Mathematics Permutations and Combinations

Permutations and Combinations Formula Sheet

All key Permutations and Combinations formulas for JEE Main & Advanced quick revision: counting principles, nPr, nCr, circular permutations, distribution, and derangements.

6 min read Updated Jun 2026 #formula sheet#quick revision#jee-main

Every formula, key relation, and must-know result for Permutations and Combinations on one scannable page. Use it for last-minute JEE revision.

Fundamental Principle of Counting

PrincipleOperationWhen to useResult
Multiplication (AND)$\times$Sequential / simultaneous independent events$m \times n \times p \times \ldots$
Addition (OR)$+$Mutually exclusive choices$m + n + p + \ldots$
$$\boxed{\text{Total ways} = m \times n \times p \times \ldots \quad (\text{AND})}$$$$\boxed{\text{Total ways} = m + n + p + \ldots \quad (\text{OR})}$$
AND vs OR

“AND then” / “followed by” means multiply. “OR” / “alternatively” (mutually exclusive) means add. Most JEE problems combine both, e.g. (3 + 4) × 2.

Factorial

$$\boxed{n! = n \times (n-1) \times (n-2) \times \ldots \times 2 \times 1}$$
QuantityValue / PropertyNotes
$0!$$1$By definition; crucial for formulas
$1!$$1$
Recursive$n! = n \times (n-1)!$Also $(n+1)! = (n+1) \times n!$

Quick values: $2! = 2$, $3! = 6$, $4! = 24$, $5! = 120$, $6! = 720$, $7! = 5{,}040$, $10! = 3{,}628{,}800$.

Never expand fully

Simplify ratios by cancelling: $\dfrac{10!}{7!} = 10 \times 9 \times 8 = 720$. Do not compute the full factorials.

Permutations (order matters)

Core formulas

$$\boxed{^nP_r = \frac{n!}{(n-r)!} = n \times (n-1) \times \ldots \times (n-r+1)}$$
QuantityFormulaNotes
Arrange all $n$ distinct objects$n!$$^nP_n = n!$
Arrange $r$ from $n$ distinct$^nP_r = \dfrac{n!}{(n-r)!}$Order matters
$^nP_0$$1$Arrange nothing
$^nP_1$$n$
$^nP_r$ when $r > n$$0$Cannot select more than available
With repetition allowed$n^r$$r$ positions, $n$ choices each

Properties

$$\boxed{^nP_r = n \times {}^{n-1}P_{r-1}} \qquad \boxed{\frac{^nP_r}{^nP_{r-1}} = n - r + 1}$$$$\boxed{^nP_r = {}^nC_r \times r!}$$

Permutations with Repeated (Identical) Objects

For $n$ objects where $p$ are alike of one kind, $q$ alike of another, $r$ alike of another, …:

$$\boxed{\frac{n!}{p! \cdot q! \cdot r! \cdot \ldots}}$$
Special caseResult
All objects distinct ($p=q=\ldots=1$)$n!$
All $n$ objects identical$1$
Count every letter

Include letters that appear once (divide by $1!$). MISSISSIPPI: M(1), I(4), S(4), P(2) gives $\dfrac{11!}{1!\,4!\,4!\,2!} = 34{,}650$. More repetition means fewer distinct arrangements.

Circular Permutations

TypeCan flip?Formula
Circular (round table, fixed orientation)No$(n-1)!$
Necklace / garland (reflection allowed)Yes$\dfrac{(n-1)!}{2}$
$$\boxed{\text{Circular} = (n-1)!} \qquad \boxed{\text{Necklace} = \frac{(n-1)!}{2}}$$

Derivation: $n$ linear arrangements ($n!$) collapse to one under rotation, so $\dfrac{n!}{n} = (n-1)!$.

Divide by 2 only for flippable objects

Necklaces, garlands and bracelets can be flipped, so divide by 2. Round tables, circular races and clocks have a fixed orientation, so do not divide by 2. For restrictions in a circle, bundle objects then apply $(n-1)!$ to the units (e.g. A, B together: $(n-2)! \times 2!$ for $n$ people total counted as units).

Combinations (order does not matter)

Core formula

$$\boxed{^nC_r = \binom{n}{r} = \frac{n!}{r!\,(n-r)!}} \qquad \boxed{^nC_r = \frac{^nP_r}{r!}}$$

Properties

PropertyStatement
Symmetry$^nC_r = {}^nC_{n-r}$
Pascal’s rule$^nC_r + {}^nC_{r-1} = {}^{n+1}C_r$
Sum of all$^nC_0 + {}^nC_1 + \ldots + {}^nC_n = 2^n$
End values$^nC_0 = {}^nC_n = 1$
Linear values$^nC_1 = {}^nC_{n-1} = n$
Quick $^nC_2$$\dfrac{n(n-1)}{2}$
Quick $^nC_3$$\dfrac{n(n-1)(n-2)}{6}$
$$\boxed{^nC_r = {}^nC_{n-r}} \qquad \boxed{{}^nC_r + {}^nC_{r-1} = {}^{n+1}C_r} \qquad \boxed{\sum_{r=0}^{n} {}^nC_r = 2^n}$$

Maximum value of $^nC_r$: at $r = n/2$ if $n$ even; at $r = \frac{n-1}{2}$ and $\frac{n+1}{2}$ (equal) if $n$ odd.

Select vs arrange

“Committee / team / group / choose” means combination. “Arrange / order / rank / podium” means permutation. If $r > n/2$, compute $^nC_{n-r}$ instead — e.g. $^{50}C_{48} = {}^{50}C_2 = 1{,}225$.

Distribution and Division

Distribution of identical objects to distinct recipients (stars and bars)

ConstraintFormula
Each gets $\ge 0$ (no restriction)$^{n+r-1}C_{r-1} = {}^{n+r-1}C_n$
Each gets $\ge 1$$^{n-1}C_{r-1}$
$$\boxed{^{n+r-1}C_{r-1}} \qquad \boxed{^{n-1}C_{r-1}}$$

Equivalent to non-negative (or positive) integer solutions of $x_1 + x_2 + \ldots + x_r = n$.

Distribution of distinct objects to distinct recipients

ConstraintFormula
No restriction$r^n$
Each gets $\ge 1$ (inclusion–exclusion)$r^n - {}^rC_1 (r-1)^n + {}^rC_2 (r-2)^n - \ldots$
$$\boxed{r^n} \qquad \boxed{r^n - {}^rC_1(r-1)^n + {}^rC_2(r-2)^n - \ldots}$$

The “each $\ge 1$” count also equals $r! \cdot S(n,r)$, where $S(n,r)$ is the Stirling number of the second kind.

Division into groups

SituationFormula
Into distinct groups of sizes $n_1, n_2, \ldots, n_k$ (multinomial)$\dfrac{n!}{n_1!\,n_2!\,\ldots\,n_k!}$
Into $k$ identical groups of equal size $m$ ($n = km$)$\dfrac{n!}{(m!)^k \cdot k!}$
$$\boxed{\frac{n!}{n_1!\,n_2!\,\ldots\,n_k!}} \qquad \boxed{\frac{n!}{(m!)^k \cdot k!}}$$
Identical objects vs identical groups

Identical objects to distinct recipients uses stars and bars. Dividing distinct objects into identical groups of the same size divides the multinomial by $k!$ — but only for groups that share a size; groups of different sizes are already distinguishable.

Selection of non-consecutive items

ArrangementSelect $r$ non-consecutive from $n$
In a line$^{n-r+1}C_r$
In a circle ($n \ge 2r$)$\dfrac{n}{n-r}\,{}^{n-r}C_r$
$$\boxed{\text{Line: } {}^{n-r+1}C_r} \qquad \boxed{\text{Circle: } \frac{n}{n-r}\,{}^{n-r}C_r}$$

Geometry of Points and Polygons

QuantityFormula
Handshakes among $n$ people$^nC_2 = \dfrac{n(n-1)}{2}$
Lines from $n$ points (no 3 collinear)$^nC_2$
Triangles from $n$ points (no 3 collinear)$^nC_3$
Diagonals of an $n$-gon$^nC_2 - n = \dfrac{n(n-3)}{2}$
$$\boxed{\text{Diagonals} = \frac{n(n-3)}{2}}$$
Collinear points

When some points are collinear, subtract the lines or triangles those collinear points would otherwise form.

Sum of Numbers Formed

Sum of all $n$-digit numbers formed using digits $d_1, d_2, \ldots, d_n$ (without repetition):

$$\boxed{(n-1)! \times (d_1 + d_2 + \ldots + d_n) \times \underbrace{111\ldots1}_{n \text{ ones}}}$$

Derangements (no element in its original position)

$$\boxed{D_n = n!\left(1 - \frac{1}{1!} + \frac{1}{2!} - \frac{1}{3!} + \ldots + \frac{(-1)^n}{n!}\right) = n!\sum_{i=0}^{n}\frac{(-1)^i}{i!}}$$
RelationFormula
Recursive$D_n = (n-1)(D_{n-1} + D_{n-2})$
Single-step recurrence$D_n = nD_{n-1} + (-1)^n$
Approximation ($n \ge 7$)$D_n \approx \dfrac{n!}{e}$
Derangement probability$\dfrac{D_n}{n!} \approx \dfrac{1}{e} \approx 0.368$
Exactly $k$ in correct position$^nC_k \cdot D_{n-k}$
Identity$\sum_{k=0}^{n} {}^nC_k \cdot D_k = n!$
$$\boxed{D_n = (n-1)(D_{n-1} + D_{n-2})} \qquad \boxed{D_n = nD_{n-1} + (-1)^n}$$

First values: $D_0 = 1$, $D_1 = 0$, $D_2 = 1$, $D_3 = 2$, $D_4 = 9$, $D_5 = 44$, $D_6 = 265$, $D_7 = 1{,}854$.

The 1/e result

About 37% of random permutations have no fixed point, and this stays near $1/e$ for all $n \ge 7$. For small $n$ use the recursion $D_n = (n-1)(D_{n-1}+D_{n-2})$.

Master Comparison: nPr vs nCr

AspectPermutation $^nP_r$Combination $^nC_r$
OrderMattersDoes not matter
Formula$\dfrac{n!}{(n-r)!}$$\dfrac{n!}{r!\,(n-r)!}$
ABC vs BACDifferentSame
KeywordsArrange, rank, podiumSelect, choose, committee
Relation$^nP_r = {}^nC_r \times r!$$^nC_r = \dfrac{^nP_r}{r!}$

Quick Revision Map

graph TD
    A[Counting] --> B[Fundamental Principle: AND multiply / OR add]
    A --> C[Permutations: order matters]
    A --> D[Combinations: order does not matter]
    C --> C1["Distinct: nPr = n!/(n-r)!"]
    C --> C2["Repetition: n!/p!q!r!"]
    C --> C3["Circular: (n-1)! ; necklace (n-1)!/2"]
    D --> D1["Select: nCr = n!/(r!(n-r)!)"]
    D --> D2["Distribute: stars & bars, multinomial"]
    D --> D3["Derangements: Dn = n! sum (-1)^i/i!"]

Key Takeaways

  • AND means multiply, OR means add; check for restrictions before counting.
  • Order matters means $^nP_r$; order does not matter means $^nC_r$, related by $^nP_r = {}^nC_r \times r!$.
  • Identical objects reduce arrangements: divide $n!$ by the factorials of repetitions.
  • Circular: fix one object so $(n-1)!$; divide by 2 only for flippable necklaces and garlands.
  • Stars and bars for identical objects to distinct boxes; multinomial for division into groups; divide by $k!$ for identical equal-sized groups.
  • Derangement probability $\approx 1/e \approx 0.368$; memorize $D_2=1, D_3=2, D_4=9, D_5=44$.