Types of Organic Reactions

Master substitution (SN1, SN2), addition, elimination (E1, E2), and rearrangement reactions with mechanisms for JEE Chemistry.

Introduction

Understanding reaction mechanisms is the ultimate skill in organic chemistry! Instead of memorizing thousands of reactions, you learn the patterns - how and why reactions happen. This is what separates JEE toppers from average students.

Teflon's Accidental Discovery
In 1938, Roy Plunkett accidentally discovered Teflon through a free radical polymerization reaction (addition reaction)! He was trying to make refrigerant but left a cylinder of tetrafluoroethylene overnight. The next morning, he found a white waxy solid - Teflon. This non-stick coating on your pans exists because of the reaction mechanisms you’re learning right now. Understanding reaction types can lead to billion-dollar discoveries!

Classification of Organic Reactions

graph TD
    A[Organic Reactions] --> B[By Bond Change]
    A --> C[By Reagent Type]
    B --> B1[Substitution]
    B --> B2[Addition]
    B --> B3[Elimination]
    B --> B4[Rearrangement]
    C --> C1[Nucleophilic]
    C --> C2[Electrophilic]
    C --> C3[Free Radical]

By mechanism:

  1. Substitution: One group replaces another
  2. Addition: Two groups add across multiple bond
  3. Elimination: Two groups leave, forming multiple bond
  4. Rearrangement: Atoms rearrange within molecule

By reagent:

  1. Nucleophilic: Nucleophile attacks
  2. Electrophilic: Electrophile attacks
  3. Free Radical: Radical chain reaction

Substitution Reactions

General: One atom/group replaced by another

$$\boxed{R-X + Nu^- \rightarrow R-Nu + X^-}$$

Nucleophilic Substitution

Nucleophile (Nu⁻): Electron-rich species, attacks electron-poor carbon.

Two mechanisms: SN1 and SN2

SN1: Unimolecular Nucleophilic Substitution

“SN1” = Substitution, Nucleophilic, 1st order

Mechanism:

Step 1: Ionization (slow, rate-determining)

$$R-X \xrightarrow{slow} R^+ + X^-$$

Step 2: Nucleophilic attack (fast)

$$R^+ + Nu^- \xrightarrow{fast} R-Nu$$

Example: tert-Butyl bromide + OH⁻

Step 1 (slow):
(CH₃)₃C-Br → (CH₃)₃C⁺ + Br⁻
(Carbocation formation)

Step 2 (fast):
(CH₃)₃C⁺ + OH⁻ → (CH₃)₃C-OH

Characteristics:

PropertySN1
RateRate = k[RX] (1st order)
MechanismTwo-step (carbocation)
CarbocationFormed (yes)
StereochemistryRacemization (loss of chirality)
Substrate3° > 2° » 1° (never)
NucleophileWeak nucleophiles OK
SolventPolar protic (stabilizes ions)
RearrangementPossible (carbocation can rearrange)

Why racemization?

  • Carbocation is planar (sp²)
  • Nucleophile attacks from both sides equally
  • 50% inversion + 50% retention = racemic mixture

Substrate reactivity:

$$\boxed{3° > 2° >> 1° \text{ (never)}}$$

Reason: Stability of carbocation intermediate

Solvent: Polar protic (H₂O, ROH)

  • Stabilizes carbocation and leaving group
  • Doesn’t need to stabilize nucleophile

SN2: Bimolecular Nucleophilic Substitution

“SN2” = Substitution, Nucleophilic, 2nd order

Mechanism:

One-step: Nucleophile attacks as leaving group departs (concerted)

$$Nu^- + R-X \rightarrow [Nu \cdots R \cdots X]^{\ddagger} \rightarrow Nu-R + X^-$$

Example: CH₃Br + OH⁻

HO⁻ + CH₃-Br → [HO···CH₃···Br]⁻ → HO-CH₃ + Br⁻

Backside attack
Transition state (not intermediate!)
Inversion of configuration

Characteristics:

PropertySN2
RateRate = k[RX][Nu⁻] (2nd order)
MechanismOne-step (concerted)
CarbocationNo intermediate
Stereochemistry100% inversion (Walden inversion)
Substrate1° > 2° » 3° (never)
NucleophileStrong nucleophiles needed
SolventPolar aprotic (doesn’t solvate Nu⁻)
RearrangementNo (no carbocation)

Why inversion?

  • Backside attack (SN2 mechanism)
  • Nucleophile approaches from side opposite to leaving group
  • Like umbrella flipping in wind

Substrate reactivity:

$$\boxed{CH_3X > 1° > 2° >> 3° \text{ (never)}}$$

Reason: Steric hindrance - nucleophile needs access to carbon

Solvent: Polar aprotic (DMSO, DMF, acetone)

  • Doesn’t solvate nucleophile
  • Keeps Nu⁻ “naked” and reactive
JEE Comparison

SN1 vs SN2 - The Ultimate Comparison:

FactorSN1SN2
Best substrate3° (most stable carbocation)1° (least hindered)
Worst substrate1° (unstable carbocation)3° (too hindered)
StereochemistryRacemizationInversion
Rate depends on[RX] only[RX][Nu⁻]
Carbocation?Yes (can rearrange)No
SolventPolar protic (H₂O, EtOH)Polar aprotic (DMSO, DMF)

Trick: “1 is slow, 2 is low (hindrance)”

  • SN1 needs slow ionization, stable carbocation (3°)
  • SN2 needs low hindrance, easy access (1°)

This table is GOLD for JEE!

Electrophilic Substitution

Electrophile (E⁺): Electron-poor species, attacks electron-rich site.

Most important: Electrophilic Aromatic Substitution (EAS)

Mechanism of EAS (General)

Step 1: Generation of electrophile Step 2: Electrophile attacks benzene Step 3: Deprotonation restores aromaticity

Example: Nitration

Step 1: Electrophile generation
HNO₃ + H₂SO₄ → NO₂⁺ + HSO₄⁻ + H₂O
(Nitronium ion)

Step 2: Attack on benzene
C₆H₆ + NO₂⁺ → C₆H₆NO₂⁺ (carbocation, arenium ion)

Step 3: Deprotonation
C₆H₆NO₂⁺ → C₆H₅NO₂ + H⁺
(Nitrobenzene)

Common EAS Reactions:

ReactionElectrophileReagentProduct
HalogenationX⁺X₂/FeX₃C₆H₅X
NitrationNO₂⁺HNO₃/H₂SO₄C₆H₅NO₂
SulfonationSO₃H⁺H₂SO₄ (fuming)C₆H₅SO₃H
Friedel-Crafts AlkylationR⁺RCl/AlCl₃C₆H₅R
Friedel-Crafts AcylationRCO⁺RCOCl/AlCl₃C₆H₅COR

Addition Reactions

General: Two groups add across multiple bond (C=C or C≡C)

$$\boxed{C=C + X-Y \rightarrow X-C-C-Y}$$

Electrophilic Addition

Most common for alkenes and alkynes

Mechanism

Step 1: Electrophile attacks π-bond, forms carbocation Step 2: Nucleophile attacks carbocation

Example: CH₂=CH₂ + HBr

Step 1:
CH₂=CH₂ + H⁺ → CH₃-CH₂⁺
(More stable carbocation)

Step 2:
CH₃-CH₂⁺ + Br⁻ → CH₃-CH₂-Br

Markovnikov’s Rule

“Rich get richer” - H adds to carbon with MORE hydrogens.

$$\boxed{\text{H to more H, X to less H}}$$

Example: Propene + HCl

CH₃-CH=CH₂ + HCl

Could form:
CH₃-CHCl-CH₃  (2° carbocation, Markovnikov)  ← Major
CH₃-CH₂-CH₂Cl (1° carbocation)               ← Minor

Markovnikov product: CH₃-CHCl-CH₃

Reason: Electrophile adds to form more stable carbocation (2° > 1°)

Anti-Markovnikov Addition

With peroxides (free radical mechanism) - ONLY for HBr!

Example: Propene + HBr (peroxide)

CH₃-CH=CH₂ + HBr --ROOR--> CH₃-CH₂-CH₂-Br

Anti-Markovnikov product!

Mechanism:

Initiation:
ROOR → 2RO·
RO· + HBr → ROH + Br·

Propagation:
Br· + CH₃-CH=CH₂ → CH₃-CH·-CH₂-Br (2° radical, stable!)
CH₃-CH·-CH₂-Br + HBr → CH₃-CH₂-CH₂-Br + Br·

Why only HBr?

  • HCl: H-Cl too strong, won’t abstract
  • HI: H-I too weak, reaction reverses

Addition Reactions Summary

ReactionReagentProductType
HydrogenationH₂/Ni, Pt, PdAlkaneSyn addition
HalogenationX₂DihaloalkaneAnti addition
Hydrogen halideHXHaloalkaneMarkovnikov
HBr + peroxideHBr/ROORHaloalkaneAnti-Markovnikov
HydrationH₂O/H⁺AlcoholMarkovnikov
OxymercurationHg(OAc)₂/NaBH₄AlcoholMarkovnikov, no rearrangement
HydroborationBH₃/H₂O₂/OH⁻AlcoholAnti-Markovnikov

Elimination Reactions

General: Two groups leave, forming multiple bond (opposite of addition)

$$\boxed{X-C-C-Y \rightarrow C=C + X-Y}$$

Most common: Dehydrohalogenation (removing HX)

E1: Unimolecular Elimination

Similar to SN1 - goes through carbocation

Mechanism:

Step 1: Ionization (slow)

$$R-X \xrightarrow{slow} R^+ + X^-$$

Step 2: Deprotonation (fast)

$$R^+ + Base \xrightarrow{fast} Alkene + H^+$$

Example: tert-Butyl bromide + OH⁻ (heat)

Step 1:
(CH₃)₃C-Br → (CH₃)₃C⁺ + Br⁻

Step 2:
(CH₃)₃C⁺ → (CH₃)₂C=CH₂ + H⁺

Characteristics:

PropertyE1
RateRate = k[RX] (1st order)
MechanismTwo-step (carbocation)
Substrate3° > 2° » 1°
BaseWeak base OK
CarbocationYes (can rearrange)
ProductMixture (Zaitsev + Hofmann)

E2: Bimolecular Elimination

Similar to SN2 - concerted, one-step

Mechanism:

One-step: Base removes H as leaving group departs (anti-periplanar)

$$Base + H-C-C-X \rightarrow Base-H + C=C + X^-$$

Example: Ethyl bromide + KOH (alcohol, heat)

          H
          |
KOH + CH₃-CH-Br → CH₂=CH₂ + H₂O + KBr
       (Anti-periplanar geometry required)

Characteristics:

PropertyE2
RateRate = k[RX][Base] (2nd order)
MechanismOne-step (concerted)
Substrate3° > 2° > 1°
BaseStrong base needed
CarbocationNo intermediate
StereochemistryAnti-periplanar required
ProductZaitsev (more substituted)

Zaitsev’s Rule

“More substituted alkene is more stable” → Major product

$$\boxed{\text{Tetrasubstituted} > \text{Trisubstituted} > \text{Disubstituted} > \text{Monosubstituted}}$$

Example: 2-Bromobutane + KOH

    CH₃
     |
CH₃-CH-CH₂-CH₃ + KOH
     |
     Br

Could form:
CH₃-CH=CH-CH₃   (Trisubstituted) ← Zaitsev (Major, 80%)
CH₂=CH-CH₂-CH₃  (Disubstituted)  ← Hofmann (Minor, 20%)

Zaitsev product: More substituted, more stable (hyperconjugation!)

Hofmann Rule

With bulky bases (like (CH₃)₃CO⁻) → Less substituted alkene

Reason: Steric hindrance - base attacks less hindered H

Common JEE Mistake

SN vs E Competition:

When do you get substitution vs elimination?

ConditionsFavorsProduct
Strong nucleophile, 1°/2°SN2Substitution
Weak nucleophile, 3°SN1Substitution
Strong base, heat, 3°E2Elimination
Weak base, heat, 3°E1Elimination
Bulky baseE2Elimination (Hofmann)

Summary:

  • 1° substrate: SN2 (never E1 or SN1)
  • 3° substrate: E2 or E1 (never SN2)
  • Heat + strong base: Elimination
  • Good nucleophile, no heat: Substitution

This is the MOST important decision tree for mechanisms!


Rearrangement Reactions

Atoms/groups move within molecule to form more stable structure.

Types

1. Wagner-Meerwein Rearrangement

Carbocation rearrangement - hydride or alkyl shift

Example: Pinacol-Pinacolone Rearrangement

  CH₃   CH₃              CH₃   CH₃
   |     |                |     |
  C  -  C      H⁺        C  =  O
  |     |      →         |
 OH    OH               CH₃

Pinacol             Pinacolone

Mechanism:

  1. Protonation of OH
  2. Loss of H₂O → carbocation
  3. Methyl shift → more stable carbocation
  4. Deprotonation → ketone

2. Beckmann Rearrangement

Oxime → Amide (used in nylon production!)

R-C=N-OH  → R-NH-CO-R'
   |
   R'

3. Benzilic Acid Rearrangement

α-Diketone → α-Hydroxy acid


Free Radical Reactions

Chain mechanism: Initiation → Propagation → Termination

Halogenation of Alkanes

Example: CH₄ + Cl₂ –hν–> CH₃Cl + HCl

Mechanism:

Initiation:

$$Cl_2 \xrightarrow{hν} 2Cl \cdot$$

Propagation:

$$CH_4 + Cl \cdot \rightarrow CH_3 \cdot + HCl$$ $$CH_3 \cdot + Cl_2 \rightarrow CH_3Cl + Cl \cdot$$

Termination:

$$Cl \cdot + Cl \cdot \rightarrow Cl_2$$ $$CH_3 \cdot + Cl \cdot \rightarrow CH_3Cl$$ $$CH_3 \cdot + CH_3 \cdot \rightarrow C_2H_6$$

Reactivity: F₂ > Cl₂ > Br₂ > I₂

Selectivity: I₂ > Br₂ > Cl₂ > F₂ (opposite!)

Why?

  • F₂ too reactive → no selectivity
  • I₂ too slow → very selective

Selectivity in alkanes:

$$\boxed{3° > 2° > 1° \text{ (for radical formation)}}$$

Summary Table

ReactionSubstrateMechanismProductKey Feature
SN1Two-step, carbocationR-NuRacemization
SN2One-step, backsideR-NuInversion
E1Two-step, carbocationAlkeneZaitsev
E23°, 2°, 1°One-step, antiAlkeneZaitsev/Hofmann
AdditionAlkeneVia carbocationX-C-C-YMarkovnikov
Free radicalAlkaneChain mechanismVarious3° > 2° > 1°

Practice Problems

Level 1: Identification

  1. Identify the mechanism (SN1, SN2, E1, E2):

    • a) (CH₃)₃C-Br + OH⁻ (aqueous, room temp)
    • b) CH₃-Br + OH⁻ (acetone)
    • c) (CH₃)₃C-Br + (CH₃)₃CO⁻ (heat)
  2. Predict major product:

    • a) CH₃CH=CH₂ + HBr
    • b) CH₃CH=CH₂ + HBr (peroxide)
  3. Which gives faster SN2? CH₃Br, CH₃CH₂Br, (CH₃)₂CHBr, (CH₃)₃CBr

Level 2: Application

  1. Explain why:

    • SN2 doesn’t work with 3° substrates
    • E2 requires anti-periplanar geometry
    • Carbocation rearrangements occur in SN1 but not SN2
  2. Draw mechanism:

    • a) 2-Bromo-2-methylpropane + H₂O → tert-Butanol
    • b) Bromomethane + OH⁻ → Methanol
  3. Predict product with stereochemistry: (R)-2-Bromobutane + OH⁻ (SN2) → ?

Level 3: JEE Advanced

  1. Which reaction is fastest?

    • (a) (CH₃)₃C-Br + H₂O (SN1)
    • (b) CH₃-Br + OH⁻ (SN2)
    • (c) (CH₃)₂CH-Br + OH⁻ (SN2)
    • (d) Cannot compare (different mechanisms)
  2. What happens when (S)-2-bromobutane undergoes SN2 with CN⁻?

    • (a) (S)-2-cyanobutane
    • (b) (R)-2-cyanobutane
    • (c) Racemic mixture
    • (d) Achiral product
  3. Assertion (A): E2 elimination requires anti-periplanar geometry. Reason (R): This allows maximum orbital overlap during elimination.

    • (a) Both true, R explains A
    • (b) Both true, R doesn’t explain A
    • (c) A true, R false
    • (d) Both false
  4. In the reaction CH₃-CH(Br)-CH₂-CH₃ + KOH (alc., heat), major product is:

    • (a) CH₂=CH-CH₂-CH₃
    • (b) CH₃-CH=CH-CH₃
    • (c) CH₃-CH₂-CH=CH₂
    • (d) CH₃-CH₂-CH₂-CH₂-OH
Quick Check

Can you draw mechanisms for:

  1. SN1 of tert-butyl bromide + water
  2. SN2 of methyl bromide + OH⁻
  3. E2 of 2-bromopropane + KOH

Include all intermediates, transition states, and curved arrows!


Memory Tricks

“1 vs 2” - The Ultimate Rule

“1” reactions:

  • One molecule in rate equation
  • One step is slow (first step)
  • Best with (most stable carbocation)
  • Racemization (SN1) or Zaitsev (E1)

“2” reactions:

  • Two molecules in rate
  • Two species in transition state
  • Best with (least hindered)
  • Inversion (SN2) or anti geometry (E2)

SN vs E Decision Tree

Is substrate 1°?
├─ Yes → SN2 (good Nu⁻, no heat) or E2 (strong base, heat)
└─ No (3°) → SN1 (weak Nu⁻) or E1/E2 (heat, base)

Heat + Strong Base = Elimination
Good Nu⁻, No heat = Substitution

Interactive Demo: Visualize Reaction Mechanisms

Watch SN1, SN2, E1, and E2 mechanisms unfold with animated electron movement.

Markovnikov

“Rich Get Richer”

  • H adds to carbon with MORE H atoms
  • Forms more stable carbocation

Within Organic Principles

Halogen Compounds (Key Applications)

Hydrocarbon Reactions

Oxygen Compounds

Nitrogen Compounds

Foundation Topics