Nuclear Reactions: Unleashing the Atom’s Power
The Trinity Test and Beyond 🎬
“Now I am become Death, the destroyer of worlds.” - J. Robert Oppenheimer, July 16, 1945
When the first atomic bomb detonated in the New Mexico desert, it proved Einstein’s E=mc² wasn’t just theory - it was the most powerful force humans had ever harnessed. From weapons to power plants to stars, nuclear reactions shape our universe.
What is a Nuclear Reaction?
Transformation of nuclei through collisions or decay.
Key Differences from Chemical Reactions
| Property | Chemical | Nuclear |
|---|---|---|
| Involves | Electrons | Nucleus |
| Energy | eV scale | MeV scale (million times more!) |
| Elements | Same before/after | Can transmute |
| Mass change | Negligible | Measurable (ΔE=mc²) |
| Rate factors | Temperature, catalyst | Independent of chemistry |
Conservation Laws
In all nuclear reactions:
:::box Conservation Rules
- Mass-Energy: Total mass-energy conserved (E=mc²)
- Charge: Total charge conserved (Z conserved)
- Nucleon number: Total nucleons conserved (A conserved)
- Momentum: Total momentum conserved
- Angular momentum: Total spin conserved :::
Example: $^7_3Li + ^1_1H → 2(^4_2He)$
Check:
- A: 7 + 1 = 4 + 4 ✓
- Z: 3 + 1 = 2 + 2 ✓
- Charge: 3 + 1 = 2 + 2 ✓
Q-Value (Energy Release)
Energy released (or absorbed) in nuclear reaction:
:::box Q-Value Formula
$$Q = (M_{reactants} - M_{products}) × c^2$$or in atomic mass units:
$$Q = Δm × 931.5 \text{ MeV}$$where Δm = (mass of reactants) - (mass of products)
Sign Convention:
- Q > 0 → Exothermic (energy released)
- Q < 0 → Endothermic (energy absorbed) :::
Alternative Formulation
$$Q = BE_{products} - BE_{reactants}$$(Energy released = increase in binding energy)
Types of Nuclear Reactions
1. Transmutation (Artificial)
First artificial transmutation (Rutherford, 1919):
$$^{14}_7N + ^4_2He → ^{17}_8O + ^1_1H$$Or in shorthand: $^{14}N(α,p)^{17}O$
General notation: $X(a,b)Y$
- X = target nucleus
- a = projectile
- b = ejected particle
- Y = product nucleus
2. Nuclear Fission
Heavy nucleus splits into lighter fragments
$$^{235}_{92}U + n → \text{Fragments} + \text{neutrons} + \text{energy}$$Typical fission:
$$^{235}U + n → ^{144}Ba + ^{89}Kr + 3n + 200 \text{ MeV}$$3. Nuclear Fusion
Light nuclei combine to form heavier
$$^2_1H + ^3_1H → ^4_2He + n + 17.6 \text{ MeV}$$Powers the Sun and stars!
Nuclear Fission: Splitting the Atom
Discovery (1938)
- Otto Hahn & Fritz Strassmann: Chemical evidence
- Lise Meitner & Otto Frisch: Physical explanation
- Realized U-235 splits when hit by neutron
The Process
Neutron
↓
²³⁵U ←──●──→ Excited ²³⁶U*
↓
Unstable!
↓
╱ ╲
Fragment1 Fragment2
+ +
2-3 neutrons Energy
Typical Fission Equation
$$^{235}_{92}U + ^1_0n → ^{236}_{92}U^* → ^A_{Z_1}X + ^{A'}_{Z_2}Y + 2-3n + Q$$where A + A’ ≈ 236
Common fragments:
- Mass ~95 (e.g., ⁹⁵Sr, ⁹⁵Y)
- Mass ~140 (e.g., ¹⁴⁰Ba, ¹⁴⁰Xe)
Energy Release
~200 MeV per fission distributed as:
| Component | Energy (MeV) | % |
|---|---|---|
| Kinetic energy of fragments | 165 | 82.5 |
| Neutron kinetic energy | 5 | 2.5 |
| Instant γ-rays | 7 | 3.5 |
| β-particles (delayed) | 8 | 4.0 |
| γ-rays (delayed) | 7 | 3.5 |
| Neutrinos (lost) | 8 | 4.0 |
| Total | 200 | 100 |
Chain Reaction
The Concept
1 neutron
↓
══●══ U-235
↙ ↓ ↘
n n n (3 neutrons released)
↓ ↓ ↓
● ● ● (3 more fissions)
↓ ↓ ↓
... ... ... (9 neutrons, then 27, 81, ...)
Self-sustaining if each fission causes ≥1 more fission!
Neutron Multiplication Factor (k)
:::box
$$k = \frac{\text{Number of neutrons in generation n+1}}{\text{Number of neutrons in generation n}}$$Three regimes:
- k < 1: Subcritical (reaction dies out)
- k = 1: Critical (steady state)
- k > 1: Supercritical (exponential growth) :::
Critical Mass
Minimum mass needed for sustained chain reaction.
For ²³⁵U sphere: ~52 kg (bare), ~15 kg (with reflector) For ²³⁹Pu sphere: ~10 kg (bare), ~5 kg (with reflector)
Depends on:
- Shape (sphere is optimal)
- Purity
- Neutron reflector
- Moderator
Fissile vs Fertile Materials
Fissile (Can fission with slow neutrons)
| Isotope | Natural? | Critical Mass |
|---|---|---|
| ²³³U | No (made from Th) | ~15 kg |
| ²³⁵U | Yes (0.7% in U) | ~52 kg |
| ²³⁹Pu | No (made from U) | ~10 kg |
Fertile (Can become fissile)
| Isotope | Converts to |
|---|---|
| ²³²Th | ²³³U (fissile) |
| ²³⁸U | ²³⁹Pu (fissile) |
Breeding reaction:
$$^{238}U + n → ^{239}U → ^{239}Np + β^- → ^{239}Pu + β^-$$Nuclear Reactor
Basic Components
flowchart TB
subgraph CORE["REACTOR CORE"]
F["Fuel Rods
(²³⁵U or ²³⁹Pu)"]
M["Moderator
(H₂O, D₂O, C)"]
CR["Control Rods
(Cd, B)"]
C["Coolant
(H₂O, CO₂, Na)"]
F --> M
M --> CR
CR --> C
end
ADJ["Adjust k"] -.-> CR
C -->|Heat| ST["Steam Turbine"]
ST --> E["Electricity"]Functions
Fuel: Provides fissile material (²³⁵U ~3-5% enrichment)
Moderator: Slows down neutrons
- Fast neutrons (2 MeV) → Slow neutrons (0.025 eV)
- Increases fission probability
- Materials: H₂O, D₂O, graphite (C)
Control Rods: Absorb neutrons to control k
- Cadmium, boron, hafnium
- Insert deeper → more neutrons absorbed → k↓
Coolant: Removes heat
- Water, heavy water, liquid sodium
- Heat → steam → turbine → electricity
Shielding: Protects from radiation
- Concrete, lead
Nuclear Fusion: Power of the Stars
Why Fusion?
BE/A curve:
╱■╲
╱ ╲
╱ ╲
Light → Heavy = CLIMB UP = Energy OUT!
Combining light nuclei increases BE/A → releases energy!
Stellar Fusion (The Sun)
Proton-Proton Chain:
$$4(^1_1H) → ^4_2He + 2e^+ + 2ν_e + 26.7 \text{ MeV}$$Detailed steps:
- $p + p → ^2H + e^+ + ν_e$ (slow!)
- $^2H + p → ^3He + γ$
- $^3He + ^3He → ^4He + 2p$
CNO Cycle (in massive stars): Uses C, N, O as catalysts.
Fusion Reactions (Laboratory/Weapons)
:::box D-T Reaction (easiest to achieve):
$$^2_1H + ^3_1H → ^4_2He (3.5 \text{ MeV}) + n (14.1 \text{ MeV})$$Total: 17.6 MeV
D-D Reactions:
$$^2H + ^2H → ^3He (0.82 \text{ MeV}) + n (2.45 \text{ MeV})$$ $$^2H + ^2H → ^3H (1.01 \text{ MeV}) + p (3.02 \text{ MeV})$$:::
Fusion Challenges
The Coulomb Barrier
Both nuclei are positive → repel!
$$E_{barrier} = \frac{kZ_1Z_2e^2}{r}$$For D+T at contact (~4 fm):
$$E_{barrier} ≈ 0.4 \text{ MeV}$$Classical: Need particles with KE > 0.4 MeV Temperature: $kT ≈ 0.4 \text{ MeV} → T ≈ 5 × 10^9 \text{ K}$! 🌡️
Quantum tunneling allows fusion at lower T: Sun’s core: 15 million K Lab fusion: 100-150 million K needed
Lawson Criterion
For net energy gain, need:
:::box
$$nτ > 10^{20} \text{ s/m}^3$$where:
- n = particle density
- τ = confinement time :::
Two approaches:
Magnetic confinement (Tokamak):
- Low density, long confinement
- ITER project
Inertial confinement (Laser):
- Very high density, short confinement
- NIF (National Ignition Facility)
Interactive Demo: Visualize Nuclear Reactions
Explore fission and fusion reactions, watching how nuclei split or combine to release energy.
Comparison: Fission vs Fusion
| Property | Fission | Fusion |
|---|---|---|
| Nuclei | Heavy → Light | Light → Heavy |
| Example | ²³⁵U → Ba + Kr | D + T → He |
| Energy/reaction | ~200 MeV | ~17.6 MeV |
| Energy/kg | ~10¹³ J | ~10¹⁴ J (10× more!) |
| Fuel | Uranium (limited) | Deuterium (abundant) |
| Waste | Radioactive (long-lived) | Minimal, short-lived |
| Control | Relatively easy | Very difficult |
| Status | Commercial power | Still experimental |
| Weapons | Atomic bomb | Hydrogen bomb |
| Temperature | Room temp OK | Millions of degrees! |
| Runaway | Meltdown risk | Reaction stops if containment fails |
Interactive Demo: Fusion vs Fission Calculator
const NuclearEnergyCalculator = () => {
const [reactionType, setReactionType] = useState('fission');
const [mass, setMass] = useState(1); // kg
// Energy values
const fissionEnergy = 200; // MeV per fission
const fusionEnergy = 17.6; // MeV per D-T fusion
const avogadro = 6.022e23;
let energyPerKg, totalEnergy, comparison;
if (reactionType === 'fission') {
// U-235 fission
const atomsPerKg = (mass * 1000 / 235) * avogadro;
const totalMeV = atomsPerKg * fissionEnergy;
energyPerKg = 8.2e13; // J/kg
totalEnergy = mass * energyPerKg;
comparison = totalEnergy / (mass * 4.6e6); // Compare to TNT
} else {
// D-T fusion (approximate as D-D for calculation)
const atomsPerKg = (mass * 1000 / 2.5) * avogadro; // Average mass
const totalMeV = atomsPerKg * fusionEnergy / 2; // Two atoms per fusion
energyPerKg = 3.4e14; // J/kg
totalEnergy = mass * energyPerKg;
comparison = totalEnergy / (mass * 4.6e6);
}
return (
<div>
<h3>Nuclear Energy Calculator</h3>
<label>Reaction Type:</label>
<select value={reactionType} onChange={(e) => setReactionType(e.target.value)}>
<option value="fission">Fission (U-235)</option>
<option value="fusion">Fusion (D-T)</option>
</select>
<label>Mass of fuel: {mass} kg</label>
<input
type="range"
min="0.1"
max="10"
step="0.1"
value={mass}
onChange={(e) => setMass(Number(e.target.value))}
/>
<div className="results">
<h4>Energy Output:</h4>
{reactionType === 'fission' ? (
<>
<p>Reaction: ²³⁵U → fragments + neutrons</p>
<p>Energy per fission: {fissionEnergy} MeV</p>
<p>Energy per kg: {(energyPerKg/1e13).toFixed(1)} × 10¹³ J</p>
</>
) : (
<>
<p>Reaction: ²H + ³H → ⁴He + n</p>
<p>Energy per fusion: {fusionEnergy} MeV</p>
<p>Energy per kg: {(energyPerKg/1e14).toFixed(1)} × 10¹⁴ J</p>
</>
)}
<p style={{fontSize: '1.2em', color: 'green'}}>
Total Energy: {totalEnergy.toExponential(2)} J
</p>
<h4>Comparisons:</h4>
<p>Equivalent to {comparison.toFixed(0)} kg of TNT</p>
<p>Could power a 100W bulb for {(totalEnergy/100/3600/24/365).toExponential(1)} years!</p>
{reactionType === 'fusion' && (
<p style={{color: 'blue'}}>
Fusion releases {(energyPerKg/8.2e13).toFixed(0)}× more energy per kg than fission!
</p>
)}
<h4>Environmental Note:</h4>
{reactionType === 'fission' ? (
<p>⚠ Produces long-lived radioactive waste</p>
) : (
<p>✓ Clean energy, minimal radioactive waste</p>
)}
</div>
</div>
);
};
Memory Tricks 🧠
“FISSION vs FUSION”
FISSION: Fragments formed Is currently used (power plants) Splits heavy nuclei Slow neutrons needed Is established technology Older discovery (1938) Nuclear waste problem
FUSION: Fuses light nuclei Ultra-high temperature Sun’s energy source In development (ITER) Ocean has fuel (deuterium) No long-lived waste
Chain Reaction Memory
1
╱│╲
2 2 2 → k=2 (supercritical)
1
│ → k=1 (critical)
1
1
╱ → k<1 (dies out)
0.5
Energy Order of Magnitude
- Chemical: 1 eV per reaction
- Fission: 200 MeV per reaction (200 million times!)
- Fusion: 20 MeV per reaction
“Millions more from nuclear than chemical!”
Common Mistakes ⚠️
❌ Mistake 1: Energy comparison
Wrong: “Fission releases more energy than fusion” Right: Per kg, fusion releases ~10× more; per reaction, fission ~10× more
❌ Mistake 2: Q-value sign
Wrong: Q negative for energy release Right: Q positive for energy release (products lighter)
❌ Mistake 3: Critical mass
Wrong: “Any amount of U-235 will explode” Right: Need critical mass for chain reaction
❌ Mistake 4: Fusion fuel
Wrong: “Fusion uses uranium” Right: Fusion uses hydrogen isotopes (D, T)
❌ Mistake 5: Conservation laws
Wrong: Forgetting to conserve both A and Z Right: Check both before and after!
Important Numerical Values
Fission
| Quantity | Value |
|---|---|
| Energy per U-235 fission | ~200 MeV |
| Energy per kg U-235 | 8.2 × 10¹³ J |
| Critical mass U-235 (bare sphere) | ~52 kg |
| Neutrons per fission | 2-3 (average 2.5) |
Fusion
| Reaction | Q-value (MeV) |
|---|---|
| D + T → He + n | 17.6 |
| D + D → He-3 + n | 3.27 |
| D + D → T + p | 4.03 |
| p + p → D + e⁺ + ν | 0.42 |
Conversion Factors
| Energy | Equivalent |
|---|---|
| 1 kg matter (E=mc²) | 9 × 10¹⁶ J |
| 1 kg TNT | 4.6 × 10⁶ J |
| 1 kg U-235 fission | ~17 kilotons TNT |
| 1 kg D-T fusion | ~100 kilotons TNT |
Practice Problems
Level 1: JEE Main Basics
Q1. Complete the nuclear reaction: $^7_3Li + ^1_1H → 2X$. Find X.
Solution:
Conserve A: 7 + 1 = 2A → A = 4
Conserve Z: 3 + 1 = 2Z → Z = 2
X = ⁴₂He (alpha particle)
Reaction: ⁷₃Li + ¹₁H → 2(⁴₂He)
Q2. Calculate Q-value for above reaction. Given: m(Li-7) = 7.016 u, m(H-1) = 1.008 u, m(He-4) = 4.003 u
Solution:
Δm = [m(Li) + m(H)] - 2m(He)
Δm = [7.016 + 1.008] - 2(4.003)
Δm = 8.024 - 8.006 = 0.018 u
Q = Δm × 931.5 = 0.018 × 931.5
Q = 16.77 MeV (exothermic!)
Q3. If neutron multiplication factor k = 1.002, is the reactor subcritical, critical, or supercritical?
Solution:
k > 1 → Supercritical
Reaction growing exponentially!
(Need to insert control rods)
Level 2: JEE Main/Advanced
Q4. A nuclear reactor produces 1000 MW power. How many U-235 atoms fission per second? (Energy per fission = 200 MeV)
Solution:
Power = 1000 MW = 10⁹ W = 10⁹ J/s
Energy per fission = 200 MeV
= 200 × 1.6 × 10⁻¹³ J
= 3.2 × 10⁻¹¹ J
Fissions per second = Power / Energy per fission
= 10⁹ / (3.2 × 10⁻¹¹)
= 3.125 × 10¹⁹ fissions/s
Q5. Calculate the energy released in the fusion reaction: $^2_1H + ^2_1H → ^3_2He + ^1_0n$
Given: m(D) = 2.014 u, m(He-3) = 3.016 u, m(n) = 1.009 u
Solution:
Δm = 2m(D) - [m(He-3) + m(n)]
Δm = 2(2.014) - [3.016 + 1.009]
Δm = 4.028 - 4.025 = 0.003 u
Q = 0.003 × 931.5 = 2.79 MeV
Q6. In a chain reaction, each fission produces 2.5 neutrons on average. If 80% are lost, what is the multiplication factor?
Solution:
Neutrons produced per fission = 2.5
Neutrons lost = 80% of 2.5 = 2.0
Neutrons causing next fission = 0.5
k = 0.5/1 = 0.5
Subcritical! (k < 1)
Reaction will die out.
Level 3: JEE Advanced
Q7. Show that 1 kg of matter, if completely converted to energy, equals 21.5 kilotons of TNT.
Solution:
E = mc² = 1 kg × (3×10⁸ m/s)²
E = 9 × 10¹⁶ J
1 kg TNT = 4.6 × 10⁶ J
1 kiloton TNT = 4.6 × 10¹² J
Equivalent TNT = (9×10¹⁶) / (4.6×10¹²)
= 19,565 kilotons
≈ 21.5 kilotons ✓
(Hiroshima bomb was ~15 kt!)
Q8. A fusion reactor runs on D-T reaction. If it produces 1000 MW power with 30% efficiency, how much tritium is consumed per day?
Solution:
Thermal power needed = 1000/0.3 = 3333 MW
Energy per D-T fusion = 17.6 MeV = 2.82 × 10⁻¹² J
Fusions per second = (3.333×10⁹) / (2.82×10⁻¹²)
= 1.18 × 10²¹ /s
Each fusion consumes 1 tritium atom.
Tritium atoms per day = 1.18×10²¹ × 86400
= 1.02 × 10²⁶
Mass of tritium = (1.02×10²⁶ / 6.022×10²³) × 3 g
= 508 g ≈ 0.5 kg per day
(Very little fuel needed!)
Q9. A bare sphere of Pu-239 has critical mass 10 kg. If surrounded by neutron reflector that reduces neutron loss by 50%, what is new critical mass?
Solution:
Critical mass depends on neutron loss.
With reflector, neutrons reflected back
→ Less mass needed for criticality
Reduction in loss by 50% roughly means:
Critical mass reduces by ~50%
New critical mass ≈ 5 kg
(This is why bombs use reflectors/tampers!)
Q10. In Sun’s core, proton-proton chain converts 4p → He + 2e⁺ + 2ν + 26.7 MeV. If Sun radiates 3.8 × 10²⁶ W, how much mass is lost per second?
Solution:
Power = 3.8 × 10²⁶ W = 3.8 × 10²⁶ J/s
From E = mc²:
dm/dt = P/c² = (3.8×10²⁶) / (9×10¹⁶)
= 4.2 × 10⁹ kg/s
Sun loses 4.2 billion kg per second!
Yet Sun's mass = 2 × 10³⁰ kg
Lifetime ≈ 10¹⁰ years
Plenty of fuel left! ☀️
Applications
1. Nuclear Power Plants
Worldwide:
- ~450 reactors in 30 countries
- ~10% of world electricity
- France: 70% nuclear
- India: Growing nuclear program
Types:
- PWR (Pressurized Water Reactor)
- BWR (Boiling Water Reactor)
- PHWR (Pressurized Heavy Water Reactor - India)
- Fast Breeder Reactor
2. Nuclear Weapons
Fission bombs:
- Hiroshima (Little Boy): Gun-type U-235
- Nagasaki (Fat Man): Implosion Pu-239
- Yield: 15-20 kilotons
Fusion bombs (H-bombs):
- Fission primary triggers fusion
- Yield: Megatons (1000× more!)
- Largest: Tsar Bomba (50 megatons)
3. Medical Applications
- Cancer therapy: Proton beams, gamma knife
- Radioisotopes: Tc-99m for imaging
- Sterilization: Gamma rays
4. Space Exploration
- RTGs (Radioisotope Thermoelectric Generators)
- Voyager, Curiosity rover
- Pu-238 decay heat → electricity
5. Research
- Particle accelerators: Transmutation studies
- Neutron scattering: Material structure
- Radioactive tracers: Biological pathways
Future of Nuclear Energy
Generation IV Reactors
- Molten Salt Reactors: Liquid fuel
- High Temperature Gas Reactors: Efficiency
- Fast Reactors: Breed and burn waste
Fusion Power
ITER (International Thermonuclear Experimental Reactor):
- Under construction in France
- Goal: Q = 10 (10× more energy out than in)
- First plasma: ~2025
- Commercial fusion: 2050s?
Advantages:
- Abundant fuel (deuterium from seawater)
- No CO₂ emissions
- No long-lived waste
- Inherently safe (can’t run away)
Challenges:
- Extreme temperatures (10× hotter than Sun)
- Plasma confinement
- Materials that can withstand neutrons
- Still net energy negative
Cross-Links to Related Topics
- Binding Energy - Why fission & fusion release energy
- Radioactivity - Natural nuclear transformations
- Nuclear Structure - Composition and mass defect
- Mass-Energy Equivalence - E=mc² foundation
Quick Revision Checklist ✓
- Nuclear reaction: Nucleus transformation
- Conservation: A, Z, charge, energy, momentum
- Q-value: Q = Δm × 931.5 MeV
- Q > 0 → exothermic (energy released)
- Fission: Heavy → light fragments (~200 MeV)
- Fusion: Light → heavier (~17.6 MeV for D-T)
- Chain reaction: Self-sustaining if k ≥ 1
- Critical mass: Minimum for chain reaction
- Fissile: ²³³U, ²³⁵U, ²³⁹Pu
- Fertile: ²³²Th, ²³⁸U (become fissile)
- Moderator: Slows neutrons
- Control rods: Absorb neutrons
- Fusion needs high T (Coulomb barrier)
- Lawson criterion: nτ > 10²⁰ s/m³
Final Tips for JEE
- Conservation always: Check A and Z in every reaction
- Q-value mastery: Know Δm × 931.5 formula
- Sign convention: Q > 0 means energy OUT
- Fission vs fusion: Know which releases more per kg vs per reaction
- Critical mass: Understand k factor
- BE/A curve: Both fission and fusion climb toward Fe-56
- Practical values: Know ~200 MeV (fission), ~17.6 MeV (D-T fusion)
- Units: MeV for nuclear, J for macroscopic
- Applications: Reactors, bombs, Sun, medical
- Future: ITER, Generation IV, fusion power coming
Last updated: May 12, 2025 Previous: Radioactivity Congratulations! You’ve completed the Modern Physics series!
Complete Modern Physics Series
You’ve now mastered all major topics in Modern Physics:
Dual Nature of Radiation
Atoms and Nuclei
- Rutherford Model
- Bohr Model
- Hydrogen Spectrum
- Nuclear Structure
- Binding Energy
- Radioactivity
- Nuclear Reactions
You’re now ready to tackle any JEE Modern Physics problem! 🎯🚀