Permutations and Combinations

Master counting principles, permutations, combinations, and their applications for JEE Mathematics.

Permutations and Combinations deal with counting arrangements and selections. These concepts are fundamental to probability.

Overview

graph TD
    A[Counting] --> B[Fundamental Principle]
    A --> C[Permutations]
    A --> D[Combinations]
    C --> C1[With Repetition]
    C --> C2[Without Repetition]
    D --> D1[Selection]
    D --> D2[Distribution]

Fundamental Principle of Counting

Multiplication Principle

If one task can be done in $m$ ways and another in $n$ ways, then both tasks can be done in $m \times n$ ways.

Addition Principle

If one task can be done in $m$ ways OR another in $n$ ways (mutually exclusive), then either task can be done in $m + n$ ways.

Factorial

$$n! = n \times (n-1) \times (n-2) \times ... \times 2 \times 1$$

Special cases:

  • $0! = 1$
  • $1! = 1$

Properties:

  • $n! = n \times (n-1)!$
  • $(n+1)! = (n+1) \times n!$

Permutations

Definition: Arrangement of objects where order matters.

Without Repetition

Number of ways to arrange $r$ objects from $n$ distinct objects:

$$\boxed{^nP_r = \frac{n!}{(n-r)!}}$$

Special cases:

  • $^nP_n = n!$ (arrange all n objects)
  • $^nP_1 = n$
  • $^nP_0 = 1$

With Repetition

$$n^r$$

(each of r positions has n choices)

Circular Permutations

$$\boxed{(n-1)!}$$

If clockwise and anticlockwise are same (like necklace):

$$\frac{(n-1)!}{2}$$

Permutations with Repeated Objects

Arrangements of $n$ objects where $p$ are alike of one kind, $q$ alike of another:

$$\frac{n!}{p! \cdot q! \cdot ...}$$
JEE Tip
To arrange letters of “MISSISSIPPI”: Total = 11 letters, I appears 4 times, S appears 4 times, P appears 2 times. Answer = $\frac{11!}{4! \cdot 4! \cdot 2!}$

Combinations

Definition: Selection of objects where order doesn’t matter.

$$\boxed{^nC_r = \binom{n}{r} = \frac{n!}{r!(n-r)!}}$$

Properties

  1. $^nC_r = ^nC_{n-r}$ (symmetry)
  2. $^nC_0 = ^nC_n = 1$
  3. $^nC_1 = ^nC_{n-1} = n$
  4. $^nC_r + ^nC_{r-1} = ^{n+1}C_r$ (Pascal’s triangle)

Relation

$$^nP_r = ^nC_r \times r!$$

Important Results

Selection from Different Groups

To select $r$ objects from $n$ different objects where $p$ are of one kind, $q$ of another (all alike within kind):

Use coefficient of $x^r$ in:

$$(1 + x + x^2 + ... + x^p)(1 + x + x^2 + ... + x^q)...$$

Division into Groups

Equal groups (distinguishable):

$$\frac{n!}{(r!)^k}$$

where $n = kr$

Equal groups (indistinguishable):

$$\frac{n!}{(r!)^k \cdot k!}$$

Derangements

Number of ways to arrange $n$ objects so that no object is in its original position:

$$D_n = n!\left(1 - \frac{1}{1!} + \frac{1}{2!} - \frac{1}{3!} + ... + \frac{(-1)^n}{n!}\right)$$

Sum of All Numbers

Sum of all $n$-digit numbers formed using digits $d_1, d_2, ..., d_n$ (without repetition):

$$= (n-1)! \times (d_1 + d_2 + ... + d_n) \times \underbrace{111...1}_{n \text{ ones}}$$

Applications

Distribution of Objects

ObjectsBoxesFormula
DistinctDistinct$n^r$ (r objects, n boxes)
IdenticalDistinct$^{n+r-1}C_{r-1}$
DistinctIdenticalStirling numbers

Handshakes/Diagonals

Handshakes among n people: $^nC_2 = \frac{n(n-1)}{2}$

Diagonals in n-gon: $^nC_2 - n = \frac{n(n-3)}{2}$

Points and Lines

Lines from n points (no 3 collinear): $^nC_2$

Triangles from n points (no 3 collinear): $^nC_3$

Common Mistake
When some points are collinear, subtract the lines/triangles that would be formed by collinear points.

Practice Problems

  1. In how many ways can letters of “ARRANGE” be arranged?

  2. How many 4-digit numbers can be formed using digits 1, 2, 3, 4, 5 without repetition?

  3. In how many ways can 8 people be seated around a circular table?

  4. How many diagonals does a decagon have?

  5. In how many ways can 12 identical balls be distributed in 3 distinct boxes?

Quick Check
Why is $^nC_r = ^nC_{n-r}$? Give an intuitive explanation.

Further Reading