Physics Electromagnetic Waves

Electromagnetic Waves Formula Sheet

All key Electromagnetic Waves formulas: displacement current, Maxwell's equations, E-B relations, energy density, intensity, radiation pressure & the EM spectrum for JEE.

6 min read Updated Jun 2026 #formula sheet#quick revision#jee-main

Every must-know formula, relation, and constant for Electromagnetic Waves in one scannable sheet — built for last-minute JEE Main and Advanced revision.

Displacement Current

The headline formula Maxwell added to fix Ampere’s law for time-varying fields:

$$\boxed{I_d = \varepsilon_0 \frac{d\Phi_E}{dt}}$$
QuantityFormulaNotes
Displacement current$I_d = \varepsilon_0 \dfrac{d\Phi_E}{dt}$$\Phi_E = \int \vec{E} \cdot d\vec{A}$ = electric flux
Displacement current (uniform field)$I_d = \varepsilon_0 A \dfrac{dE}{dt}$$A$ = area of surface
Displacement current density$J_d = \varepsilon_0 \dfrac{dE}{dt}$Units A/m²
Conduction current$I_c = \dfrac{dq}{dt}$Real charge flow
Charging capacitor$I_d = I_c$Always equal in a charging/discharging capacitor

In a parallel-plate capacitor, the field is $E = \dfrac{\sigma}{\varepsilon_0} = \dfrac{q}{\varepsilon_0 A}$, giving $\dfrac{dE}{dt} = \dfrac{I_c}{\varepsilon_0 A}$, which forces $I_d = I_c$.

Ampere–Maxwell Law

$$\oint \vec{B} \cdot d\vec{l} = \mu_0(I_c + I_d) = \mu_0 I_c + \mu_0\varepsilon_0\frac{d\Phi_E}{dt}$$

Differential form:

$$\nabla \times \vec{B} = \mu_0 \vec{J} + \mu_0 \varepsilon_0 \frac{\partial \vec{E}}{\partial t}$$

Magnetic Field Inside a Charging Capacitor

For circular plates of radius $R$, at distance $r < R$ from the axis:

$$\boxed{B = \frac{\mu_0 \varepsilon_0\, r}{2}\frac{dE}{dt}}$$
  • $B \propto r$ (inside the capacitor); $B = 0$ at the centre.
High-Yield
For a square-plate capacitor (side $a$) carrying conduction current $I_0$, the displacement current through a small circular area of radius $r$ between the plates is $I_d = \dfrac{\pi r^2 I_0}{a^2}$ — it scales with the area fraction.

Maxwell’s Equations (Integral Form)

#LawEquation
1Gauss’s law$\oint \vec{E} \cdot d\vec{A} = \dfrac{Q_{enc}}{\varepsilon_0}$
2Gauss’s law (magnetism)$\oint \vec{B} \cdot d\vec{A} = 0$
3Faraday’s law$\oint \vec{E} \cdot d\vec{l} = -\dfrac{d\Phi_B}{dt}$
4Ampere–Maxwell law$\oint \vec{B} \cdot d\vec{l} = \mu_0 I_c + \mu_0 \varepsilon_0 \dfrac{d\Phi_E}{dt}$

Key symmetry: changing $\vec{B} \rightarrow \vec{E}$ (Faraday); changing $\vec{E} \rightarrow \vec{B}$ (Maxwell). This symmetry is what produces self-propagating EM waves.

Speed of EM Waves

$$\boxed{c = \frac{1}{\sqrt{\mu_0\varepsilon_0}} = 3 \times 10^8 \text{ m/s}}$$
QuantityFormulaNotes
Speed in vacuum$c = \dfrac{1}{\sqrt{\mu_0\varepsilon_0}}$Universal for all EM waves
Speed in medium$v = \dfrac{1}{\sqrt{\mu\varepsilon}} = \dfrac{c}{n}$$n$ = refractive index
Refractive index$n = \sqrt{\mu_r \varepsilon_r}$Non-magnetic media: $n \approx \sqrt{\varepsilon_r}$
Wave equation$\dfrac{\partial^2 \vec{E}}{\partial t^2} = c^2 \nabla^2 \vec{E}$Same form for $\vec{B}$

Sample medium speeds: water ($n \approx 1.33$) → $v \approx 2.25 \times 10^8$ m/s; glass ($n \approx 1.5$) → $v \approx 2 \times 10^8$ m/s.

Wave Structure: E and B Fields

For a plane wave travelling in the $+x$ direction:

$$\vec{E} = E_0 \sin(kx - \omega t)\,\hat{j}, \qquad \vec{B} = B_0 \sin(kx - \omega t)\,\hat{k}$$

Direction of propagation: $\hat{j} \times \hat{k} = \hat{i}$.

RelationFormulaNotes
Field ratio$\dfrac{E}{B} = \dfrac{E_0}{B_0} = c$$E$ and $B$ in phase
Wave number$k = \dfrac{2\pi}{\lambda}$
Angular frequency$\omega = 2\pi f$
Dispersion relation$\omega = ck$$c = \dfrac{\omega}{k}$
Wave relation$c = f\lambda$
$$\boxed{\frac{E}{B} = c}$$
Transverse & In-Phase
EM waves are transverse: $\vec{E} \perp \vec{B} \perp$ direction of propagation, and $\vec{E} \times \vec{B}$ points along the propagation direction. $\vec{E}$ and $\vec{B}$ reach their maxima and zeros at the same instant. Polarization is described by the $\vec{E}$-field direction. EM waves need no medium — they travel through vacuum at $c$.

Energy in EM Waves

Energy Density

QuantityFormula
Electric energy density$u_E = \dfrac{1}{2}\varepsilon_0 E^2$
Magnetic energy density$u_B = \dfrac{B^2}{2\mu_0}$
Total energy density$u = u_E + u_B = \varepsilon_0 E^2 = \dfrac{B^2}{\mu_0} = \dfrac{EB}{\mu_0 c}$
$$\boxed{u_E = u_B \implies u = 2u_E = 2u_B}$$

Energy is split equally between the electric and magnetic fields.

Intensity and Poynting Vector

QuantityFormulaNotes
Poynting vector$\vec{S} = \dfrac{1}{\mu_0}(\vec{E} \times \vec{B})$Energy flow per unit area per unit time
Instantaneous intensity$I = uc = \varepsilon_0 c E^2 = \dfrac{cB^2}{\mu_0} = \dfrac{EB}{\mu_0}$Units W/m²
Average intensity$\langle I \rangle = \dfrac{1}{2}\varepsilon_0 c E_0^2 = \dfrac{c B_0^2}{2\mu_0} = \dfrac{E_0 B_0}{2\mu_0}$$E_0, B_0$ = amplitudes
$$\boxed{\langle I \rangle = \frac{1}{2}\varepsilon_0 c E_0^2 = \frac{E_0 B_0}{2\mu_0}}$$
Don't Drop the ½
For sinusoidal waves the time-average introduces a factor of $\tfrac{1}{2}$: use $\langle I \rangle = \tfrac{1}{2}\varepsilon_0 c E_0^2$ with amplitudes, not the instantaneous $I = \varepsilon_0 c E^2$.

Inverse Square Law (Point Source)

$$I = \frac{P}{4\pi r^2}$$

Solar constant at Earth ($r = 1.5 \times 10^{11}$ m) ≈ 1350 W/m².

Momentum and Radiation Pressure

QuantityFormulaNotes
Momentum density$\vec{p} = \dfrac{\vec{S}}{c^2} = \dfrac{u}{c}\hat{n}$
Photon momentum$p = \dfrac{E}{c} = \dfrac{h}{\lambda}$EM waves carry momentum despite zero mass
Radiation pressure (absorption)$P_{abs} = \dfrac{I}{c} = u$Surface absorbs the wave
Radiation pressure (reflection)$P_{ref} = \dfrac{2I}{c} = 2u$Factor of 2 from momentum reversal
Force on surface$F = P \times A$$F = \dfrac{IA}{c}$ (abs.), $\dfrac{2IA}{c}$ (refl.)
$$\boxed{P_{abs} = \frac{I}{c}, \qquad P_{ref} = \frac{2I}{c}}$$
Common Trap
The factor of 2 in $P_{ref} = \dfrac{2I}{c}$ comes from the momentum change $\Delta p = p - (-p) = 2p$ on reflection. Forgetting it is the most common error in radiation-pressure problems.

Doppler Effect for EM Waves

$$f' = f\sqrt{\frac{c + v_r}{c - v_r}}$$

$v_r$ = radial velocity (positive if approaching). Used for astronomical redshift and radar speed detection.

Electromagnetic Spectrum

$$\boxed{c = f\lambda}, \qquad f = \frac{c}{\lambda}, \quad \lambda = \frac{c}{f}$$

Order from longest wavelength / lowest energy to shortest / highest:

graph LR
    A[Radio] --> B[Microwave] --> C[Infrared] --> D[Visible] --> E[Ultraviolet] --> F[X-rays] --> G[Gamma]
TypeWavelengthFrequencySource
Radio> 0.1 m< 3 GHzOscillating circuits, antennas
Microwave1 mm – 0.1 m3 GHz – 300 GHzMagnetron, klystron, Gunn diode
Infrared700 nm – 1 mm300 GHz – 4×10¹⁴ HzHot objects, molecular vibrations
Visible400 – 700 nm4×10¹⁴ – 7.5×10¹⁴ HzAtomic transitions (outer e⁻)
Ultraviolet10 – 400 nm7.5×10¹⁴ – 3×10¹⁶ HzSun, mercury lamps
X-rays0.01 – 10 nm3×10¹⁶ – 3×10¹⁹ HzInner-shell e⁻, X-ray tube
Gamma rays< 0.01 nm> 3×10¹⁹ HzNuclei, cosmic sources

Full span: frequency 10⁴ Hz (radio) → 10²² Hz (gamma); wavelength 10⁴ m → 10⁻¹⁴ m. All travel at $c$ in vacuum.

Order Mnemonics
Spectrum order: Radio → Microwave → Infrared → Visible → Ultraviolet → X-rays → Gamma (“Real Men In Vegas Usually X-ray Gorillas”). Visible: VIBGYOR — Violet (shortest λ, highest f) to Red (longest λ, lowest f). Ionizing: UV (partially), X-rays, and Gamma.

Visible Spectrum

ColorWavelength (nm)
Violet400–450 (highest frequency)
Indigo450–475
Blue475–495
Green495–570
Yellow570–590
Orange590–620
Red620–700 (lowest frequency)

Photon Energy and Momentum

QuantityFormulaNotes
Photon energy$E = hf = \dfrac{hc}{\lambda}$$h = 6.626 \times 10^{-34}$ J·s
Energy in eV$E(\text{eV}) = \dfrac{1240}{\lambda(\text{nm})}$Shortcut for visible/UV
Photon momentum$p = \dfrac{E}{c} = \dfrac{h}{\lambda}$
$$\boxed{E = hf = \frac{hc}{\lambda} \quad\Rightarrow\quad E(\text{eV}) = \frac{1240}{\lambda(\text{nm})}}$$

Quick values: red (620 nm) ≈ 2 eV; blue (450 nm) ≈ 2.76 eV; UV (300 nm) ≈ 4.13 eV; X-ray (1 nm) ≈ 1.24 keV.

Key Constants

ConstantValueNotes
Permittivity of free space$\varepsilon_0 = 8.85 \times 10^{-12}$ F/mAlso C²/(N·m²)
Permeability of free space$\mu_0 = 4\pi \times 10^{-7}$ T·m/A$\approx 1.26 \times 10^{-6}$; also H/m
Speed of light$c = 3 \times 10^8$ m/s$c = 1/\sqrt{\mu_0\varepsilon_0}$
Planck’s constant$h = 6.626 \times 10^{-34}$ J·s
Electron volt$1 \text{ eV} = 1.6 \times 10^{-19}$ J
Unit Gotchas
$1$ nm $= 10\,$Å (X-ray $1$ Å $= 0.1$ nm, not 1 nm). $B$ is numerically much smaller than $E$ since $B = E/c$. Intensity in W/m², energy density in J/m³, radiation pressure in Pa — don’t confuse them. Keep the exponent sign right: $\varepsilon_0 = 10^{-12}$, not $10^{12}$.