar)
  • Bond angle: ~120°
  • Unpaired electron in p-orbital
        R
        |
    R - C·     ← Planar
        |         Unpaired e⁻ in p
        R

Characteristics:

  • Highly reactive
  • Neutral (no charge)
  • Paramagnetic (unpaired electron)
  • React with almost anything!

Stability Order

Same as carbocations!

$$\boxed{3° > 2° > 1° > CH_3 \cdot}$$

Detailed:

$$\boxed{(CH_3)_3C \cdot > (CH_3)_2CH \cdot > CH_3CH_2 \cdot > CH_3 \cdot}$$

Special cases:

$$\boxed{\text{Allyl/Benzyl} \cdot > 3° > 2° > 1°}$$

Factors:

1. Hyperconjugation

More α-H → More stable

Same as carbocations!

2. Resonance

Example: Allyl radical

CH₂=CH-CH₂·  ↔  ·CH₂-CH=CH₂

Unpaired electron delocalized
Very stable!

Example: Benzyl radical

Resonance with benzene ring
Very stable - used in polymerization!

Free Radical Reactions

1. Halogenation

Example: CH₄ + Cl₂ → CH₃Cl + HCl

Mechanism:

Initiation:
Cl₂ --hν--> 2Cl·

Propagation:
CH₄ + Cl· → CH₃· + HCl
CH₃· + Cl₂ → CH₃Cl + Cl·

Termination:
CH₃· + Cl· → CH₃Cl
CH₃· + CH₃· → C₂H₆
Cl· + Cl· → Cl₂

2. Anti-Markovnikov Addition (Peroxide Effect)

Example: CH₃CH=CH₂ + HBr –peroxide–> CH₃CH₂CH₂Br

Normal (without peroxide): Markovnikov (CH₃CHBrCH₃) With peroxide: Anti-Markovnikov (CH₃CH₂CH₂Br)

Mechanism:

Initiation:
ROOR → 2RO·
RO· + HBr → ROH + Br·

Propagation:
Br· + CH₃CH=CH₂ → CH₃CHBrCH₂· (2° radical, more stable)
CH₃CHBrCH₂· + HBr → CH₃CHBrCH₃ + Br·

Wait - this gives Markovnikov!

Actually:
Br· + CH₃CH=CH₂ → CH₃CH·-CH₂Br (less stable, but forms)
                OR
              → ·CH₂-CHBr-CH₃ (2°, preferred!)

Correct mechanism: Br· adds to give more stable radical intermediate!

JEE Alert

Peroxide effect (Anti-Markovnikov) works ONLY with HBr!

NOT with HCl or HI

Why?

  • HCl: C-Cl bond too strong, propagation too slow
  • HI: H-I bond too weak, reverses too easily
  • HBr: Just right! (Goldilocks)

This specificity is heavily tested!

Interactive Demo: Visualize Carbocation Rearrangements

Watch how carbocations rearrange to achieve greater stability.


Carbenes

Structure

Definition: Neutral carbon with only 6 valence electrons and no charge.

$$\boxed{R_2C: \text{ (divalent carbon)}}$$

Two types:

Singlet Carbene

  • Paired electrons in same orbital
  • sp² hybridized
  • Angular geometry
  • Diamagnetic
    R
    |
    C:    ← Bent, sp²
    |       Lone pair in sp²
    R       Empty p

Triplet Carbene

  • Two unpaired electrons
  • sp hybridized
  • Linear geometry
  • Paramagnetic
R-C-R   ← Linear
  : :     Two unpaired in p orbitals

Generation

1. From Haloforms:

CHCl₃ + KOH → :CCl₂ + KCl + H₂O

Dichlorocarbene

2. From Diazomethane:

CH₂N₂ --hν--> :CH₂ + N₂

Methylene (carbene)

Reactions

Highly reactive - inserts into bonds!

1. Addition to alkenes (cyclopropane formation):

    :CH₂ + CH₂=CH₂ → Cyclopropane

2. Insertion into C-H bonds


Nitrenes

Similar to carbenes but with nitrogen

$$\boxed{R-N: \text{ (monovalent nitrogen)}}$$

Generation from azides:

R-N₃ --Δ--> R-N: + N₂

Comparison Summary

IntermediateStructureHybridizationGeometryStability Order
CarbocationR₃C⁺sp²Planar3° > 2° > 1°
CarbanionR₃C⁻sp³Pyramidal1° > 2° > 3°
Free RadicalR₃C·sp²Planar3° > 2° > 1°
CarbeneR₂C:sp² (singlet)Angular-

Key Differences:

PropertyCarbocationCarbanionFree Radical
Charge+1-10
Electrons687
NatureElectrophileNucleophileBoth
+I effectStabilizesDestabilizesStabilizes
Stability3° > 1°1° > 3°3° > 1°

Practice Problems

Level 1: Basic Concepts

  1. Identify the intermediate formed:

    • a) CH₃CH₂Cl + AlCl₃
    • b) CH₃CH₂Br + Mg
    • c) (CH₃)₃C-Cl –hν–>
  2. Arrange in order of stability:

    • a) CH₃⁺, CH₃CH₂⁺, (CH₃)₂CH⁺, (CH₃)₃C⁺
    • b) CH₃⁻, CH₃CH₂⁻, (CH₃)₂CH⁻, (CH₃)₃C⁻
  3. Which is most stable?

    • a) CH₂=CH-CH₂⁺
    • b) CH₃-CH₂-CH₂⁺
    • c) (CH₃)₂CH⁺
    • d) CH₃⁺

Level 2: Application

  1. Explain why:

    • Allyl cation is more stable than propyl cation
    • Acetylene is more acidic than ethane
    • tert-Butyl radical is more stable than methyl radical
  2. Predict the major product:

    CH₃-CH(CH₃)-CH=CH₂ + HCl →
    
    (Consider carbocation rearrangement!)
    
  3. Why does peroxide effect work only with HBr?

Level 3: JEE Advanced

  1. The most stable carbocation is:

    • (a) (CH₃)₃C⁺
    • (b) CH₂=CH-CH₂⁺
    • (c) C₆H₅-CH₂⁺
    • (d) CH₃-CH₂⁺
  2. Which rearrangement is NOT possible?

    • (a) Hydride shift
    • (b) Methyl shift
    • (c) Phenyl shift
    • (d) Alkyl shift
  3. Arrange in increasing order of acidity: HC≡CH, CH₂=CH₂, CH₃-CH₃

  4. Assertion (A): Benzyl cation is more stable than ethyl cation. Reason (R): Benzyl cation shows resonance stabilization.

    • (a) Both true, R explains A
    • (b) Both true, R doesn’t explain A
    • (c) A true, R false
    • (d) Both false
  5. In the reaction CH₃CH=CH₂ + HBr (with peroxide), the intermediate formed is:

    • (a) CH₃CH⁺CH₂Br
    • (b) CH₃CHCH₂Br· (radical)
    • (c) CH₃CH⁻CH₂Br
    • (d) CH₃CH(Br)CH₂·
  6. The stability order of following carbanions is: CH₃⁻, CF₃CH₂⁻, CH₃CH₂⁻, (CH₃)₃C⁻

Quick Check
Can you explain: Why does (CH₃)₂CH-CH₂⁺ rearrange to (CH₃)₂C⁺-CH₃? Draw the mechanism and explain the driving force!

Memory Tricks

“CPR-F” for Intermediates

  • Carbocation: Positive, planar, sp²
  • Carbanion: Negative, pyramidal, sp³ (like NH₃)
  • Radical: Neutral, planar, unpaired electron
  • Free radical stability = Carbocation stability

Stability Orders

“3-2-1 for Cations & Radicals”

  • 3° > 2° > 1° (carbocations and radicals)

“1-2-3 for Anions” (reverse!)

  • 1° > 2° > 3° (carbanions)

Hyperconjugation

“Count Alpha H - More is Better (except anions!)”

  • Carbocations: More α-H → More stable
  • Radicals: More α-H → More stable
  • Carbanions: More α-H → LESS stable (reverse!)

Peroxide Effect

“Only Bromine Reverses”

  • Peroxide effect: Only with HBr
  • Anti-Markovnikov addition
  • NOT with HCl or HI

Within Organic Principles

Other Chemistry Topics

Foundation Topics