Binomial Theorem Formula Sheet
All key Binomial Theorem formulas — expansion, general & middle term, coefficient identities, multinomial theorem and approximations for JEE quick revision.
Every must-know Binomial Theorem result in one scannable place — expansion, general and middle term, coefficient identities, the multinomial theorem, and approximation formulas. Use this for last-minute JEE Main and Advanced revision.
The Binomial Theorem
For any positive integer $n$:
$$\boxed{(a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r}$$$$= \binom{n}{0}a^n + \binom{n}{1}a^{n-1}b + \binom{n}{2}a^{n-2}b^2 + \cdots + \binom{n}{n}b^n$$where the binomial coefficient is
$$\binom{n}{r} = {}^nC_r = \frac{n!}{r!(n-r)!}$$The expansion of $(a+b)^n$ has exactly $(n+1)$ terms, and in every term the sum of the powers of $a$ and $b$ equals $n$.
Standard forms
| Form | Expansion |
|---|---|
| $(1 + x)^n$ | $1 + nx + \dfrac{n(n-1)}{2!}x^2 + \dfrac{n(n-1)(n-2)}{3!}x^3 + \cdots + x^n$ |
| $(1 - x)^n$ | $1 - nx + \dfrac{n(n-1)}{2!}x^2 - \cdots + (-1)^n x^n$ |
| $(x + a)^n$ | $x^n + nx^{n-1}a + \dfrac{n(n-1)}{2!}x^{n-2}a^2 + \cdots + a^n$ |
For $(a - b)^n$, replace $b$ with $(-b)$ and include the sign before raising to the power. E.g. in $(x-2y)^5$, $T_3 = \binom{5}{2}x^3(-2y)^2 = 40x^3y^2$, not $\binom{5}{2}x^3(2y)^2$.
General Term & Term Finding
The general term — the $(r+1)^{\text{th}}$ term — of $(a+b)^n$:
$$\boxed{T_{r+1} = \binom{n}{r} a^{n-r} b^r}, \quad r = 0, 1, 2, \ldots, n$$| Expansion | General term $T_{r+1}$ |
|---|---|
| $(x + a)^n$ | $\binom{n}{r} x^{n-r} a^r$ |
| $(1 + x)^n$ | $\binom{n}{r} x^r$ |
| $(ax + b)^n$ | $\binom{n}{r} a^{n-r} b^r x^{n-r}$ |
| $\left(x + \tfrac{1}{x}\right)^n$ | $\binom{n}{r} x^{n-2r}$ |
Term number $= r + 1$. The 5th term means $T_5$, so $r = 4$. Term independent of $x$: set the net power of $x$ in $T_{r+1}$ to $0$ and solve for $r$. If $r$ is not a non-negative integer, that term (or coefficient) is $0$.
Term from the end
$$r^{\text{th}} \text{ term from the end} = (n - r + 2)^{\text{th}} \text{ term from the start}$$Middle Term(s)
| Case | Middle term(s) |
|---|---|
| $n$ even | one term: $T_{\frac{n}{2}+1}$ |
| $n$ odd | two terms: $T_{\frac{n+1}{2}}$ and $T_{\frac{n+3}{2}}$ |
For $n$ even:
$$\boxed{T_{\frac{n}{2}+1} = \binom{n}{n/2}\, a^{n/2} b^{n/2}}$$For $n$ odd:
$$\boxed{T_{\frac{n+1}{2}} = \binom{n}{(n-1)/2}\, a^{(n+1)/2} b^{(n-1)/2}}$$$$\boxed{T_{\frac{n+3}{2}} = \binom{n}{(n+1)/2}\, a^{(n-1)/2} b^{(n+1)/2}}$$Greatest coefficient: $\binom{n}{n/2}$ if $n$ is even; $\binom{n}{(n-1)/2} = \binom{n}{(n+1)/2}$ if $n$ is odd.
Greatest Term (Numerically)
For $(a + b)^n$, the numerically greatest term is $T_{r+1}$ where
$$\boxed{r = \left[\frac{(n+1)\,|b|}{|a| + |b|}\right]} \quad ([\,\cdot\,] = \text{greatest integer})$$Equivalently, $T_{r+1} > T_r$ as long as
$$\frac{(n - r + 1)\,|b|}{r\,|a|} > 1$$For $(1+x)^n$ with $x > 0$: if $\dfrac{(n+1)x}{1+x}$ is an integer $m$, then $T_m$ and $T_{m+1}$ are both greatest; otherwise $T_{[m]+1}$ is greatest.
Binomial Coefficient Properties
$$\binom{n}{0} = \binom{n}{n} = 1, \quad \binom{n}{1} = \binom{n}{n-1} = n$$| Identity | Formula |
|---|---|
| Symmetry | $\binom{n}{r} = \binom{n}{n-r}$ |
| Pascal’s identity | $\binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r}$ |
| Sum of consecutive | $\binom{n}{r} + \binom{n}{r+1} = \binom{n+1}{r+1}$ |
| Ratio of consecutive | $\dfrac{\binom{n}{r}}{\binom{n}{r-1}} = \dfrac{n-r+1}{r}$ |
| Index relation | $r\binom{n}{r} = n\binom{n-1}{r-1}$ |
$\binom{10}{3} = \binom{10}{7}$, not $\binom{3}{10}$. And Pascal’s identity goes to the previous row: $\binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r}$ — never same-row neighbours.
Sum Identities (with $C_r = \binom{n}{r}$)
| Sum | Result |
|---|---|
| $C_0 + C_1 + C_2 + \cdots + C_n$ | $2^n$ |
| $C_0 - C_1 + C_2 - \cdots + (-1)^n C_n$ | $0$ |
| $C_0 + C_2 + C_4 + \cdots$ | $2^{n-1}$ |
| $C_1 + C_3 + C_5 + \cdots$ | $2^{n-1}$ |
| $C_1 + 2C_2 + 3C_3 + \cdots + nC_n = \sum r\,C_r$ | $n\cdot 2^{n-1}$ |
| $\sum_{r=0}^{n} r^2 \binom{n}{r}$ | $n(n+1)\,2^{n-2}$ |
| $C_0^2 + C_1^2 + \cdots + C_n^2 = \sum \binom{n}{r}^2$ | $\binom{2n}{n}$ |
Headline results:
$$\boxed{\sum_{r=0}^{n}\binom{n}{r} = 2^n} \qquad \boxed{\sum_{r=0}^{n}\binom{n}{r}^2 = \binom{2n}{n}}$$$$\boxed{\sum_{r=0}^{n} r\binom{n}{r} = n\cdot 2^{n-1}}$$Vandermonde’s identity
$$\boxed{\sum_{r=0}^{k} \binom{m}{r}\binom{n}{k-r} = \binom{m+n}{k}}$$Integration / differentiation results
$$\sum_{r=0}^{n} \frac{\binom{n}{r}}{r+1} = \frac{2^{n+1} - 1}{n+1}$$$$\sum_{r=0}^{n}(-1)^r\binom{n}{r}^2 = \begin{cases} 0 & n \text{ odd} \\ (-1)^{n/2}\binom{n}{n/2} & n \text{ even} \end{cases}$$Put $x = 1$ in $(1+x)^n$ for the total $2^n$; put $x = -1$ for the alternating sum $0$. For weighted sums ($\sum rC_r$, $\sum r^2 C_r$) differentiate $(1+x)^n$ then put $x=1$; for $\sum \frac{C_r}{r+1}$ integrate from $0$ to $1$.
Multinomial Theorem
For a positive integer $n$ and $k$ variables:
$$\boxed{(x_1 + x_2 + \cdots + x_k)^n = \sum \frac{n!}{n_1!\, n_2! \cdots n_k!}\, x_1^{n_1} x_2^{n_2} \cdots x_k^{n_k}}$$where $n_1 + n_2 + \cdots + n_k = n$, all $n_i \ge 0$.
Multinomial coefficient:
$$\binom{n}{n_1, n_2, \ldots, n_k} = \frac{n!}{n_1!\, n_2! \cdots n_k!} = \binom{n}{n_1}\binom{n-n_1}{n_2}\binom{n-n_1-n_2}{n_3}\cdots$$Trinomial special case:
$$(a + b + c)^n = \sum_{p+q+r=n} \frac{n!}{p!\,q!\,r!}\, a^p b^q c^r$$| Quantity | Formula | Notes |
|---|---|---|
| Number of terms | $\binom{n+k-1}{k-1} = \binom{n+k-1}{n}$ | stars-and-bars; $\binom{n+2}{2}$ for trinomial |
| Sum of all coefficients | $k^n$ | put every variable $= 1$ |
| Greatest coefficient | powers as equal as possible | if $n = kq + r$: $r$ terms get power $q+1$, rest get $q$ |
Coefficient of $x^a y^b z^c$ in $(x+y+z)^n$ is $\dfrac{n!}{a!\,b!\,c!}$ — total factorial on top. It exists only if $a + b + c = n$; otherwise the coefficient is $0$.
Approximations (small $x$)
For $|x| < 1$ and any real $n$ (positive, negative, or fractional):
$$\boxed{(1 + x)^n = 1 + nx + \frac{n(n-1)}{2!}x^2 + \frac{n(n-1)(n-2)}{3!}x^3 + \cdots}$$- First order: $(1+x)^n \approx 1 + nx$
- Second order: $(1+x)^n \approx 1 + nx + \dfrac{n(n-1)}{2}x^2$
| Expression | Approximation (small $x$) |
|---|---|
| $(1 + x)^n$ | $1 + nx$ |
| $(1 - x)^n$ | $1 - nx$ |
| $\sqrt{1 + x}$ | $1 + \dfrac{x}{2}$ |
| $\sqrt[3]{1 + x}$ | $1 + \dfrac{x}{3}$ |
| $\dfrac{1}{1 + x}$ | $1 - x$ |
| $\dfrac{1}{\sqrt{1 + x}}$ | $1 - \dfrac{x}{2}$ |
| $\dfrac{1}{(1 + x)^2}$ | $1 - 2x$ |
Higher-order single-variable expansions used in JEE:
$$\sqrt{1+x} \approx 1 + \frac{x}{2} - \frac{x^2}{8}, \qquad \sqrt[3]{1+x} \approx 1 + \frac{x}{3} - \frac{x^2}{9}$$$$\frac{1}{1+x} = (1+x)^{-1} \approx 1 - x + x^2 - x^3 + \cdots$$Relative error when using $(1+x)^n \approx 1 + nx$:
$$\text{Relative error} \approx \frac{n(n-1)x^2}{2}$$Use $(1+x)^n \approx 1+nx$ only when $|x| \ll 1$ (typically $|x| < 0.1$). To apply it, first factor the base close to $1$: e.g. $(2.03)^5 = 2^5\left(1 + \tfrac{0.03}{2}\right)^5$ and $\sqrt{99} = 10\left(1 - \tfrac{1}{100}\right)^{1/2}$.
Pascal’s Triangle
Each entry is the sum of the two directly above it (Pascal’s identity), giving the binomial coefficients row by row.
graph TD
A["n=0: 1"] --> B["n=1: 1 1"]
B --> C["n=2: 1 2 1"]
C --> D["n=3: 1 3 3 1"]
D --> E["n=4: 1 4 6 4 1"]
E --> F["n=5: 1 5 10 10 5 1"]One-Glance Summary
| Quantity | Formula |
|---|---|
| Expansion | $(a+b)^n = \sum_{r=0}^{n}\binom{n}{r}a^{n-r}b^r$ |
| Number of terms | $n + 1$ |
| General term | $T_{r+1} = \binom{n}{r}a^{n-r}b^r$ |
| Middle term ($n$ even) | $T_{\frac{n}{2}+1}$ |
| Middle terms ($n$ odd) | $T_{\frac{n+1}{2}},\ T_{\frac{n+3}{2}}$ |
| Greatest term index | $r = \left[\dfrac{(n+1) |
| Symmetry | $\binom{n}{r} = \binom{n}{n-r}$ |
| Pascal’s identity | $\binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r}$ |
| Ratio | $\dfrac{\binom{n}{r}}{\binom{n}{r-1}} = \dfrac{n-r+1}{r}$ |
| $\sum C_r$ | $2^n$ |
| $\sum (-1)^r C_r$ | $0$ |
| Even = odd place sum | $2^{n-1}$ |
| $\sum r\,C_r$ | $n\,2^{n-1}$ |
| $\sum r^2 C_r$ | $n(n+1)2^{n-2}$ |
| $\sum C_r^2$ | $\binom{2n}{n}$ |
| Vandermonde | $\sum_r \binom{m}{r}\binom{n}{k-r} = \binom{m+n}{k}$ |
| Multinomial terms | $\binom{n+k-1}{k-1}$ |
| Multinomial coeff. sum | $k^n$ |
| Approximation | $(1+x)^n \approx 1 + nx,\ |