Dimensional Formulas

Master dimensional formulas of physical quantities for JEE Physics

Prerequisites

Before studying dimensional formulas, you should understand:

What Are Dimensions?

Dimensions of a physical quantity are the powers (exponents) to which the base quantities are raised to represent that quantity.

Real Life: Building a House
Think of dimensions like a recipe. Just as a cake recipe tells you how much flour, sugar, and eggs you need, dimensional formulas tell you how physical quantities are “made” from fundamental quantities like mass, length, and time.

The Seven Fundamental Dimensions

We use square brackets [ ] to denote dimensions:

Base QuantitySymbolDimension
MassM[M]
LengthL[L]
TimeT[T]
Electric CurrentI or A[I] or [A]
Temperatureθ or K[θ] or [K]
Amount of SubstanceN or mol[N] or [mol]
Luminous IntensityJ or cd[J] or [cd]
For JEE: Focus on MLT
Most JEE problems use only the first three: M (Mass), L (Length), and T (Time). Electrical quantities also use I (Current). Temperature θ appears in thermodynamics.

Dimensional Formula vs Unit

Don’t confuse these two concepts:

Physical QuantityUnitDimensional Formula
Velocitym/s[M⁰L¹T⁻¹] or [LT⁻¹]
Forcenewton (N)[MLT⁻²]
Energyjoule (J)[ML²T⁻²]
  • Unit = actual measurement standard (meter, kilogram, etc.)
  • Dimensional Formula = abstract relationship between base quantities

Writing Dimensional Formulas: Step-by-Step

Method 1: From Definition/Formula

Example: Velocity

$$v = \frac{\text{displacement}}{\text{time}} = \frac{L}{T}$$ $$\boxed{[v] = [L][T]^{-1} = [M^0 L^1 T^{-1}]}$$

Example: Force

$$F = ma = M \times \frac{L}{T^2}$$ $$\boxed{[F] = [M][L][T]^{-2} = [M^1 L^1 T^{-2}]}$$

Method 2: From SI Unit

Example: Pressure

Unit: Pascal (Pa) = N/m² = kg/(m·s²)

$$\boxed{[P] = \frac{[M]}{[L][T]^2} = [M^1 L^{-1} T^{-2}]}$$
Golden Rule

In dimensional formulas:

  • Powers can be positive, negative, or zero
  • Powers are always rational numbers
  • We write [M⁰L¹T⁻¹] or simply [LT⁻¹] (omitting M⁰)

Interactive Demo: Visualize Dimensional Formulas

See how physical quantities are composed from fundamental dimensions.

Comprehensive Dimensional Formula Table

1. Mechanical Quantities

Physical QuantitySymbolFormula/DefinitionDimensional FormulaSI Unit
Lengthl, d, r[L]m
Massm[M]kg
Timet[T]s
AreaA[L²]
VolumeV[L³]
Densityρm/V[ML⁻³]kg/m³
Velocityvs/t[LT⁻¹]m/s
Accelerationav/t[LT⁻²]m/s²
Momentumpmv[MLT⁻¹]kg·m/s
ForceFma[MLT⁻²]N
ImpulseJFt[MLT⁻¹]N·s
Work/EnergyW, EFs[ML²T⁻²]J
PowerPW/t[ML²T⁻³]W
PressurepF/A[ML⁻¹T⁻²]Pa
Angular velocityωθ/t[T⁻¹]rad/s
Angular accelerationαω/t[T⁻²]rad/s²
Moment of inertiaImr²[ML²]kg·m²
TorqueτFr[ML²T⁻²]N·m
Angular momentumL[ML²T⁻¹]kg·m²/s
Important Observation

Work, Energy, and Torque all have the same dimensions [ML²T⁻²], but:

  • Work and Energy have the same unit: joule (J)
  • Torque has unit: N·m (not joule!)

This is because torque is a vector product (r × F) while work is a scalar product (F · s).

2. Thermal Quantities

Physical QuantitySymbolDimensional FormulaSI Unit
TemperatureT, θ[K] or [θ]K
HeatQ[ML²T⁻²]J
Specific heats, c[L²T⁻²K⁻¹]J/(kg·K)
Latent heatL[L²T⁻²]J/kg
Thermal conductivityk[MLT⁻³K⁻¹]W/(m·K)
Stefan’s constantσ[MT⁻³K⁻⁴]W/(m²·K⁴)
Boltzmann constantk_B[ML²T⁻²K⁻¹]J/K
Gas constantR[ML²T⁻²K⁻¹mol⁻¹]J/(mol·K)

3. Electricity and Magnetism

Physical QuantitySymbolDimensional FormulaSI Unit
Chargeq, Q[IT] or [AT]C
CurrentI[I] or [A]A
Voltage/EMFV, ε[ML²T⁻³I⁻¹]V
ResistanceR[ML²T⁻³I⁻²]Ω
CapacitanceC[M⁻¹L⁻²T⁴I²]F
Electric fieldE[MLT⁻³I⁻¹]V/m or N/C
Magnetic fieldB[MT⁻²I⁻¹]T
Magnetic fluxΦ[ML²T⁻²I⁻¹]Wb
InductanceL[ML²T⁻²I⁻²]H
Permittivityε₀[M⁻¹L⁻³T⁴I²]F/m
Permeabilityμ₀[MLT⁻²I⁻²]H/m

4. Waves and Oscillations

Physical QuantitySymbolDimensional FormulaSI Unit
Frequencyf, ν[T⁻¹]Hz
Wavelengthλ[L]m
Wave velocityv[LT⁻¹]m/s
AmplitudeA[L]m
Time periodT[T]s
Spring constantk[MT⁻²]N/m
Surface tensionγ, σ[MT⁻²]N/m
Viscosityη[ML⁻¹T⁻¹]Pa·s

5. Modern Physics

Physical QuantitySymbolDimensional FormulaSI Unit
Planck’s constanth[ML²T⁻¹]J·s
Work functionφ[ML²T⁻²]J or eV
Radioactive decay constantλ[T⁻¹]s⁻¹
Half-lifet₁/₂[T]s

6. Special Constants

Physical QuantitySymbolDimensional FormulaSI Unit
Gravitational constantG[M⁻¹L³T⁻²]N·m²/kg²
Acceleration due to gravityg[LT⁻²]m/s²
Universal gas constantR[ML²T⁻²K⁻¹mol⁻¹]J/(mol·K)
Avogadro’s numberN_A[mol⁻¹]mol⁻¹

Dimensionless Quantities

Some quantities have no dimensions (all powers are zero):

QuantityTypeExample
Pure numbersCounting1, 2, π, e
Ratios of same quantitiesRelativeStrain = ΔL/L
AnglesTrigonometricθ, sin θ, cos θ, tan θ
Relative densityRatioρ_substance/ρ_water
Refractive indexRation = c/v
Coefficient of frictionRatioμ = F_friction/F_normal
Poisson’s ratioRatioσ = -lateral strain/longitudinal strain
Reynold’s numberDimensionless parameterRe = ρvL/η
$$\boxed{[\text{Dimensionless}] = [M^0 L^0 T^0] = [1]}$$
Common Mistake

Mistake: Thinking angles have dimensions because they’re measured in degrees or radians.

Fact: Angles are dimensionless! Radians are defined as arc length/radius = L/L = 1 (dimensionless).

Same for solid angle (steradians): area/radius² = L²/L² = 1.

Principle of Homogeneity of Dimensions

Fundamental Principle

In any correct physical equation, the dimensions of all terms on both sides must be the same.

This is called the Principle of Homogeneity.

Example: Checking Homogeneity

$$s = ut + \frac{1}{2}at^2$$

Check each term:

  • [s] = [L]
  • [ut] = [LT⁻¹][T] = [L] ✓
  • [½at²] = [LT⁻²][T²] = [L] ✓

All terms have dimension [L], so the equation is dimensionally correct.

Important
  • Only terms with same dimensions can be added or subtracted
  • Dimensionless constants (like ½, π, e) don’t affect dimensional analysis
  • Arguments of exponential, logarithmic, and trigonometric functions must be dimensionless

Memory Tricks

Trick 1: Power = Force × Velocity
$$[P] = [F][v] = [MLT^{-2}][LT^{-1}] = [ML^2T^{-3}]$$

Remember: “Power is Force times Velocity” → Powers add when multiplying!

Trick 2: Energy Family

All have [ML²T⁻²]:

  • Work
  • Energy (kinetic, potential, heat)
  • Torque
  • Moment of force

Memory: “WET Moments” = Work, Energy, Torque, Moments

Trick 3: Per Unit Area → Add L⁻²
  • Pressure = Force/Area → [MLT⁻²][L⁻²] = [ML⁻¹T⁻²]
  • Surface tension = Force/Length → [MLT⁻²][L⁻¹] = [MT⁻²]
  • Stress = Force/Area → [ML⁻¹T⁻²]

Practice Problems

Level 1: JEE Main Basics

Problem 1

Find the dimensional formula of kinetic energy using KE = ½mv².

Solution:

$$[KE] = [m][v]^2 = [M][LT^{-1}]^2$$ $$= [M][L^2T^{-2}]$$ $$= \boxed{[ML^2T^{-2}]}$$
Problem 2

What are the dimensions of universal gravitational constant G in the equation F = Gm₁m₂/r²?

Solution:

$$F = \frac{Gm_1m_2}{r^2}$$ $$G = \frac{Fr^2}{m_1m_2}$$ $$[G] = \frac{[MLT^{-2}][L^2]}{[M][M]} = \frac{[ML^3T^{-2}]}{[M^2]}$$ $$= \boxed{[M^{-1}L^3T^{-2}]}$$

Level 2: JEE Main/Advanced

Problem 3

Check if the equation $v^2 = u^2 + 2as$ is dimensionally correct.

Solution: LHS: $[v^2] = [LT^{-1}]^2 = [L^2T^{-2}]$

RHS:

  • $[u^2] = [L^2T^{-2}]$
  • $[2as] = [LT^{-2}][L] = [L^2T^{-2}]$

Both terms on RHS have [L²T⁻²], and LHS = RHS.

Answer: ✓ Dimensionally correct!

Problem 4

Find the dimensions of a/b in the equation P = (a - t²)/bx, where P = pressure, t = time, x = distance.

Solution:

$$P = \frac{a - t^2}{bx}$$

Since (a - t²) must have same dimensions as t²:

$$[a] = [t^2] = [T^2]$$

From dimensional homogeneity:

$$[P] = \frac{[a]}{[b][x]} = \frac{[T^2]}{[b][L]}$$ $$[ML^{-1}T^{-2}] = \frac{[T^2]}{[b][L]}$$ $$[b] = \frac{[T^2]}{[ML^{-1}T^{-2}][L]} = \frac{[T^2]}{[MT^{-2}]} = [M^{-1}T^4]$$ $$\frac{[a]}{[b]} = \frac{[T^2]}{[M^{-1}T^4]} = \boxed{[MT^{-2}]}$$

This is the dimension of surface tension or spring constant!

Level 3: JEE Advanced

Problem 5

The velocity v of water waves depends on wavelength λ, density ρ, and acceleration due to gravity g. Find the relation between them using dimensional analysis.

Solution: Let $v = k\lambda^a \rho^b g^c$ (k is dimensionless)

Dimensions:

  • [v] = [LT⁻¹]
  • [λ] = [L]
  • [ρ] = [ML⁻³]
  • [g] = [LT⁻²]
$$[LT^{-1}] = [L]^a [ML^{-3}]^b [LT^{-2}]^c$$ $$[LT^{-1}] = [M^b L^{a-3b+c} T^{-2c}]$$

Comparing powers:

  • For M: 0 = b → b = 0
  • For T: -1 = -2c → c = 1/2
  • For L: 1 = a - 3b + c = a + 1/2 → a = 1/2
$$\boxed{v = k\sqrt{\lambda g}}$$

(The actual formula is v = √(gλ/2π), where k = 1/√(2π))

Quick Reference

Dimensional FormulaPhysical Quantities
[L]Length, wavelength, amplitude
[T]Time, time period, half-life
[LT⁻¹]Velocity, wave velocity
[LT⁻²]Acceleration, gravity
[MLT⁻¹]Momentum, impulse
[MLT⁻²]Force, weight, thrust
[ML²T⁻²]Work, energy, torque
[ML²T⁻³]Power
[ML⁻¹T⁻²]Pressure, stress
[ML⁻³]Density
[MT⁻²]Surface tension, spring constant
[ML⁻¹T⁻¹]Viscosity
[T⁻¹]Frequency, angular velocity, decay constant

Within Units and Measurements

Connected Chapters